Human Eye and C...

Why are red coloured lights are used in traffic signals to stop the vehicles?

A professor reads a greeting card on his $$50th$$ birthday with $$+2.5D$$ glasses keeping the card $$25\ cm$$ away. $$10$$ years later he reads the greeting card with the same glasses keeping the card $$50\ cm$$ away. What power should he wear now?

The image formed by the eye lens on the retina is :

Identify the wrong description of the given figures.

In the absence of atmosphere, the sky appears :

The muscles of a normal eye are least strained when the eye is focused on an object:

The ciliary muscles of eye control the curvature of the lens in the eye and hence and alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained, the curvature of lens increases. That means, radius of curvature decreases and focal length decreases. For a clear vision, the image must be on the retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye lens. It is about $$25\ cm$$ for a grown up person.
A person can theoretically have clear vision of an object situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown up person, minimum distance of the object should be around $$25\ cm$$.
A person suffering from eye defects uses spectacles (eye glass). The function of lens of spectacles is to form the image of the objects within the range in which the person can see clearly. The image of the spectacle lens becomes object for the eye lens and whose image is formed on the retina.
The number of spectacle lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle lens is equal to the numerical value of the power of lens with sign. For example, if power of the lens required is $$+3D$$ (converging lens of focal length $$100/3\ cm$$), then number of lens will be $$+3$$.
For all the calculations required, you can used the lens formula and lensmaker's formula. Assume that the eye lens is equiconvex lens. Neglect the distance between the eye lens and the spectacle lens.
A near sighted man can clearly see objects only upto a distance of $$100 cm$$ and not beyond this. The number of the spectacle lenses necessary for the remedy of this defect will be

When the refraction takes place through a glass prism the emergent ray always bends towards the .......... of prism.

A normal eye is not able to see objects closer than 25 cm because:

Hypermetropia is