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Numerical Applications Test 16

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Numerical Applications Test 16
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  • Question 1
    1 / -0
    Saturday was a holiday for Republic Day, $$14$$th of the next month is again holiday for Shivratri. What day was it on the $$14$$th?
  • Question 2
    1 / -0
    A group of workers accepted to do a piece of work in $$25$$ days.If $$6$$ of them did not turn up for the work and the remaining workers did the work in $$40$$ days, then the original number of workers was
    Solution
    Let $$x$$ no. of men can do work in 25 days
    Using $$M_1D_1=M_2D_2$$
    $$25x=(x-6)40$$
    $$15x=240$$
    $$X=16$$
  • Question 3
    1 / -0
    $$120$$ men got food provision for $$200$$ days.After $$5$$ days, $$30 $$men died of an epidemic.The food will last for further
    Solution
    $$120 \times 200 =120\times 5 +90 \times x$$
    $$120[200-5]=90 \times x$$
    $$\dfrac{120 \times 195}{90}=x$$
    $$x=260\ days$$
  • Question 4
    1 / -0
    A bus travels 126 km in 3 hours and a train travels 315 km in 5 hours . The ratio of their speeds is ______ .
    Solution
    $$\Rightarrow$$ A bus travels $$126\,km$$ in $$3\,hrs$$.
    $$\Rightarrow$$ A train travels $$315\,km$$ in $$5\,hrs$$.
    $$\Rightarrow$$  We know, $$Speed=\dfrac{Distance}{Time}$$

     $$\therefore$$   Speed of bus = $$\dfrac{126}{3}=42\,km/hr$$

    $$\therefore$$   Speed of train = $$\dfrac{315}{5}=63\,km\,hr$$

    $$\therefore$$  Ratio of speeds = $$\dfrac{42}{63}=\dfrac{2}{3}=2:3$$
  • Question 5
    1 / -0
    There is leak in the bottom of a tank. This leak can empty full tank in 8 hours.When the tank is full, a tap is opened into the tank which admits 6 litres per hour and the tank is now emptied in 12 hours.What is the capacity of the tank?
    Solution
    Working by the in let in 1 hour
    $$\dfrac{1}{8}-\dfrac{1}{12}=\dfrac{1}{24}$$
    $$\therefore $$ Volume of $$\dfrac{1}{24}$$ part = 6 litres
    $$\therefore$$ Volume of whole = $$24 \times 6$$ litres
    $$=144$$ litres.
  • Question 6
    1 / -0
    $$3$$ men or $$5$$ women can do a work in $$12$$ days. How long will $$6$$ men and $$5$$ women take to finish the work?
    Solution
    $$3 men$$ $$\equiv 5 women$$ 

    $$6 men + 5 women \equiv 15 women$$

    Now, $$5 women$$ can do it in $$12$$ days.

    $$1 women$$ can do it in $$12$$ $$\times 5 = 60$$ days.

    $$15 women$$ can do it in $$=\dfrac{12\times 5}{15}=4$$ days.
  • Question 7
    1 / -0
    A can do $$\dfrac 12$$ of a piece of work in $$5$$ days. B can do $$3S$$ of the same work in $$9$$ days and C can do $$\dfrac 23$$ of that work in $$8$$ days. In how many days can three of them together do the work. 
    Solution
    Given that,
    A does $$\displaystyle\frac{1}{2}$$ work in 5 days.
    A does the whole work in 10 days.
    B does $$\displaystyle\frac{3}{5}$$ work in 9 days.
    B does the whole work in 15 days.
    C does $$\displaystyle\frac{2}{3}$$ of work in 8 days.
    does the whole work in 12 days.
    Let the total unit of work be 60 units. [LCM of (10, 15, 12)] 
    A does = $$\displaystyle\frac{60}{10}$$ = 6 units/day
    B does = $$\displaystyle\frac{60}{15}$$ = 4 units/day
    C does = $$\displaystyle\frac{60}{12}$$ = 5 units/day
    (A  + B + C)s together per day work = 6 + 4 - 5 = 15 units/day
    Days required to complete the work = $$\displaystyle\frac{60}{15}$$ = 4 days.
  • Question 8
    1 / -0
    Choose the correct answer from the alternatives given.
    A can complete a work in m days and B can complete it in n days. How many days will it take to complete the work if both A and B work together?
    Solution
    Let the total work be mn units. [LCM of m and n]
    A does =$$\dfrac{mn}{m}$$ = n units/day

    B does =$$\dfrac{mn}{n}$$ = m units / day
    A and B together do = (n + m) units/day
    Hence, the work will get completed by them in $$\dfrac{mn}{m + n}$$ days. 
  • Question 9
    1 / -0
    Two taps A and B can fill a tank in $$10$$ hrs and $$12$$ hrs respectively. If both the taps are opened together, the tank will be full in
    Solution
    $$ A $$    $$ B $$
    $$ \Downarrow $$     $$ \Downarrow $$
    $$ 10\,  hr $$  $$ 12\, hr $$
    $$ = \dfrac{1}{10} + \dfrac{1}{12} = \dfrac{6+5}{60} = \dfrac{11}{60}$$
    $$ = \dfrac{60}{11} hrs $$
    $$ = 5 \dfrac{5}{11} hrs $$

  • Question 10
    1 / -0
    A can do a piece of work in $$9$$ days. B is $$50\%$$ more efficient than A. The number of days it takes B to do the same piece of work is:
    Solution
    In one day A can do $$1/9$$ of the job.
     Since B is $$50\%$$ more efficient than A
    B can do $$\dfrac32.\dfrac 19=\dfrac16$$ of the job in one day.
     Therefore, B needs $$6$$ days for the complete job.
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