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Human Eye and Colourful World Test - 53

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Human Eye and Colourful World Test - 53
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  • Question 1
    1 / -0
    An old person is able to see an object nearest to 1 m.What should be the power of lens required so that he can see an object placed at nearest distance of distinct vision?
    Solution

    Hypermetropia is a condition of the eye where the person is not able to see things clearly when nearer to the eye.

    The normal near point of the eye is =$$25cm$$

    For corrective lens to be used ,

    Focal length,= $$f$$

    For corrective lens object distance =The normal near point of the eye   = $$u=-25cm$$ and image distance = defected near point of man = $$ v=-100cm$$

    Lens formula:

    $$ \dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u} $$

    $$ \dfrac{1}{f}=\dfrac{1}{-100}-\dfrac{1}{-25}=\dfrac{1}{25}-\dfrac{1}{100}=\dfrac{3}{100} $$

    $$ f=33.33\,cm=0.33\,m $$

    Power, $$P=\dfrac{1}{f}=\,\dfrac{1}{0.333}=3D$$

    Hence, Power of lens is $$3D$$

  • Question 2
    1 / -0
    In the figure below for no dispersion to take place, light rays must enter from _____ and emerge from _____.

    Solution
    The light ray must enter from $$A2B2$$ and emerge from $$P2Q2$$
  • Question 3
    1 / -0
    A person cannot see distant objects clearly. his vision can be corrected by using the spectacle containing :
    Solution
    Concave lenses spread the light out before it reaches the convex lens in the eye, therefore letting the image focus directly on the retina and thereby correcting myopia.
  • Question 4
    1 / -0
    Rainbow is observed when the Sun is 
    Solution
    The sun is always behind the observer. This is because the rainbow is actually just sunlight which has been refracted and reflected.
  • Question 5
    1 / -0
    A person can see clearly objects only when they lie between $$50$$cm and $$400$$cm from his eyes. In order to increase the maximum distance of distinct vision to infinity, the type and power of the correcting lens, the person has to use, will be?
    Solution
    Maximum distance of distinct vision $$=400$$cm. So image of object at infinity is to be formed at $$400$$cm

    Use lens formula, $$\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}$$

    $$\dfrac{1}{-400}-\dfrac{1}{\infty}=\dfrac{1}{f}$$

    $$P=-0.25$$D.
  • Question 6
    1 / -0
    A young man has to hold a book at arm's length to be able to read it clearly. The defect of vision is: 
    Solution
    Hypermetropia (long-sightedness) is a common eye condition where nearby objects appear blurred, but your vision is clearer when looking at things further away.
  • Question 7
    1 / -0
    Though a woman can see the distant objects clearly, she cannot see the nearby object clearly. She is suffering from the defect called :
    Solution
    Long-sightedness is a common eye condition where nearby objects appear blurred, but your vision is clearer when looking at things further away.
  • Question 8
    1 / -0
    What is the common phenomena of light between random wavering of flickering of objects seen through a turbulent stream of hot air, advance sunrise and delayed sunset and twinkling of stars?
    Solution
    Atmospheric refraction is responsible for advanced sunrise, delayed sunset and twinkling of stars. 
  • Question 9
    1 / -0
    A person can not see the distant objects clearly (though he can see the nearby object clearly). He is suffering from the defect of vision called:
    Solution
    Myopia is a vision condition in which people can see close objects clearly, but objects farther away appear blurred.
  • Question 10
    1 / -0
    The near point and the far point of a child are at 10 and 100 cm. If the retina is 2.0 cm behind the eyelens  .What is the range of the power of the eye lens?
    Solution

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