Electricity Test

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Electricity Test - 27

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Weekly Quiz Competition

Question 1
1 / -0

________are substances which do not allow electricity to pass through them.

A
Insulators

B
Conductors

C
Semi-conductors

D
None of these

Solution

The substance which do not allow electricity to pass through them are called $$insulators$$.

Answer-(A)
Question 2
1 / -0

Find odd man out
Plastic, Rubber, Glass, Silver

A
Glass

B
Rubber

C
Silver

D
Plastic

Solution

All are bad conductors (insulator) of electricity, but silver is a good conductor.
Question 3
1 / -0

For a heater rated at $$4.4 \ kW \ , \ 220 \ V$$ . Calculate the current drawn by the heater.

A
$$40 \ A$$

B
$$20\ A$$

C
$$12.6 \ A$$

D
$$0 \ A$$

Solution

Given:
$$V =220$$ volts
$$P = 4.4 \ kW = 4400 \ W$$

Since, $$ P = VI$$
Current drawn by heater $$I =\dfrac{P}{V} = \dfrac{4400}{220} = 20 \ A$$
Question 4
1 / -0

For a heater rated at $$4 \ kW$$; $$220 \ V$$ . Calculate the resistance of the heater element.

A
$$20 \Omega$$

B
$$21.6\Omega$$

C
$$200\Omega$$

D
$$12.2\Omega$$

Solution

Given: $$V =220$$ volts $$P = 4000$$ W
Electric power is given by
$$P=\dfrac{V^2}{R}$$ where $$R$$ is resistance and $$V$$ is voltage.

$$\therefore$$ Resistance of the heater $$R = \dfrac{V^2}{P} =\dfrac{220^2}{4000} = 12.1\Omega$$
Question 5
1 / -0

When a current flows through a conductor its temperature

A
May increase or decrease

B
Remains same

C
Decreases

D
Increases

Solution

According to Joule's heating effect of current, heat energy is generated across a conductor due to the current flowing through it and hence its temperature increases.
Question 6
1 / -0

For a heater rated at 4.4 KW; 220 V, calculate the energy consumed by the heater in 4 hours?

A
12 KWh

B
17.6 KWh

C
0 KWh

D
4.4 KWh

Solution

Given : $$P = 4.4$$ KW, $$t = 4$$ h
$$\therefore$$ Energy consumed in 4 h
$$\Rightarrow E= P\times t =4.4\times 4 = 17.6$$ kWh
Question 7
1 / -0

The direction of current is taken as

A
The opposite to the direction of flow of current.

B
Opposite to the direction of flow of protons.

C
Opposite to the direction of flow of electrons.

D
All

Solution

Conventionally, the direction of current is taken as the direction of flow of positive charge (protons) and opposite to the direction of flow of negative charge (electrons).
Hence option C is correct.
Question 8
1 / -0

If a fuse is rated as 8 A, and current more than 8 A passes through it then

A
it would melt

B
circuit gets broken

C
both A and B

D
none

Solution

The maximum current which can flow through a fuse without melting it is called its rating. For example, a fuse rated at 8A can stand current up to 8 A. If current higher than 8 A flows through the fuse, it would melt, and the circuit gets broken. The rating of a fuse depends upon the thickness of the fuse wire (because the length of the wire is fixed). The thicker fuse has a higher rating. So, the thickness of the fuse wire in 8 A circuit is more than that of the fuse wire in 5 A circuit.
So, when the current higher than 8A passes the fuse melts and breaks the circuit which stops the flow of the current.
Therefore, answer is (C)
Question 9
1 / -0

Motion of charges is nothing but:

A
electric current

B
magnetic effect of current

C
heating effect of current

D
all of the above

Solution

Movement of charges is called current. The current always flow in the opposite direction of the movement of electrons.
Question 10
1 / -0

When 1 coulomb of charge flows through a conductor in 1 sec, then the current passing through the conductor is?

A
1Hp

B
1A

C
1C

D
1P

Solution

Given : $$q =1$$ C $$t = 1$$ s
$$\therefore$$ Current $$I = \dfrac{q}{t} = 1$$ s
Thus 1 Ampere is the current is defined as flow of 1 coulomb charge through a conductor in 1 second.

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Electricity Test - 27

Result

Electricity Test - 27

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Question 1

Insulators

Conductors

Semi-conductors

None of these

Solution

Question 2

Glass

Rubber

Silver

Plastic

Solution

Question 3

$$40 \ A$$

$$20\ A$$

$$12.6 \ A$$

$$0 \ A$$

Solution

Question 4

$$20 \Omega$$

$$21.6\Omega$$

$$200\Omega$$

$$12.2\Omega$$

Solution

Question 5

May increase or decrease

Remains same

Decreases

Increases

Solution

Question 6

12 KWh

17.6 KWh

0 KWh

4.4 KWh

Solution

Question 7

The opposite to the direction of flow of current.

Opposite to the direction of flow of protons.

Opposite to the direction of flow of electrons.

All

Solution

Question 8

it would melt

circuit gets broken

both A and B

none

Solution

Question 9

electric current

magnetic effect of current

heating effect of current

all of the above

Solution

Question 10

1Hp

1A

1C

1P

Solution

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