Acids Bases and Salts Test

Result

Acids Bases and Salts Test - 31

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Weekly Quiz Competition

Question 1
1 / -0

Match the following

Column (A) Column (B)
(a) $$NaHCO_3$$ (i) Caustic soda
(b) $$Na_2CO_3.10H_2O$$ (ii) Baking soda
(c) $$NaOH$$ (iii) Blue vitriol
(d) $$CuSO_4\,. 5H_2O$$ (iv) Washing soda

A
a-(i), b-(ii), c-(iii), d-(iv)

B
a-(ii), b-(iv), c-(i), d-(iii)

C
a-(i), b-(iv), c-(ii), d-(iii)

D
a-(ii), b-(iv), c-(iii), d-(i)

Solution

$$NaHCO_3\longrightarrow$$ Baking soda (Sodium Bi-carbonate)
$$Na_2CO_3\cdot 10H_2O\longrightarrow$$ Washing soda (Sodium carbonate deca-hydrate)
$$NaOH\longrightarrow$$ Caustic soda (Sodium hydroxide)
$$CuSO_4\cdot 5H_2O\longrightarrow$$ Blue vitriol (Copper sulphate pentahydrate)
Hence, option $$B$$ is correct.
Question 2
1 / -0

_____ of acids are lower than that of bases.

A
$$log[H^+]$$

B
$$pOH$$

C
$$[H^+]$$

D
$$pH$$

Solution

$$pH$$ of acids are lower than that of bases.

Anything $$pH <7$$ is acidic, and anything $$pH>7$$ is alkaline or basic.

$$pH$$ scale range from $$0$$ to $$14$$.

Hence, option D is correct.
Question 3
1 / -0

When zinc reacts with dilute $$NaOH,$$ the products formed are:

A
$$H_2+Zn(OH)_2+Na$$

B
$$H_2+ZnO+Na$$

C
$$H_2+Na_2ZnO_2$$

D
$$NaOH+H_2+ZnO$$

Solution

Metals react with bases to form a salt and release hydrogen gas.

Zinc reacts with dilute $$NaOH$$ as follows:

$$Zn$$ + $$2NaOH\rightarrow$$ $$H_2$$ + $$Na_2ZnO_2$$

Hence, option C is correct.
Question 4
1 / -0

Raw materials used in the manufacture of bleaching powder are :

A
lime stone and chlorine

B
quick lime and chlorine

C
dry slaked lime and $$HCl$$

D
dry slaked lime and chlorine

Solution

Chlorine is produced during the electrolysis of aqueous sodium chloride (brine). This chlorine gas is used for the manufacture of bleaching powder. Bleaching powder is produced by the action of chlorine on dry slaked lime [$$Ca(OH)_2$$].
The reaction involved is:-

$$Ca(OH)_2+ Cl_2 → CaOCl_2 + H_2O$$

Thus, option $$D$$ is correct.
Question 5
1 / -0

The pH of a compound is found to be $$9$$. The compound can be:

A
$$HCl$$

B
$$NH_4Cl$$

C
$$Na_2CO_3$$

D
$$CH_3COOH$$

Solution

$$pH$$ above $$7$$ confirms the compound to be alkaline in nature $$HCl$$ and $$CH_3COOH$$ are acidic in nature.
Ammonium Chloride, $$NH_4Cl$$, is an acidic salt as $$NH_4^+$$ comes from a weak base and $$Cl^-$$ comes from a strong acid and its pH is bound to be below 7.
Sodium carbonate, $$Na_2CO_3$$, is a basic salt as $$Na^+$$ ions from a strong base and $$CO_3 ^ 2-$$ ions come from a weak acid. Being a basic salt, it's pH is bound to be more than 7.
Question 6
1 / -0

Study the table carefully. Which of the above are correctly matched?

A
(i) & (iii)

B
(ii) & (iv)

C
(i), (ii) & (iii)

D
(i), (iii) & (iv)

Solution

Tamarind juice is acidic in nature so it turns blue litmus red while lime water is alkaline in nature so it turns red litmus blue.
Question 7
1 / -0

A bottle of fire extinguishers contain $$H_2SO_4$$ and __________.

A
$$CaCO_3$$

B
$$MgCO_3$$

C
$$NaHCO_3$$

D
Any carbonate

Solution

Sodium carbonate was the first of the dry chemical agents. In the heat of a fire it releases a cloud of carbon dioxide that smothers the fire. The gas drives the the oxygen away from the fire thus stopping the chemical reaction.
Question 8
1 / -0

Most of the metals combine with acids:

A
to produce carbon dioxide gas

B
to form a base

C
to liberate hydrogen gas by displacing hydrogen from the acids

D
to form acidic salt

Solution

Metals on the top of the reactivity series react easily with mineral acids to evolve hydrogen gas, e.g., sodium, magnesium, calcium, etc.
Question 9
1 / -0

The constituent present in baking powder is:

A
Sodium benzoate

B
Acetic acid

C
Sodium lactate

D
Tartaric acid

Solution

The constituent present in baking powder is tartaric acid.

Baking powder contains basic sodium hydrogen carbonate which is neutralized with tartaric acid.
Question 10
1 / -0

Chlorine, used for manufacturing bleaching powder, is obtained by

A
Electrolysis of Brine

B
Reaction of air on dry slaked lime

C
Reaction of $$NaCl$$ with moist air

D
Decomposition of Calcium Hydroxide

Solution

When electricity is passed through an aqueous solution of sodium
chloride (called brine), it decomposes to form sodium hydroxide. The
process is called the 'chlor-alkali' process because of the products formed– 'chlor' for chlorine and 'alkali' for sodium hydroxide.
The reaction involved in the process is:

$$2NaCl(aq) + 2H_2O(l) → 2NaOH(aq) + Cl_2(g) + H_2(g)$$

Thus, Option $$A$$ is correct.

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Re-Attempt Weekly Quiz Competition

	Column (A)		Column (B)
(a)	$$NaHCO_3$$	(i)	Caustic soda
(b)	$$Na_2CO_3.10H_2O$$	(ii)	Baking soda
(c)	$$NaOH$$	(iii)	Blue vitriol
(d)	$$CuSO_4\,. 5H_2O$$	(iv)	Washing soda

Acids Bases and Salts Test - 31

Result

Acids Bases and Salts Test - 31

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Question 1

a-(i), b-(ii), c-(iii), d-(iv)

a-(ii), b-(iv), c-(i), d-(iii)

a-(i), b-(iv), c-(ii), d-(iii)

a-(ii), b-(iv), c-(iii), d-(i)

Solution

Question 2

$$log[H^+]$$

$$pOH$$

$$[H^+]$$

$$pH$$

Solution

Question 3

$$H_2+Zn(OH)_2+Na$$

$$H_2+ZnO+Na$$

$$H_2+Na_2ZnO_2$$

$$NaOH+H_2+ZnO$$

Solution

Question 4

lime stone and chlorine

quick lime and chlorine

dry slaked lime and $$HCl$$

dry slaked lime and chlorine

Solution

Question 5

$$HCl$$

$$NH_4Cl$$

$$Na_2CO_3$$

$$CH_3COOH$$

Solution

Question 6

(i) & (iii)

(ii) & (iv)

(i), (ii) & (iii)

(i), (iii) & (iv)

Solution

Question 7

$$CaCO_3$$

$$MgCO_3$$

$$NaHCO_3$$

Any carbonate

Solution

Question 8

to produce carbon dioxide gas

to form a base

to liberate hydrogen gas by displacing hydrogen from the acids

to form acidic salt

Solution

Question 9

Sodium benzoate

Acetic acid

Sodium lactate

Tartaric acid

Solution

Question 10

Electrolysis of Brine

Reaction of air on dry slaked lime

Reaction of $$NaCl$$ with moist air

Decomposition of Calcium Hydroxide

Solution

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