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Carbon and its Compounds Test - 27

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Carbon and its Compounds Test - 27
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  • Question 1
    1 / -0
    Which one of the following is not a property of carbon?
    Solution
    Carbon shows the property of catenation.

    It forms multiple bonds as there are 4 electrons in its valence shell.

    The boiling point and melting point of carbon are very high. 

    Carbon is a non-metal.

    Option D is correct.

  • Question 2
    1 / -0
    Identify the substance which is:
    (i) Used in making leads of pencils.
    (ii) Used as a dry lubricant.
    (iii) Used in making black paint and printers ink.
    (iv) Used in nuclear reactors as a moderator.
    Solution
    The substance with the following applications is Graphite. It is an allotrope of Carbon and is
    (I) used in making leads of pencils.
    (ii) used as a dry lubricant.
    (iii) used in making black paint and printers ink.
    (iv) used in nuclear reactors as a moderator.
    It is also used in making electrodes, carbon arcs and in the refractory crucible.
  • Question 3
    1 / -0
    Due to the weak Van der Waals' forces and less distance between the layers, graphite:
    Solution
    Because the layers are only weakly held together they can easily slip over one another. 
    Hence, graphite shows a lubricating property.
  • Question 4
    1 / -0
    In the Earth's crust, Carbon is found in the form of_________.
    Solution
    In the earth's crust carbon is found in rocks, petroleum and as carbonates. 
    Carbon is also present in the form of hydrocarbons which often use as sources of energy, such as coal, petrol and natural gas.
  • Question 5
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    Identify the unsaturated compounds from the following :
    $$(i)$$ Propane      $$(ii)$$ Propene      $$(iii)$$ Propyne      $$(iv)$$ Chloropropane
    Solution
    (i) Propane  $$CH_3-CH_2-CH_3$$
    (ii) Propene  $$CH_3-CH=CH_2$$
    (iii) Propyne   $$CH_3-C \equiv CH$$  
    (iv) Chloropropane   $$CH_3-CH(Cl)-CH_3$$

    Propene and propyne are unsaturated compound as they contain carbon-carbon multiple bonds.
  • Question 6
    1 / -0
    What is the name of the compound $$CH_3CH_2CH(CH_3)CH_2OH$$?
    Solution
    The name of the compound is 2-methyl butanol. 
    Since $$-OH$$ is the only functional group in this compound, we will start numbering from carbon nearest to the $$-OH$$ group. Then find the longest carbon chain that is 4 carbons means the word root is "but" and methyl is substituted at 2nd position. Hence, the name would be 2-methyl butanol.
  • Question 7
    1 / -0

     What is the name of the compound shown in the figure?

    Solution
    Longest chain consists of 4 carbon atoms. There are no functional groups attached. The name of the compound is butane.
  • Question 8
    1 / -0
    Which of the following are members of same homologous series?
    Solution
    $$\bf{Hint:}$$ It is a series of compounds with similar chemical properties and some functional groups differing by methylene group ($$-CH_2$$)

    $$\bf{Correct \ answer:}$$ Option $$A$$

    $$\bf{Explanation \ for \ correct \ option:}$$

    A homologous series is a family of hydrocarbons with similar chemical properties that share the same general formula. 
    Both given compound $$HCOOCH_{3}$$ and $$CH_{3}COOCH_{3}$$ are homologous series of a simple ester group $$RCOOH$$, where a successive methyl group $$-CH_{3}$$ added to previous one.

    $$\bf{Explanation \ for \ incorrect \ options:}$$

    • Compound $$CH_3COOH$$ is a second homologous compound for  $$HCOOH$$. It is not a successive member, therefore, it is not a member of the same homologous series.

    • In both compounds, $$CH_{3}COCH_{3}$$ and $$CH_{3}CH_{2}CHO$$ the functional group are different, hence it could not be homologous members.

    • In both compounds, $$C_{2}H_{5}OH$$ and $$CH_{3}OCH_{3}$$ the functional group are different, hence it could not be homologous members.
  • Question 9
    1 / -0
    Which general formula represents the homologous series of hydrocarbons that includes the compound 1-heptyne? 
    Solution
    1-heptyne is alkyne. The general formula for alkyne is $$C_nH_{2n-2}$$.
  • Question 10
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    Directions For Questions

    An organic compound $$X$$ is widely used as a preservative in pickles and has a molecular formula $$C_2H_4O_2$$. This compound reacts with ethanol to form a sweet smelling compound $$Y$$.

    ...view full instructions

    How can we get compound X back from Y? Name the process.
    Solution
    The molecular formula of a given organic compound is $$C_2H_4O_2$$ and it is also used as preservatives in pickles means it is acetic acid.
    When acetic acid$$(X)$$ reacts with ethanol it forms sweet-smelling compound ester$$(Y)$$.

    $$CH_3COOH + CH_3CH_2OH \rightarrow CH_3COOC_2H_5 + H_2O$$
          $$X$$              $$Ethanol$$                                   $$Y$$     

    To get back $$X$$(acetic acid) from $$Y$$(ester), $$Y$$ is treated with sodium hydroxide, then ester is converted back into ethanol, and sodium salt of carboxylic acid(acetic acid) is formed.

    $$CH_3COOC_2H_5+NaOH\rightarrow C_2H_5OH+CH_3COONa$$
    The process is known as saponification.
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