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Relations Test 13

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Relations Test 13
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  • Question 1
    1 / -0
    Let $$A=\left \{ 1, 2, 3 \right \}$$. Which of the following is not an equivalence relation on A?
    Solution
    every relation in options follow the equivalence property.
    but in fourth option this option only contains two elements $$[[{1,1}],[{2,1}]]$$
    this option doesn't satisfy reflexive i.e., doesn't contain all $$(a,a)$$ type $$(2,2),(3,3)$$
    Not symmetric i.e., doesn't contain this type of elements  $$(1,2)$$ missing
    and as well transitive.

    and all others options satisfy these relations. 
  • Question 2
    1 / -0
    The relation "congruence modulo $$m$$" is:
    Solution
    If $$R$$ be the relation, then
    $$x R y$$ $$\Leftrightarrow  x-y$$ is divisible by $$m$$.
    $$x R x$$ because $$x-x=0$$ is divisible by $$m$$. 
    So, $$R$$ is reflexive. 
    If $$xRy\Rightarrow x-y$$ is divisible by $$m$$
    $$y-x=-(x-y)$$ is divisible by $$m$$
    $$\Rightarrow yRx$$
    So, $$R$$ is symmetric
    Let $$x R y$$ and $$y R z$$
    $$\Rightarrow x-y=k_{1}m, y-z=k_{2}m$$
    $$\therefore x-z=x-y+y-z=k_{1}m+k_{2}m=(k_{1}+k_{2})m$$. 
    So, $$R$$ is transitive.
    As R is reflexive, symmetric and transitive, it is an equivalence relation.
  • Question 3
    1 / -0
    The minimum number of elements that must be added to the relation $$R=\left \{ (1, 2),(2, 3) \right \}$$ on the set of natural numbers, so that it is an equivalence is:
    Solution
    Since $$R=\left \{ (1, 2),(2, 3) \right \}$$
    i.e.,  $$A=\left \{ (1, 2) \right \} $$ and $$B=\left \{ 2, 3 \right \}$$
    Now, if $$R_{r}$$ is the reflexive relation, such that 
    $$R_{1}=\left \{ (1, 2),(2, 3),(1, 1),(2, 2),(3, 3) \right \}$$ has $$5$$ elements.
    Now, if  R' is both symmetric and reflexive relation, then 
    $$R_{2}=\left \{ (1, 2),(2, 3),(1, 1),(2, 2),(2, 1),(3, 2),(3, 3) \right \}$$ has $$7$$ elements
    Again, if $$R_{3}$$ is reflexive, symmetric and transitive all together, than 
    $$R_{3}=\begin{Bmatrix} (1, 2) & (2, 3) & (1, 1) \\ (2, 2) & (2, 1) & (3, 2) \\ (3, 3) & (1, 3) & (3, 1)\end{Bmatrix} $$
    has $$9$$ elements. Starting from $$2$$ elements, therefore, the minimum number of elements to be added is $$7$$.
  • Question 4
    1 / -0
    Let R be the relation in the set N given by $$=\left \{ (a, b):a=b-2, b >6 \right \}$$. Choose the correct answer.
    Solution
    $$(a,b)∈R$$ only if $$a=b−2$$ and $$b>6$$
    $$(6,8)∈R$$ as $$6=8−2$$ and $$8 >6$$
    Hence $$(c)$$ is the correct alternative
  • Question 5
    1 / -0

    Directions For Questions

    Based on this information answer the question
    (i) If $$A=\left \{ 1, 2, 3, 4 \right \}$$ the $$p(A)=\left \{ \phi , \left \{ 1 \right \}, 
    \left \{ 2 \right \}, \left \{ 3 \right \}, \left \{ 1, 2 \right \}, \left \{ 2, 3 \right \}, 
    \left \{ 1, 3 \right \}, \left \{ 1, 2, 3 \right \} \right \}$$ 
    Power set of an empty set, $$p(\phi )=\left \{ \left ( \phi  \right ) \right \}$$ and $$n\{p(\phi 
    )\}=1.$$
    (ii) Any subset of $$A\times A $$ is called a relation on A. Number of relations on $$A=2^{n^{2}}$$

    ...view full instructions

    Find the number of relations from $$\left \{ m, o, t, h, e, r \right \}$$ to $$\left \{ c, h, i, l, d \right \}$$
    Solution
    $$n \{m.o,t,b,e,r\} = 6 = m$$ (let)
    $$n \{c,h,i,l,d\} = 5 = n$$ (let)

    $$\therefore $$ numbers of Relations 
    $$= { 2 }^{ mn }$$
    $$= { 2 }^{ 6\times 5 }$$
    $$= { 2 }^{ 30 }$$                                                                      
  • Question 6
    1 / -0
    If $$R$$ is a relation from a set $$A$$ to a set $$B$$ and $$S$$ is a relation from $$B$$ to a set $$C$$, then the relation $$SOR$$
    Solution
    Domain of $$SOR$$ is the domain of $$R$$ and the range is the range of $$S$$. Hence the mapping is from set $$A$$ to set $$C$$. 
  • Question 7
    1 / -0
    Let $$A=\left \{ 1,2,3 \right \}$$. The total number of distinct relations that can be defined over $$A$$ is:
    Solution
    Total number of distinct binary relations over the set $$ A$$ will be
    $$2^{n^2}$$
    $$=2^{3^{2}}$$
    $$=2^{9}$$
    $$=512$$
  • Question 8
    1 / -0
    Which of the following statements is true?
    Solution
    Since, Origin is the point of intersection of $$x$$ and $$y,$$ we can say that option $$D$$ is correct.
  • Question 9
    1 / -0
    Let $$R=\{(1, 3), (2, 2), (3, 2)\}$$ and $$S=\{(2, 1), (3, 2), (2, 3)\}$$ be two relations on set $$A=\{1, 2, 3\}$$.Then $$R$$o$$S$$ is equal
    Solution
    If $$f\epsilon X\times Y$$ and $$g\epsilon Y\times Z$$

    Then
    $$gof\epsilon X\times Z$$ i.e
    $$ (x,z)\epsilon gof$$

    Applying the above concept, we gives us
    $$RoS=\{(2,1)|(1,3),(3,2)|(2,2),(2,3)|(3,2)\}$$

    $$=\{(2,3),(3,2),(2,2)\}$$
  • Question 10
    1 / -0
    If $$A=\{1, 2, 3\}$$ and $$B=\{3, 8\}$$, then $$(A\cup B)\times (A\cap B)$$ is
    Solution
    $$A\cup B=\{1,2,3,8\}$$
    $$A\cap B=\{3\}$$
    $$\therefore (A\cup B)\times (A\cap B)$$
    $$=\{(1,3),(2,3),(3,3),(8,3)\}$$
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