Self Studies

Electricity Test - 15

Result Self Studies

Electricity Test - 15
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

    Match the following with the correct response:

     (1) Electric current  (A) The current flowing through conductor is directly proportional
    to the potential difference applied across the ends of conductor.
     (2) Electric Potential  (B) Amount of charge flowing through an area in unit second.
     (3) Resistance  (C) Rate at which energy is consumed.
     (4) Power  (D) Work done in moving a unit charge from infinity to that point.
    Solution

    Electric current (I) is the amount of charge (Q) flowing through an area of cross-section in unit second. Electric Potential at a point is the work done in moving a unit charge from infinity to that point. Resistance (R) is a property that resists the flow of current in a circuit. According to Ohm's law. the current (I) flowing through conductor is directly proportional to the potential difference (V) applied across the ends of the conductor. Power (P) is the rate at which electric energy is lost (dissipated) or consumed in an electrical device due to resistance (R).

     (1) Electric current  (B) Amount of charge flowing through an area in unit second.
     (2) Electric Potential  (D) Work done in moving a unit charge from infinity to that point.
     (3) Resistance  (A) The current flowing through conductor is directly proportional to the potential difference applied across the ends of conductor.
     (4) Power  (C) Rate at which energy is consumed.
  • Question 2
    1 / -0

    Match the following with correct response:

     (1) Current divides at a junction  (A) Fuse
     (2) Two or more cells connected together  (B) Battery
     (3) Current is the same at all points  (C) Parallel circuit
     (4) They protect electrical appliances from high voltage  (D) Series circuit
    Solution

    A Battery maintains potential difference between two points in an electric circuit. It is made up of two or more cells connected together. In a series combination of resistors, the same current flows through each resistor. The current is the same in every part of the circuit. In a parallel combination of resistors, the current divides at a junction. A Fuse protects electrical appliances from high voltage. It is a safety device consisting of a strip of wire that melts and breaks an electric circuit if the current exceeds a safe level.

     (1) Current divides at a junction  (C) Parallel circuit
     (2) Two or more cells connected together  (B) Battery
     (3) Current is the same at all points  (D) Series circuit
     (4) They protect electrical appliances from high voltage  (A) Fuse
  • Question 3
    1 / -0

    Match the following with the correct response:

     (1) Electric current  (A) Ammeter
     (2) Small deflection in the circuit  (B) Battery
     (3) Maintains potential difference between two points  (C) Galvanometer
     (4) Variable Resistance  (D) Rheostat
    Solution

    An Ammeter (from Ampere Meter) is used to measure electric current (flow of electric charge) in an electric circuit. A Galvanometer is an electromechanical instrument for detecting and measuring small electric currents. A Battery maintains potential difference between two points in an electric circuit. A Rheostat is an electrical instrument used to control current in a circuit by varying the resistance.

     (1) Electric current  (A) Ammeter
     (2) Small deflection in the circuit  (C) Galvanometer
     (3) Maintains potential difference between two points  (B) Battery
     (4) Variable Resistance  (D) Rheostat
  • Question 4
    1 / -0

     

    The rate of electric energy loss in a thermal device due to resistance R is given by:
    A. P = I2/R
    B. P = V2/R
    C. P = I2/V
    D. P = V/I

    Solution

    The rate at which electric energy is lost (dissipated) or consumed in a thermal device due to resistance R is given by P = VI or P = I2R = V2/R

  • Question 5
    1 / -0

    Three bulbs of 100 W, 200 W and 60 W are connected in series to the main supply of 220 V. The current will be:
    A. Equal in 100 W and 200 W.
    B. Equal in 200 W and 60 W.
    C. Different in all bulbs.
    D. None of the above

    Solution

    The current will be same in all the bulbs. In a series combination of resistors, the same current flows through each resistor. The current is the same in every part of the circuit.

  • Question 6
    1 / -0

    Manganin is an alloy of:
    A. Copper
    B. Manganese
    C. Nickel
    D. Platinum

    Solution

    Manganin is an alloy of copper, manganese and nickel. It typically contains 86% copper, 12% manganese, and 2% nickel. It was first developed by Edward Weston in 1892 improving upon his Constantan. Manganin wire is used in the manufacture of resistors.

  • Question 7
    1 / -0

    Which of the following statements is/are incorrect?
    A. A neutron has a positive charge of + 1.6 × 10−19 C
    B. An ammeter is a low resistance device.
    C. Resistance of semiconductors decreases with temperature.
    D. One ampere is equal to 10−6 uA.

    Solution

    b

  • Question 8
    1 / -0

    Which of the following statements are correct about resistance?
    A. Resistance of a conductor is directly proportional to the length.
    B. Resistance of a conductor is directly proportional to the area of cross-section.
    C. Resistance of a conductor depends on the nature of the material.
    D. Resistance of conductor is inversely proportional to the length.

    Solution

    Resistance (R) of a conductor at a given temperature:

    • is directly proportional to the length (l)
    • is inversely proportional to the area of cross-section (a)
    • depends on the nature of the material (ρ)

    R = ρ × l / a

  • Question 9
    1 / -0

    Which of the following charges is possible?

    A. 1.6 × 10−19C

    B. 3.2 × 10−19C

    C. 6.4 × 10−19C

    D. 0.8 × 10−19C

    Solution

    Charges given in A, B and C are possible. 1.6 × 10−19C is the amount of charge on a proton or an electron. This is the minimum charge that any particle will have.

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now