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Electricity Test - 30

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Electricity Test - 30
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Identify the changes in a circuit on adding a light bulb in parallel to the actual resistance of the circuit. It will:
    Solution
    For the parallel combination of two resistances            

    $$\dfrac{1}{R_{eq}} =\dfrac{1}{R_1} +\dfrac{1}{R_2}$$

    $$\Rightarrow R_{eq}<  min {R_1, R_2}$$
    Light bulb has its own resistance and hence the total resistance of the circuit decreases when it is connected in parallel to the actual resistance of the circuit.
  • Question 2
    1 / -0
    Which of the following is an insulator?
    Solution
    Insulator is unable to transfer heat or electricity. Here the wood one of example of insulator because it is unable to transfer any heat or electricity.   
  • Question 3
    1 / -0
    Consider the direction of the current AND flow of electrons from the section $$A$$ to $$B$$ that goes through the resistor in the circuit pictured.

    Solution
        In the external circuit , the current flows from positive terminal to the negative terminal of the battery , therefore current in the given circuit will flow from A to B i.e.   downward .
       Now the direction of electron flow is given opposite to the  conventional current , therefore electron flow will be opposite to AB i.e. upward .
  • Question 4
    1 / -0
    Insulators
    Solution
    $$\textbf{Explanation}$$
    $$\bullet$$Insulators doesn’t have free electrons , so current doesn’t flow through them.
    $$\bullet$$ Hence they are not able to transfer electricity untill very high temperature is applied. Thus, insulators do not conduct electricity. 

    $$\textbf{ Hence option B correct}$$
  • Question 5
    1 / -0
    If three resistors 2 ohm, 3 ohm and 4 ohm are connected in series, then effective resistance in a circuit will be _______ ohm.
    Solution
    $$R_{eq}=R_1 + R_2 + R_3$$
             
            $$=2+3+4= 9 \Omega$$
  • Question 6
    1 / -0
    Your are given three equal resistances. In how many combinations can they be arranged?
    Solution
    Three equal resistances can be connected in four different combinations:
    1) All three in parallel.
    2) Two in parallel and third in series.
    3) Two in series and third in parallel of both.
    4) All three in series.

  • Question 7
    1 / -0
    Which of the following component is connected in parallel in the circuit?

    Solution
    Since the current in both bulbs is not same but they have same potential so they are connected in parallel.
    Therefore, C is correct statement.
  • Question 8
    1 / -0
    Which of the following is not a correct statement with respect to the given circuit?

  • Question 9
    1 / -0
    Taking the resistivity of platinoid as $$3.3 \times 10^{-7} \Omega m$$, find the resistance of $$7.0 m$$ of platinoid wire of average diameter $$0.14 cm$$. 
    Solution
    Let the platinoid wire of uniform cross-section has a resistance of $$R$$.
    Let the diameter be $$d$$.
    Let the length of the wire be $$l$$.
    According to question: 
    $$l=7\ m$$
    $$d=0.14\ cm$$ 
    Cross sectional Area be $$A$$:
    $$A=\pi\dfrac{d^2}{4}$$ = $$\pi \times\frac{{.0014}^2}{4}$$
    $$\therefore$$ $$A=15.4$$$$\times 10^-{^7} m^{2}$$

    Now the resistance of a wire can be expressed as:
    $$R=\rho\dfrac{l}{A}$$

    Where resistivity is $$\rho$$.

    $$\rho =3.3\times10^-{^7}$$ $$\Omega m$$

    Putting the values of $$l, A$$ and $$\rho$$ in Eq.1

    $$R=$$ $$\dfrac{3.3 \times{10}^{-7}}{15.4\times{10}^{-7}}$$ $$\times 7$$ $$=1.5$$ ohm
  • Question 10
    1 / -0
    Materials that allow electrons to flow through them are known as
    Solution
    Materials that allow electrons to flow through them are known as conductors. They consist of free electrons and hence allow the flow of charges through them. 
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