Carbon and its Compounds Test

Result

Carbon and its Compounds Test - 19

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following compounds will fall in the same homologous series of formic acid $$(H-COOH)$$?

A
$$CH_3COOH$$

B
$$CH_3COCH_3$$

C
$$CH_3CHO$$

D
None of the above

Solution

The given formula is the starting member of the carboxylic acid series.

The formulae for the members of homologous series of carboxylic acid which begins with $$\displaystyle HCOOH $$ are:

$$\displaystyle HCOOH, CH_3COOH, CH_3CH_2COOH, CH_3CH_2CH_2COOH, CH_3CH_2CH_2CH_2COOH $$ and so on.

Hence, the correct option is A.
Question 2
1 / -0

What change will you observe if you test soap with litmus paper (red and blue)?

A
It will turn red litmus blue

B
It will turn blue to red

C
Red litmus paper won't change colour

D
None of these

Solution

Since, soaps are basic in nature, thus, it turns red litmus paper to blue. When blue litmus paper is dipped in soap solution, it remains blue.

Option A is correct.
Question 3
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What are the two properties of carbon which led to the huge number of carbon compounds we see around us?

A
(i) Catenation (ii) Tetravalency

B
(i) Catenation (ii) Trivalency

C
(i) Catenation (ii) Pentavalency

D
(i) Covalency (ii) Divalency

Solution

Carbon can form huge number of carbon compounds due to following properties:
Catenation is a self linkage property, present in carbon. Because of catenation, carbon can form long chains, branched chains and closed chains.
Tetravalency: It is the state of an atom with four electrons available for covalent chemical bonding in its valence shell.
Question 4
1 / -0

Draw the electron dot structure for oxygen molecule.

A

B

C

D

Solution

Option $$B$$ shows the lewis structure of $$O_2$$ molecule.
Question 5
1 / -0

Test that can be used to differentiate between butter and cooking oil is :

A
Hydrogenation reaction

B
Substitution reaction

C
Oxidation reaction

D
Double displacement reactions

Solution

Cooking oil is an unsaturated hydrocarbon which can undergo addition of hydrogen to form saturated hydrocarbon, e.g., alkene to alkane while this hydrogenation addition reaction is not possible for butter or ghee as butter and ghee are saturated hydrocarbons.
$${ C }_{ 2 }{ H }_{ 4 }+{ H }_{ 2 } \rightarrow { C }_{ 2 }{ H }_{ 6 }$$
Question 6
1 / -0

Which out of the following has smell similar to that of vinegar?

A
Methanol

B
Ethanol

C
Ethanoic acid

D
Formic acid

Solution

Vinegar is a liquid having acetic acid and water as its mixture. So, ethanoic acid is the other name of acetic acid and this smell of vinegar is similar to ethanoic acid.
Question 7
1 / -0

Vinegar is a:

A
5-8% solution of acetic acid in water

B
25-30% solution of acetic acid in water

C
40-45% solution of acetic acid in water

D
45-50% solution of acetic acid in water

Solution

Vinegar is a liquid containing acetic acid and water. This acetic acid is produced by the fermentation of ethanol by acetic acid bacteria. It is mainly used as a cooking ingredient. It is a 5-8% solution of acetic acid in water and most easily available mild acid.
Question 8
1 / -0

Which of the following will give a pleasant smell of ester when heated with ethanol and a small quantity of sulphuric acid?

A
$$ CH_{2}CH_{2}OH $$

B
$$ CH_{3}OH $$

C
$$ CH_{3}COOH $$

D
$$ CH_{3}CHO $$

Solution

Acetic acid gives a pleasent smell on reaction with ethanol due to the formation of ethyl acetate as :
$$CH_{3}COOH + C_{2}H_{5}OH \rightarrow CH_{3}COOC_{2}H_{5} + H_{2}O$$
Question 9
1 / -0

$$ NaOH+{ C }{ H }_{ 3 }COOH\longrightarrow C{ H }_{ 3 }COONa+{ H }_{ 2 }O $$
This reaction is called :

A
oxidation reaction

B
hydrogention reaction

C
neutralisation reaction

D
addition reaction

Solution

Acid and Base reacts to form Salt and Water. This reaction is called neutralisation reaction. In this, acid is acetic acid and base is sodium hydroxide. Salt ($$CH_3COONa$$) is formed.
Question 10
1 / -0

$$ N{ a }_{ 2 }C{ O }_{ 3 }+2C{ H }_{ 3 }COOH\longrightarrow $$
Which gas is produced in this reaction?

A
$${ H }_{ 2 }O $$

B
$$CO_2$$

C
$$CO$$

D
$$H_2$$

Solution

$$ N{ a }_{ 2 }C{ O }_{ 3 }+2C{ H }_{ 3 }COOH\longrightarrow $$ $$2CH_3COONa$$ + $$CO_2$$ + $$H_2O$$
The above is an acid-base reaction, where $$CH_3COOH$$ is an acid and $$Na_2CO_3$$ is a base. In this reaction, $$CO_2$$ gas is evolved.
Therefore, the correct option is $$B$$