Carbon and its Compounds Test

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Carbon and its Compounds Test - 30

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Weekly Quiz Competition

Question 1
1 / -0

Addition reactions are limited to chemical compounds that have :

A
multiple bonds

B
single bonds

C
only double bonds

D
only triple bonds

Solution

Addition reactions are limited to chemical compounds that have multiple bonds, such as molecules with carbon-carbon double bonds (alkenes), or with triple bonds (alkynes).
Question 2
1 / -0

Cyclic alkanes are simply prefixed with:

A
alphabet

B
cyclo

C
ring

D
numbers

Solution

Cyclic alkanes are simply prefixed with "cyclo-". For example, $$C_{4}H_{8}$$ is cyclobutane and $$C_{6}H_{12}$$ is cyclohexane.
Question 3
1 / -0

In the homologous series of alkane, the boiling point increases with :

A
increase in volume

B
decrease in mass

C
increase in mass

D
decrease in number of atoms

Solution

Within the alkane homologous series, many physical properties such as boiling point gradually increase with increasing mass. For example, ethane $$(C_{2}H_{6})$$ has a higher boiling point than methane $$(CH_{4})$$.
Question 4
1 / -0

If the number of carbon atoms $$n$$ is 6, the corresponding alkane is:

A
heptane

B
hexane

C
butane

D
nonane

Solution

Carbon compounds that contain only single bonds between the carbon atoms are called alkanes. Their general formula is $$C_n{H}_{2n+2}$$.
If $$n=6$$, $$C_6H_{(2\times 6)+2}$$ $$= C_6H_{14}$$
Hence, the alkane is hexane.
Question 5
1 / -0

How many double covalent bonds can a single carbon atom form at a time?

A
1

B
2

C
3

D
4

Solution

carbon can have a maximum valency of 4 and can form at the most two double bonds.
Question 6
1 / -0

Successive members of homologous series differ from one another in their mass by:

A
10 units

B
15 units

C
20 units

D
14 units

Solution

A series of organic compounds with the same general formula but differ from adjacent members by $$"-C{H}_{2}-"$$ group are referred to as homologous series of compounds. Successive members of homologous series differ from one another in their mass by $$14 \ units$$.
For example: $$CH_4$$ and $$C_2H_6$$ are homologous series. Its molar mass is $$16$$ and $$30 \ gm/mole$$ respectively.
Hence, it is differed by unit $$14$$.
Option D is correct.
Question 7
1 / -0

Carbon exhibits ________ by sharing its four electrons.

A
pentavalency

B
tetravalency

C
trivalency

D
divalency

Solution

Carbon has four valence electrons in its outermost shell. It attains its stability by sharing these four electrons and is said to exhibit tetravalency.
Hence, option B is correct.
Question 8
1 / -0

Why a saturated hydrocarbon does not undergo addition reactions?

A
They have low stability

B
All carbon bonds are fully utilized

C
They have low boiling points

D
All of above

Solution

Saturated hydrocarbon does not undergo addition reaction because the bond between carbon atoms is already a single bond and is very stable.
Therefore, we can say all carbon bonds are fully utilized.
Question 9
1 / -0

Hydrocarbons having single bonds are known as:

A
saturated hydrocarbon

B
unsaturated hydrocarbon

C
alkyne

D
none of above

Solution

Hydrocarbons having single bonds are known as saturated hydrocarbons. Saturated hydrocarbons are known as an alkane. These are also known as paraffin.
Unsaturated hydrocarbons are having double or triple bonds i.e alkenes and alkynes.
Hence, option $$A$$ is correct.
Question 10
1 / -0

Is the following compound saturated or unsaturated?
$$C_6H_{12}$$

A
Saturated

B
Unsaturated

C
Both A and B

D
None of the above

Solution

From its molecular formula $$C_6H_{12}$$, we see that it satisfies the general formula of alkene $$C_nH_{2n}$$, where n=2. An alkene is an unsaturated compound.

$$CH_3CH_2CH_2CH=CHCH_3$$ is unsaturated due to the presence of a double bond.

Option B is correct.

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Carbon and its Compounds Test - 30

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Carbon and its Compounds Test - 30

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Question 1

multiple bonds

single bonds

only double bonds

only triple bonds

Solution

Question 2

alphabet

cyclo

ring

numbers

Solution

Question 3

increase in volume

decrease in mass

increase in mass

decrease in number of atoms

Solution

Question 4

heptane

hexane

butane

nonane

Solution

Question 5

1

2

3

4

Solution

Question 6

10 units

15 units

20 units

14 units

Solution

Question 7

pentavalency

tetravalency

trivalency

divalency

Solution

Question 8

They have low stability

All carbon bonds are fully utilized

They have low boiling points

All of above

Solution

Question 9

saturated hydrocarbon

unsaturated hydrocarbon

alkyne

none of above

Solution

Question 10

Saturated

Unsaturated

Both A and B

None of the above

Solution

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