Electricity Test

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Electricity Test - 28

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Weekly Quiz Competition

Question 1
1 / -0

An electric bulb is rated $$750 \ W - 200 \ V$$. Calculate the magnitude of current.

A
$$200 \ A$$

B
$$3.75 \ A$$

C
$$15 \ A$$

D
$$2 \ A$$

Solution

Given, voltage $$V = 200 \ V$$ , Power $$ P = 750 \ W$$.

Using , $$P = Vi$$

$$i = \dfrac{P}{V} = \dfrac{750}{200} = 3.75 \ A$$

Hence, $$i = 3.75 \ A$$.
Question 2
1 / -0

Heating effect of current is due to

A
the flow of voltage through the conductor.

B
the flow of current through a conductor.

C
both A and B.

D
neither A nor B.

Solution

Whenever an electric current passes through a conductor, it gets heated up. The amount of heat produced is directly proportional to the square of the current ($$H\propto i^2$$).
Question 3
1 / -0

Calculate the current through a lamp of 25w operating at 220v.

A
2A

B
25A

C
0.114A

D
6A

Solution

Given : $$P = 25$$ W $$V= 220$$ volts
$$\therefore$$ Current through the lamp $$I = \dfrac{P}{V} = \dfrac{25}{220} = 0.114$$ A
Question 4
1 / -0

The equivalent resistance of resistors connected in series is always

A
Equal to the mean of component resistors

B
Less than the lowest of component resistors

C
in between the lowest and highest of component resistors

D
Equal to sum of component resistors

Solution

Equivalent resistance of series combination $$R_{eq} =R_1+R_2+R_3+.....$$
Thus equivalent resistance of the resistors connected in series is always equal to the sum of component resistors.
Question 5
1 / -0

An electric stove uses _________ resistances.

A
High

B
Low

C
Medium

D
None

Solution

According to Joule’s law of heating, heat produced in a resistor $$(H)$$ is
(i) directly proportional to the square of current $$(I)$$ for a given resistance
(ii) directly proportional to resistance $$(R)$$ for a given current, and
(iii) directly proportional to the time $$(t)$$ for which the current flows through the resistor
$$H=I^2Rt$$
An electric stove uses high resistance.
Question 6
1 / -0

A bulb uses 5000J of energy in 10s, calculate its power.

A
50 $$J/s$$

B
500 $$Watts$$

C
5 $$Watts$$

D
600 $$J/s$$

Solution

Given : $$E = 5000$$ J $$t = 10$$ s
Power of the bulb $$Power=\dfrac{Energy \quad spent}{Time}$$ $$P = \dfrac{E}{t} = \dfrac{5000}{10} = 500$$ $$Watts$$
Question 7
1 / -0

1mA =

A
$$1000A$$

B
$$\displaystyle { 10 }^{ -3 }A$$

C
$$\displaystyle { 1Cs }^{ -1 }$$

D
None

Solution

As milli scale is of the order of $$10^{-3}$$ units.
$$\therefore$$ Mathematically, 1 mA $$ = 10^{-3}$$ A
Question 8
1 / -0

The direction of current in a conductor is in the direction of flow of

A
Electrons

B
Atoms

C
Positive charges

D
None

Solution

Conventionally, the current flows in the direction of flow of positive charge or opposite to the flow of negative charge (electrons).
$$\text{Remember:}$$ In reality, positive charges in a conductor do not flow. It is free electrons that constitute a current.
Question 9
1 / -0

SI unit of electrical energy is

A
Joule

B
Kilowatt hour

C
KiloJoule

D
Watt hour

Solution

SI unit of electrical energy is Joule.
$$1 Joule = 1 Volt \times 1 ampere \times 1 second$$
Question 10
1 / -0

An electric bulb works on the principle of:

A
Archimedes

B
Heating effect of current

C
Magnetic effect of current

D
None of these

Solution

An electric bulb works on the principle of hearing effect of current. It consists of a tungsten filament with a coating of thorium. This filament gets heated up to emit light when current passes through it.

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Re-Attempt Weekly Quiz Competition

Electricity Test - 28

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Electricity Test - 28

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SHARING IS CARING

Question 1

$$200 \ A$$

$$3.75 \ A$$

$$15 \ A$$

$$2 \ A$$

Solution

Question 2

the flow of voltage through the conductor.

the flow of current through a conductor.

both A and B.

neither A nor B.

Solution

Question 3

2A

25A

0.114A

6A

Solution

Question 4

Equal to the mean of component resistors

Less than the lowest of component resistors

in between the lowest and highest of component resistors

Equal to sum of component resistors

Solution

Question 5

High

Low

Medium

None

Solution

Question 6

50 $$J/s$$

500 $$Watts$$

5 $$Watts$$

600 $$J/s$$

Solution

Question 7

$$1000A$$

$$\displaystyle { 10 }^{ -3 }A$$

$$\displaystyle { 1Cs }^{ -1 }$$

None

Solution

Question 8

Electrons

Atoms

Positive charges

None

Solution

Question 9

Joule

Kilowatt hour

KiloJoule

Watt hour

Solution

Question 10

Archimedes

Heating effect of current

Magnetic effect of current

None of these

Solution

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