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Light Reflection and Refraction Test - 67

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Light Reflection and Refraction Test - 67
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  • Question 1
    1 / -0
    A point object is placed at a distance of $$10\ cm$$ and is real image is formed at a distance of $$20\ cm$$ from a concave mirror. If the object is moved by $$0.1\ cm$$ toward the mirror, the image will shift by about 
    Solution
    Mirror formula 
    $$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}\Rightarrow \dfrac{1}{f}=\dfrac{1}{-20}+\dfrac{1}{(-10)}\Rightarrow f=\dfrac{20}{3}\ cm.$$ If object moves towards the mirror by $$0.1\ cm$$ then.
    $$(10-0.1)=9.9\ cm.$$ Hence again from mirror formula $$\dfrac{1}{-20/3}=\dfrac{1}{v'}+\dfrac{1}{-9.9}\Rightarrow v'=20.4\ cm$$ i.e. image shifts away from the mirror by $$0.4\ cm.$$
  • Question 2
    1 / -0
    Velocity of light in a medium is $$1.5\times 10^8 m/s$$. Its refractive index will be
    Solution
    $$c$$=$$3 \times 10 ^{8} m/s^{-1}$$........Speed of light in vaccum
    $$v$$=$$1.5 \times 10 ^{8} m/s^{-1}$$........Speed of light in medium
    $$\mu =\dfrac {c}{v}=\dfrac {3\times 10^8}{1.5\times 10^8}=2$$
  • Question 3
    1 / -0
    If the speed of light in vacuum is $$C\ \ m/sec$$, then the velocity of light in a medium of refractive index $$1.5$$ is
    Solution
    Spped of light in vacuum $$=C$$ m/s
    Refrective index of medium $$\mu=1.5$$
    Velocity of light in any medium having refrective index $$\mu$$,  $$v=\dfrac C\mu$$
    On putting the value of $$\mu$$,   $$v=\dfrac C{1.5}$$

    Option D.
  • Question 4
    1 / -0
    On a glass plate a light wave is incident at an angle of $$60^o$$. If the reflected and the refracted waves are mutually perpendicular, the refractive index of material is
    Solution
    From figure
    $$ < i=60^o, < r=30^o$$
    so $$\mu =\dfrac {\sin 60}{\sin 30}=\sqrt 3$$

  • Question 5
    1 / -0
    Refractive index of glass is $$\dfrac {3}{2}$$ and refractive index of water is $$\dfrac {4}{3}$$. If the speed of light in glass is $$2.00\times 10^8\ m/s$$ , the speed in water will be
    Solution
    As we know,
    $$\mu=\dfrac{c}{v}$$
    $$\mu\propto \dfrac {1}{v}$$   where $$\mu$$
     is refractive index of medium , $$c$$ speed of light in vaccum and $$v$$ is speed of light in medium $$\Rightarrow \dfrac {\mu_g}{\mu_w}=\dfrac {v_w}{v_g}\Rightarrow \dfrac {3/2}{4/3}=\dfrac {v_w}{2\times 10^8}$$
    $$\Rightarrow v_w =2.25\times 10^8 m/s$$
  • Question 6
    1 / -0
    A convex lens
    Solution
    A convex lens converges ray of light coming from an object to form a real and inverted image provided object is not located in front of Focal Length($$F$$) of the lens. If object is located in front of $$F$$ then image formed is virtual and magnified.

    Hence, only option A is correct.

  • Question 7
    1 / -0
    When a ray of light passes through the second optical medium with a change in the angle, the phenomenon is known as:
    Solution
    The bending of rays of light after passing through one medium to another is known as refraction.
    A light ray traveling obliquely from a denser medium to a rarer medium bends away from the normal. A light ray bends towards the normal when it travels obliquely from a rarer to a denser medium.
  • Question 8
    1 / -0
    Which of the following event is not related to refraction of light ?
    Solution

  • Question 9
    1 / -0
    Which of the following materials has maximum optical density?
    Solution
    Diamond
    Diamond has the highest refractive index of $$2.42$$. The larger the refractive index of a medium, the greater is its optical density.
  • Question 10
    1 / -0
    The magnification of plane mirror is always ...............
    Solution
    1
    Since the size of the image formed by a plane mirror is equal to the size of the object, its magnification is always 1.
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