Differentiation Test 26

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Differentiation Test 26

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Weekly Quiz Competition

Question 1
1 / -0

Which number comes next?
$$5, 9, 13, 17, 21, 25, 29,...$$

A
$$31$$

B
$$32$$

C
$$30$$

D
$$33$$

Solution

The series adds $$4$$ to each number to get the next number.
So, the next number is $$29 + 4 = 33$$
Question 2
1 / -0

Find the next number of the series.
$$7, 10, 8, 11, 9, 12,....$$

A
9

B
10

C
8

D
7

Solution

The next number is $$10$$.
The first $$2$$ numbers difference is $$3$$.
The second $$2$$ numbers difference is $$2$$.
So, this is simple alternating addition of $$ 3$$ and subtraction of $$2$$.
Question 3
1 / -0

$$2, 3,$$ __$$, 4, 4, 5, 6, 6, 6, 7, 7, 7...$$ What number should fill the blank?

A
$$1$$

B
$$2$$

C
$$3$$

D
$$4$$

Solution
Question 4
1 / -0

Which pair of numbers comes next?
$$10, 18, 12, 21, 15 ,25, ,....$$

A
$$19, 30$$

B
$$19, 27$$

C
$$30, 19$$

D
$$27, 19$$

Solution

This is an alternating addition series
First series = $$10, 10+2=12, 12+3=15$$. $$\therefore$$ next number= $$15+4=19$$
Second series = $$18, 18+3=21, 21+4=25$$ $$\therefore$$ next number = $$25+5=30$$
The next pair of numbers are $$19, 30$$.
Question 5
1 / -0

Fill in the blank: $$62, 66, 63, 66, 64,$$ __$$, 65,....$$

A
60

B
61

C
62

D
63

Solution

The series alternates the addition of $$4$$ with the subtraction of $$3$$.
So, the missing number is $$61$$.
Question 6
1 / -0

Look at this series: $$32, 31, 33, 32, 34, 33,...$$. What is the next number?

A
34

B
32

C
35

D
36

Solution

The next number is $$35$$.
Here first $$1$$ is subtracted and then $$2$$ is added, and so on.
Question 7
1 / -0

Find the value of $$'?'$$ in the series: $$12, 17, 15, ?, 18, 23, 21,....$$

A
20

B
21

C
22

D
24

Solution

The series alternates the addition of $$5$$ with the subtraction of $$2$$.
So, the number is $$20$$.
Question 8
1 / -0

The area of the triangle formed from points $$(1, 2), (2, 4)$$ and $$(3, 1)$$ is ____ square units.

A
$$\dfrac{5}{2}$$

B
$$\dfrac{2}{5}$$

C
$$\dfrac{3}{2}$$

D
$$2$$

Solution

Formula for area of triangle is $$\left|\dfrac{1}{2}[x_{1}(y_{2}-y_{3}) + x_{2} (y_{3} - y_{1}) + x_{3} (y_{1} - y_{2})] \right|$$
where $$x_{1} = 1$$, $$y_{1} = 2$$, $$x_{2} = 2$$, $$y_{2} = 4$$, $$x_{3} = 3$$ and $$y_{3} = 1$$
Substitute the values, we get,
Area of triangle $$=$$ $$\left|\dfrac{1}{2}\times[1(4 - 1) + 2(1 - 2) + 3(2 - 4)]\right|$$
$$=$$ $$\left|\dfrac{1}{2}\times[3 - 2 - 6]\right|$$
$$=$$ $$\left|\dfrac{1}{2}\times -5\right|$$
$$=$$ $$\left|-\frac{5}{2} \right|$$
Area always in absolute value.
So, area of the triangle $$= \dfrac{5}{2}$$ square units.
Question 9
1 / -0

Choose the missing number in the series: $$2, 2, 3, 4, 4,$$__$$, 6, 6, 7, 8, 8, 9....$$

A
5

B
6

C
7

D
8

Solution

This is a continuous series of adding $$1$$ to the previous number, in which every third number is not repeated.
So, the missing number is $$5$$.
Question 10
1 / -0

Find the value of $$'x'$$ in the series: $$144, 169, x, 225, 256, 289$$.

A
190

B
192

C
196

D
195

Solution

The series is a perfect square in increasing order of $$12, 13, 14, 15...$$
So, the value of $$x$$ is $$196$$.

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Re-Attempt Weekly Quiz Competition

Differentiation Test 26

Result

Differentiation Test 26

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Rank

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SHARING IS CARING

Question 1

$$31$$

$$32$$

$$30$$

$$33$$

Solution

Question 2

9

10

8

7

Solution

Question 3

$$1$$

$$2$$

$$3$$

$$4$$

Solution

Question 4

$$19, 30$$

$$19, 27$$

$$30, 19$$

$$27, 19$$

Solution

Question 5

60

61

62

63

Solution

Question 6

34

32

35

36

Solution

Question 7

20

21

22

24

Solution

Question 8

$$\dfrac{5}{2}$$

$$\dfrac{2}{5}$$

$$\dfrac{3}{2}$$

$$2$$

Solution

Question 9

5

6

7

8

Solution

Question 10

190

192

196

195

Solution

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