Acids Bases and Salts Test

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Acids Bases and Salts Test - 28

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Weekly Quiz Competition

Question 1
1 / -0

Chemical formula of gypsum is:

A
$$CaSO_4 . 2H_2O$$

B
$$CaSO_4 . \dfrac 12H_2O$$

C
$$CaSO_4 . H_2O$$

D
$$CaSO_4 $$

Solution

Calcium sulphate dihydrate is called gypsum with chemical formula, $$CaSO_4 .2H_2O$$. It's the main constituent of plaster of Paris.
Question 2
1 / -0

$$pH$$ scale ranges from:

A
$$7-14$$

B
$$0-12$$

C
$$0-14$$

D
$$0-7$$

Solution

$$pH$$ scale ranges from $$0-14$$. A value below $$7$$ indicates an acidic solution while a value above $$7$$ indicates basic nature. $$7$$ is the neutral point of the scale.
Question 3
1 / -0

A reaction of hydrated copper [II] sulphate is given:

$${ CuSO }_{ 4 }. { xH }_{ 2 }O$$ (blue\hydrous) $$\xrightarrow { { H }_{ 2 }{ SO }_{ 4 } }$$ $$y { CuSO }_{ 4 }$$ (white\anhydrous) $$+\ 5{ H }_{ 2 }O$$

Find $$x$$ and $$y$$.

A
$$ x = 5 , y = 1 $$

B
$$ x = 5 , y = 2 $$

C
$$ x = 2, y = 1 $$

D
$$ x = 2 , y = 2$$

Solution

Copper sulphate crystals contain water of crystallisation. When we heat the crystals, this water is removed and the salt turns white. Five water molecules are associated with one formula unit of copper sulphate. So, $$x = 5$$. When the water of crystallisation is removed, one molecule of copper sulphate is left behind. So, $$y = 1$$.

$${ CuSO }_{ 4 }\cdot { 5H }_{ 2 }O$$ (blue\hydrous) $$\xrightarrow { { H }_{ 2 }{ SO }_{ 4 } }$$ $${ CuSO }_{ 4 }$$ (white\anhydrous) $$+\ 5{ H }_{ 2 }O$$
Question 4
1 / -0

pH of any neutral solution is:

A
$$0$$

B
$$1$$

C
$$14$$

D
$$7$$

Solution

Correct Answer: Option D

Explanation
Pure water is a neutral solution.

In the pure water, the concentration of $$\left[ {{H}^{+}} \right]={{10}^{-7}}$$ and $$\left[ O{{H}^{-}} \right]={{10}^{-7}}$$ .

Now, the formula of calculating $${{P}^{H}}$$ is,

$${{P}^{H}}=-\log \left[ {{H}^{+}} \right]$$

$$\therefore$$ $${{P}^{H}}=-\log \left[ {{10}^{-7}} \right]$$

$$\therefore$$ $${{P}^{H}}=-\left( -7 \right)\log10$$, as ( $$\log {{x}^{a}}=a\log x$$ )
$$\therefore$$ $${{P}^{H}}=7$$, where $$\log 10=1$$.

Hence, the $${{P}^{H}}$$ of a solution which is neutral is $$7$$.
Question 5
1 / -0

NaOH is not used in :

A
paper industry

B
soap industry

C
rayon industry

D
plastic industry

Solution

Sodium hydroxide is used in several processes to make products including soaps, rayon, and textiles, revitalizing acids in petroleum refining, removal of paint, etc but it cannot be used in the plastic industry.
Question 6
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Which of the following compounds form salt with $$NaHCO_3$$?

A
$$NaOH$$

B
$$Na_2CO_3$$

C
$$CH_3COOH$$

D
All the above

Solution

$$NaHCO_3$$ is a base. It will react with carboxylic acid $$CH_3COOH$$ to form a salt.

$$NaHCO_3 + CH_3COOH$$ $$\rightarrow$$ $$H_2O + CO_2 + CH_3COOH$$

It will not react with bases such as $$NaOH $$ and $$Na_2CO_3$$.
Question 7
1 / -0

Calcium phosphate is present in tooth enamel, its nature is:

A
basic

B
acidic

C
neutral

D
none of the above

Solution

Calcium phosphate is present in tooth enamel and it is known as hydroxyapatite which is basic in nature. It is present in bones also. It is the hardest known material in the whole body. It is present on the outside part of the crown area in a tooth.

Hence, option A is correct.
Question 8
1 / -0

Which of the following is acidic in nature?

A
Lime juice

B
Human blood

C
Lime water

D
Antacid

Solution

Human blood, lime water and antacid(sodium bicarbonate) are alkaline in nature which have $$pH$$ greater than $$7$$ while lime juice which has $$pH$$ less than $$7$$ is acidic in nature.

Hence, the correct option is A.
Question 9
1 / -0

Solutions of sodium hydroixde and acetic acid are mixed:
Write the balanced chemical equation.

A
$$NaOH + CH_3COOH \rightarrow CH_3COONa + H_2O$$

B
$$NaOH_2 + CH_3COOH \rightarrow CH_3COONa + H_2O$$

C
$$2NaOH + CH_3COOH \rightarrow CH_3COONa + H_2O$$

D
$$NaOH + CH_3COOH \rightarrow 3CH_3COONa + H_2O$$

Solution

When the sodium hydroxide reacts with an acetic acid, the NaOH, a base, it generates sodium acetate, a salt, and $$H_2O$$.
$$CH_3COOH + NaOH \rightarrow CH_3COONa + H_2O$$
Acid-base reaction always results in the salt of the acid and base and water.
Option $$A$$ is correct.
Question 10
1 / -0

Metal carbonates react with dilute $$H_2SO_4$$ to produce:

A
carbonic acids

B
metallic oxides

C
weak metallic oxides

D
$$CO_2$$ gas

Solution

All metal carbonates react with acids to give a corresponding salt, carbon dioxide, and water.

Example-
$${ Na }_{ 2 }{ CO }_{ 3 }+{ H }_{ 2 }{ SO }_{ 4 }\rightarrow { Na }_{ 2 }{ SO }_{ 4 }+{ H }_{ 2 }O+{ CO }_{ 2 }$$

Thus, option $$D$$ is correct

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Re-Attempt Weekly Quiz Competition

Acids Bases and Salts Test - 28

Result

Acids Bases and Salts Test - 28

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SHARING IS CARING

Question 1

$$CaSO_4 . 2H_2O$$

$$CaSO_4 . \dfrac 12H_2O$$

$$CaSO_4 . H_2O$$

$$CaSO_4 $$

Solution

Question 2

$$7-14$$

$$0-12$$

$$0-14$$

$$0-7$$

Solution

Question 3

$$ x = 5 , y = 1 $$

$$ x = 5 , y = 2 $$

$$ x = 2, y = 1 $$

$$ x = 2 , y = 2$$

Solution

Question 4

$$0$$

$$1$$

$$14$$

$$7$$

Solution

Question 5

paper industry

soap industry

rayon industry

plastic industry

Solution

Question 6

$$NaOH$$

$$Na_2CO_3$$

$$CH_3COOH$$

All the above

Solution

Question 7

basic

acidic

neutral

none of the above

Solution

Question 8

Lime juice

Human blood

Lime water

Antacid

Solution

Question 9

$$NaOH + CH_3COOH \rightarrow CH_3COONa + H_2O$$

$$NaOH_2 + CH_3COOH \rightarrow CH_3COONa + H_2O$$

$$2NaOH + CH_3COOH \rightarrow CH_3COONa + H_2O$$

$$NaOH + CH_3COOH \rightarrow 3CH_3COONa + H_2O$$

Solution

Question 10

carbonic acids

metallic oxides

weak metallic oxides

$$CO_2$$ gas

Solution

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