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Numerical Applications Test 7

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Numerical Applications Test 7
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  • Question 1
    1 / -0
    A can do a piece of work in 40 days. He worked at it for 5 days, then B finished it in 21 days. The number of days that A and B take together to finish the work are
    Solution
    A csn do a piece of work in 40 days
    Work of A in 1 day=1/40
    Work of A in 5 days=5/40=1/8
    1/8th part of work is done by A
    Remaining work=$$\left( 1-\frac { 1 }{ 8 }  \right) =\frac { 7 }{ 8 } $$
    7/8th part is done by B in 21 days
    Total work will be done by B  in $$=\frac { 21 }{ \frac { 7 }{ 8 }  } =\frac { 21 }{ 7 } \times 8=24days$$
    Work done by B in one day=1/24
    Work done by A and B together in one day will be$$\left( \frac { 1 }{ 40 } +\frac { 1 }{ 24 }  \right) $$
     $$\left( \frac { 3+5 }{ 120 }  \right) =\frac { 8 }{ 120 } =\frac { 1 }{ 15 } $$
    A and B will take 15 days to complete the work together.


  • Question 2
    1 / -0
    Out of 100 students 50 fail in English and 30 in Maths. If 12 students fail in both English and Maths, then the number of students passing both the subjects is
    Solution
    Total number of students=100
    Number of students fail in English=(50-12)=38
    Number of students fail in Maths=(30-12)=18
    Number of students fail in both=12
    Therefore total failing students=(38+18+12)=68
    Pass in both the subjects=(100-68)
                                              =32 students
    32 students have passed in both subjects
  • Question 3
    1 / -0
    Find the AM of $$20$$ and $$26$$.
    Solution
    $$\displaystyle AM=\frac { 20+26 }{ 2 } =\frac { 46 }{ 2 } =23$$
  • Question 4
    1 / -0
    The mean of the following natural numbers $$1, 2,3 ...... 10$$ is
    Solution
    Mean $$ = \dfrac {1 + 2 + 3 + 4 + 5 +6 + 7 + 8 + 9 + 10}{10} = 5.5 $$
  • Question 5
    1 / -0
    A clocks takes six seconds to strike four how long it will take to strike ten?
    Solution
    When the clock strikes four there are three intervals between So three interval take 6 seconds and each interval takes 2 seconds
    Now when it strikes 10 there are 9 intervals
    and it takes 18 sec
  • Question 6
    1 / -0
    If $$35$$ men can reap a field in $$8$$ days; in how many days can $$20$$ men reap the same field ?
    Solution
    Since Total work done is same.
    $$35 \times 8=20 \times x$$
    $$\Longrightarrow x=\dfrac{35 \times 8}{20}$$
    $$\Longrightarrow x=14$$ days
  • Question 7
    1 / -0
    In a class there are 18 boys who are over 160 cm tall If these constitute three-fourths of the boys and the total number of boys is tow-third of the total number of students in the class what is the number of girls in the class?
    Solution
    Given in class there are 18 boys who over 160 cm tall and these are three- fourths of total boys 
    Then total boys in class=$$18\div  \frac{3}{4}= 18\times \frac{4}{3}=24$$
    And total no of student in class=$$24\times \frac{3}{2}=36$$
    Then number of girls=36-24=12
  • Question 8
    1 / -0
    A scanner can print at a rate of $$5$$ pages per minute. Calculate the number of hours will it take to print $$300$$ pages?
    Solution
    Scanner print $$5$$ pages in $$1$$ minute.
    $$\therefore$$ number of hours required to print $$300$$ pages would be $$=$$ $$\dfrac{300}{5}=60$$ minute $$=1$$ hour.
  • Question 9
    1 / -0
    $$10$$ pipes fill a tank in $$3$$ hours. How many pipes are required to fill it in $$2$$ hours?
    Solution
    This is an example is of inverse proportion
    No. of pipes     Time taken
    $$10$$                        $$3$$ hours
    $$x$$                          $$2$$ hours
    By inverse proportion,
    $$10\times 3 = x\times 2$$
    $$\therefore x = \dfrac{10\times3}{2}$$
    $$\therefore x = 15$$
    Hence the answer is option A

  • Question 10
    1 / -0
    A person crosses a 600 m long street in 5 minutes. what is his speed in km per hour ?

    Solution
    Distance=600m
    Time=5 min=5\times 60  sec
    $$Speed=\dfrac{Distance}{times}$$
    $$\Rightarrow \dfrac{600}{5\times 60}  m/sec$$
    $$\Rightarrow 2  m\sec\Rightarrow 2\times\dfrac{18}{5}=7.2 Km/hr$$
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