Light Reflection and Refraction Test

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Light Reflection and Refraction Test - 48

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Weekly Quiz Competition

Question 1
1 / -0

Fill in the blanks
The ray of light bending away from normal is called _____.

A
Refracted ray

B
Incident ray

C
Emergent ray

D
None of the above

Solution

A ray of light bending away from normal is called the refracted ray.
When light rays move from one medium to another medium then Light Rays deviate towards or away from normal. Deviated rays is called refracted ray.
Question 2
1 / -0

When light moving in one medium falls at the surface of another medium, _______ light returns back to the same medium.

A
all of

B
a part of

C
no

D
either all or no

Solution

Light moving in one medium when falls at the surface of another medium, part of light returns to the same medium. Some part is transmitted and the rest is absorbed. No material is a perfect reflector. Almost all surfaces absorb some part of light.
Question 3
1 / -0

Refraction occurs due to:

A
Change in direction of light

B
Change in speed of light

C
Change in quality of light

D
All

Solution

Refraction occurs due to change in optical properties of the light which causes change in direction and speed of light.

The light bends towards the normal or away from the normal if the refracting medium is denser or rarer respectively. The extent of bending is governed by Snell's law: $$\dfrac{n_i}{n_r}=\dfrac{sin \ \theta_r}{sin \ \theta_i}$$

The light slows down in a denser medium and becomes faster in a rarer medium.
Question 4
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Which of the states Snell's law?

A
Incident ray, refracted ray and the normal at the point of incidence all lies in the same plane

B
$$\dfrac {sin i}{sin r} =$$ constant (for a given media)

C
Angle of incidence $$=$$ Angle of refraction

D
All

Solution

The ratio of sine of angle of incidence to the sine of angle of refraction is a constant, for the light of a given colour and for the given pair of media. This law is also known as Snell’s law of refraction.
If i is the angle of incidence and r is the angle of refraction, then,
$$\dfrac {\sin i}{\sin r} =$$ constant (for a given media)
This constant value is called the refractive index of the second medium with respect to the first.
Question 5
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Which phenomena of light makes a pool of water appears to be less deep than it actually is?

A
Reflecion

B
Refraction

C
Diffraction

D
Lateral inversion

Solution

The rays of light coming from the bottom of the swimming pool travel from water to air. As the rays pass from denser medium (water) to rarer medium (air), they bend away from the normal. When the rays are produced back, they form an image of the bottom of the pool at a point above the real position. Therefore, the swimming pool appears to be less deep that it actually is.
This phenomenon takes place due to the refraction of light at the interface of the two media.

Hence, the correct answer is OPTION B.
Question 6
1 / -0

Fill in the blanks:
A spherical mirror whose reflecting surface is curved outwards is called _________.

A
concave mirror

B
convex mirror

C
plane mirror

D
biconvex mirror

Solution

The reflecting surface of a spherical mirror may be curved inwards or outwards.
A spherical mirror whose reflecting surface is curved inwards is called as a concave mirror whereas a spherical mirror whose reflecting surface is curved outwards is called as a convex mirror.
Question 7
1 / -0

Magnification for erect and inverted image is:

A
$$+ve$$ and $$-ve$$ respectively

B
$$-ve$$ and $$+ve$$ respectively

C
$$+ve$$

D
$$-ve$$
Solution
Magnification is the ratio of height of image and object.
$$m = \dfrac{h_i}{h_o}$$
And by convention, height of image formed below principal axis is taken negative and above is taken positive.

Hence,
for erect image, $$m=+ve$$
for inverted image $$m=-ve$$.

Answer is option (A).
Question 8
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Refractive index of diamond with respect to glass is $$1.6$$ and absolute refractive index of glass is $$1.5$$. Find out the absolute refractive index of diamond.

A
$$1.06$$

B
$$0.93$$

C
$$2.4$$

D
$$0.75$$

Solution

Given,

Refractive index of diamond with respect to glass, $${ _{ g }{ n }_{ d } } = 1.6$$,

Absolute refractive index of glass, $$n_{g} = 1.5$$

Refractive index of diamond with respect to glass $$= \dfrac {\text {Absolute refractive index of diamond}}{\text {Absolute refractive index of glass}}$$

Therefore, absolute refractive index of diamond $$=$$ Refractive index of diamond with respect to glass $$\times$$ Absolute refractive index of glass $$= 1.6 \times 1.5 = 2.4$$
Question 9
1 / -0

Which of the following comes under laws of refraction?

A
Angle of incidence is equal to angle refraction

B
Angle of refraction is greater than angle of incidence

C
Value of $$\dfrac {sin\ i}{sin\ r}$$ is known as refractive index of the medium

D
All

Solution

The laws of refraction are as follows:

1. According to the first law of refraction, the incident ray, the refracted ray and the normal to the point of incidence, all lie in the same plane.

2. According to the second law of refraction, also, known as the Snell's law, the ratio of sine of the angle of incidence to the sine of angle of refraction is a constant for a given pair of media.
$$ \Rightarrow \dfrac{Sin\ i}{Sin\ r} = Constant $$

This constant is known as the refractive index.

Hence, the correct answer is option C.
Question 10
1 / -0

............... lens is known as diverging lens.

A
Convex

B
Concave

C
Sperical

D
Plano convex

Solution

Concave lens are known as diverging lens as they diverge parallel beam of light falling on it.

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Re-Attempt Weekly Quiz Competition

Light Reflection and Refraction Test - 48

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Light Reflection and Refraction Test - 48

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SHARING IS CARING

Question 1

Refracted ray

Incident ray

Emergent ray

None of the above

Solution

Question 2

all of

a part of

no

either all or no

Solution

Question 3

Change in direction of light

Change in speed of light

Change in quality of light

All

Solution

Question 4

Incident ray, refracted ray and the normal at the point of incidence all lies in the same plane

$$\dfrac {sin i}{sin r} =$$ constant (for a given media)

Angle of incidence $$=$$ Angle of refraction

All

Solution

Question 5

Reflecion

Refraction

Diffraction

Lateral inversion

Solution

Question 6

concave mirror

convex mirror

plane mirror

biconvex mirror

Solution

Question 7

$$+ve$$ and $$-ve$$ respectively

$$-ve$$ and $$+ve$$ respectively

$$+ve$$

$$-ve$$

Solution

Question 8

$$1.06$$

$$0.93$$

$$2.4$$

$$0.75$$

Solution

Question 9

Angle of incidence is equal to angle refraction

Angle of refraction is greater than angle of incidence

Value of $$\dfrac {sin\ i}{sin\ r}$$ is known as refractive index of the medium

All

Solution

Question 10

Convex

Concave

Sperical

Plano convex

Solution

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