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Sequences and Series Test 46

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Sequences and Series Test 46
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Weekly Quiz Competition
  • Question 1
    1 / -0
    How many Pythagorean triangles are there with integer sides and one leg is Ramanujan Number 1729 .
  • Question 2
    1 / -0
    Find the missing number, if a certain rule is followed
    $$1$$$$9$$?
    $$2$$$$12$$$$14$$
    $$3$$$$117$$$$105$$
     either row-wise or column-wise.
    Solution

  • Question 3
    1 / -0
    Direction: In a given question, one number is missing in the series. you have to understand the pattern of the series and insert the number 
    JN    28   27    GP
    CE   12   45    TU
    LR     ?     ?     MS
  • Question 4
    1 / -0
    The number of the three digits numbers having only two consecutive digits identical is:
    Solution

  • Question 5
    1 / -0
    $$10$$ IIT and $$2$$ NIT students sit at random in a row, and then number of ways in which exactly $$3$$ IIT students sit between $$2$$ NIT students is
    Solution

  • Question 6
    1 / -0
    The area of the triangle whose co-ordinates are $$(2012, 7), (2014, 7)$$ and $$(2014, a)$$ is $$1 \,sq$$ unit. The sum of possible values of $$a$$ is
    Solution

  • Question 7
    1 / -0
    If $$ '-'$$ denotes $$'\div ',\ '\div '$$ denotes $$'\times ',\ '+'$$ denotes' - 'and $$'\times '$$ denotes $$'+'$$, then find the value of $$116+9\div 52-4\times 5$$.
    Solution
    $$-$$ denoted $$\div$$
    $$\div$$ denoted $$\times $$
    $$+$$ denoted $$-$$
    $$\times $$ denoted $$+$$       $$\boxed{BODMAS}$$
    $$116+9\div 52-4\times 5$$
    $$116-9\times 52\div 4+5$$
    $$116-9\times 13+5$$
    $$116-117+5$$
    $$116-112=4$$
  • Question 8
    1 / -0
    If $$n\ \in\ N$$ & $$n$$ is even, then $$\dfrac {1}{1\ .\ (n-1)\ !}+\dfrac {1}{3\ !(n-3)\ !}+\dfrac {1}{5\ !\  (n-5)\ !}+....+\dfrac {1}{(n-1)\ !\ 1\ !}=$$ 
    Solution

  • Question 9
    1 / -0
    $$40280625, 732375, 16275, 465, 18.6, 1.24,?$$
    Solution
    $$40280625, 732375,16275,465,18.6,1.24$$
    $$\cfrac{40280625}{732375}=55$$
    $$\cfrac{732375}{16275}=45$$
    $$\cfrac{16275}{465}=35$$
    $$\cfrac{465}{18.6}=25$$
    $$\cfrac{18.6}{1.24}=15$$
    $$\cfrac{1.24}{x}=5$$
    $$x=0.248$$

  • Question 10
    1 / -0
    $$435, 354, 282, 219, 165, ?$$
    Solution
    $$\therefore 165-45=x$$
    $$x=120$$.

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