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Numerical Applications Test 31

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Numerical Applications Test 31
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  • Question 1
    1 / -0
    On which day of the week was the New year's day celebrated in $$2007$$ ?
    Solution
    To find the New year's day celebrated in 2007, we will find the day on 1st Jan;2007.
    1st Jan 2007 = 2006 years + 01/01/2007 
    2000 years have 0 odd days.
    Now, 6 years comprise of 1 leap year and 5 ordinary years.
    So, the number of odd days in 6 years =1  2 + 5 = 7 days or 0 odd days.
    There are 0 odd days till 31st Dec 2006.
    Therefore, the day on 1st Jan 2007 is Monday. 
    Hence,  option (B) is the correct answer.
  • Question 2
    1 / -0
    If yesterday of yesterday was Wednesday, which of the following days would represent tomorrow's yesterday ?
    Solution
    Given, yesterday of yesterday was Wednesday.So, the present day is Friday.
    Now, the tomorrow of present day (Friday) is Saturday.
    So,     tomorrow's yesterday will again be Friday. 
    Hence, option (C) is the correct answer.
  • Question 3
    1 / -0
    If $$\text{26 January 1995}$$ fell on a Thursday, on what day did it fall in the year $$1986$$ ?
    Solution
    Given, 26 January 1995 fell on a Thursday and we have to find the day on 26th Jan 1986.
    Between, 26 Jan 1986 and 26 Jan 1995, we have 2 leap years (1988 and 1992) and 7 ordinary years.
    Therefore, number of odd days = 2 X 2 + 7 X 1 = 11 days or 1 week and 4 odd days
    So, the day on 26 Jan 1985 is 4 days back from Thursday i.e., Sunday.  
    Hence, option (C) is the correct answer.
  • Question 4
    1 / -0
    If it was a Saturday on $$\text{18 December 1982}$$, what was the day on $$\text{22 September 1984}$$ ?
    Solution
    Given, it was Saturday on 18 December 1982.
    We know that 1982 is an ordinary year which has only 1 odd day.
    Therefore, 1    8 December 1983 is Sunday.
    So, 25th Dec 1983 and 1 Jan 1984 is also a Sunday and 1984 is a leap year.
    Now, In 1984, till 22nd Sep, the number of odd days is calculated as follows:
    Month Jan                    Feb    Mar    Apr    May   Jun    July    Aug     Sept  
    Days     30(= 31 - 1) +   29  +   31 +   30  +  31   + 30  +  31   +  31   + 22   = 265 days or 37 weeks and 6 odd days.
    Therefore, the day on 22nd September 1984 is 6 days after Sunday(on 1 Jan 1984) i.e., Saturday.       
    Hence, the day on 22nd Sep 1984 is Saturday.
     
  • Question 5
    1 / -0
    If $$\text{8 March 1985}$$ was Friday, then which was the day on $$\text{26 July 1985}$$ ?
    Solution
    Given year 1985 is non-leap year and 8 March 1985 of the year was Friday.
    Let us find the number of odd days between 8 Mar and 26 July.
    Month   Mar               Apr    May    Jun    July     
    Days     23(=31 -8) +  30  +  31   +  30  +  26  = 140 days or 20 weeks    
    So, the day on 26th July will be the same as the day on 8 March i.e., Friday.
     Hence, option (B) is the correct answer.
  • Question 6
    1 / -0
    A person born on a Monday in July 1921 retires in 1981 on the day he attains the age of 60. He retires on
    Solution
    As we know that date jumps by one day when year is changed and date jumps by $$5$$ days in a four year time gap because it include a leap year.
    Since there will be $$15$$ leap years between $$1921$$ to $$1981$$.
    So, he retires in $$1981$$ on the day $$=\dfrac{5\times 15}{7}\Rightarrow 5(Remainder)$$
    Hence, it will be $$5^{th}$$ day of week that is $$Friday.$$
  • Question 7
    1 / -0
    If the day before yesterday was Thursday when will be Sunday?
    Solution
    If day before yesterday was Thursday so today is Saturday So tomorrow will be Sunday
  • Question 8
    1 / -0
    If p persons working p hours a day for each of p days produce p units of works, then the units of work produced by q persons working q hours a day for each of q days is
    Solution
    $$\because$$ Persons working p hours a day in p days produce p units of work
    $$\therefore$$ 1 person working 1 hours a day in 1 day produces

    $$\displaystyle=\frac{p}{p\times p\times p}$$

    $$\therefore$$ q persons working q hours a day in q days produce

    $$\displaystyle=\frac{p\times q\times q\times q}{p^3}=\frac{q^3}{p^2}$$
  • Question 9
    1 / -0
    A is 3 times more efficient than B. Hence, he takes 60 days less in painting a room. In how many days, work will be completed, if A & B both work together ?
    Solution
    A : B = x : 3x
    Given that 3x - x = 60 = x = 30
    A's efficiency = 30 and B's efficiency = 3 x 30 = 90
    When A and B work together, they can complete the work in $$\displaystyle \dfrac { 30\times 90 }{ 120 } =22\dfrac { 1 }{ 2 } $$ days
  • Question 10
    1 / -0
    If 4 days before today it was Monday, what day will it fall on after 3 days ? 
    Solution
                 ________Before Four Days 
                                    (Monday)
                ________ Tuesday
                _________ Wednesday
                __________ Thursday
    Today  _________ Friday
                __________ Saturday
                ____________ Sunday
                ____________ After three days
                                               (Monday)
    Hence it will also be Monday after three days.
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