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Numerical Applications Test 9

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Numerical Applications Test 9
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Weekly Quiz Competition
  • Question 1
    1 / -0
    How many days are there in x weeks x days?
    Solution
    x weeks x days = (7x + x) days = 8x days.
  • Question 2
    1 / -0
    January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?
    Solution
    The year 2008 is a leap year. So, it has 2 odd days.
    1st day of the year 2008 is Tuesday (Given)
    So, 1st day of the year 2009 is 2 days beyond Tuesday.
    Hence, it will be Thursday.
  • Question 3
    1 / -0
    In one hour, a boat goes 11 km/hr along the stream and 5 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
    Solution
    Speed in still water $$=\frac{1}{2}(11+5)kmph=8kmph$$
  • Question 4
    1 / -0
    A train 800 metres long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is:
    Solution
    $$Speed = \left( 78 \times \dfrac{5}{18} \right) m/sec = \left( \dfrac{65}{3} \right) m/sec$$
    Time = 1 minute = 60 seconds.
    Let the length of the tunnel be x metres.
    Then, $$\left( \dfrac{800 + x}{60} \right) = \dfrac{65}{3}$$
    $$\Rightarrow 3 (800 + x) = 3900$$
    $$\Rightarrow x = 500$$
  • Question 5
    1 / -0
    A 300 metre long train crosses a platform in 30 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
    Solution
    $$Speed = \left( \dfrac{300}{8} \right) m/sec = \dfrac{50}{3} m/sec$$
    Let the length of the platform be x metres.
    Then, $$\left( \dfrac{x + 300}{39} \right) = \dfrac{50}{3}$$
    $$\Rightarrow 3(x + 300 ) = 1950$$
    $$\Rightarrow x = 350 m$$
  • Question 6
    1 / -0
    A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is
    Solution
    Let the speed of the second train be x km/hr
    Relative speed = (x + 50) km/hr
    =[(x+50)×518]m/sec
  • Question 7
    1 / -0
    The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is
    Solution
    $$Speed=(45\times \dfrac{5}{18})m/sec$$
    Time = 30 sec.
    Let the length of bridge be x metres.
    Then, $$\dfrac{130 + x}{30} = \dfrac{25}{2}$$
    $$\Rightarrow 2(130 +x) = 750$$
    $$\Rightarrow x = 245 m$$
  • Question 8
    1 / -0
    4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat-weavers in 8 days?
    Solution
    Let the required number of bottles be x.
    More weavers, More mats (Direct Proportion)
    More days, More mats (Direct Proportion)
    $$\left.\begin{matrix}Wavers & 4 : 8 \\ Days  &  4 : 8 \end{matrix}\right\} :: 4 : x$$
    $$\therefore 4 \times 4 \times x = 8 \times 8 \times 4$$
    $$\Rightarrow x = \dfrac{(8 \times 8 \times 4)}{(4 \times 4)}$$
    $$\Rightarrow x = 16$$
  • Question 9
    1 / -0
    Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is
    Solution
    Let the speed of the slower train be x m/sec.
    Then, speed of the fater train = 2x m/sec.
    Relative speed = (x + 2x) m/sec = 3x m/sec.
    $$\therefore \dfrac{100 + 100}{8} = 3x$$
    $$\Rightarrow 24 x = 200$$
    $$\Rightarrow 24 x = 200$$
    $$\Rightarrow x = \dfrac{25}{3}$$
    So, speed of the faster train $$= \dfrac{50}{3} m/sec$$
    $$\left( \dfrac{50}{3} \times \dfrac{18}{5} \right) km/hr$$
    $$= 60 km /hr$$
  • Question 10
    1 / -0
    On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?
    Solution
    The year 2006 is an ordinary year. So, it has 1 odd day.
    So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.
    But, 8th Dec, 2007 is Saturday.
    $$\displaystyle \therefore $$ 
    8th Dec, 2006 is Friday.
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