Straight Lines Test 28

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Straight Lines Test 28

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Question 1
1 / -0

Find the missing number in above figure :

A
$$35$$

B
$$40$$

C
$$49$$

D
$$53$$

Solution

$$23 + 5 = 28, 45 + 5 = 50, 35 + 5 = 40$$.
$$\therefore$$ The solution is $$40$$.
Question 2
1 / -0

Find the missing number in above figure :

A
$$P$$

B
$$H$$

C
$$M$$

D
$$L$$

Solution

Position of $$N \rightarrow 14$$ (in alphabetical order)
Position of $$T \rightarrow 20$$
Position of $$B \rightarrow 2$$
$$\therefore$$ Position of $$P \rightarrow 16$$.
$$\therefore$$ The solution is $$P$$.
Question 3
1 / -0

Directions For Questions

In these questions, numbers are placed in the figures on the basis of some rules. One place is vacant which if indicated as'?' Find out the correct alternatives to replace the question mark '?'

...view full instructions

The figure is given.

A
$$144$$

B
$$100$$

C
$$116$$

D
$$169$$

E
$$180$$

Solution

By observation, the no. in the middle circle is the sum of the cube of all the no.s outside the square
$$\implies 1^3+2^3+4^3+6^3=289$$ : Circle 2
$$\implies 1^3+5^3+6^3+7^3=685$$ : Circle 3
Thus, $$1^3+2^3+3^3+4^3=100$$ : Circle 1
Thus, the answer is $$100$$.
Question 4
1 / -0

Find the missing number in above figure :

A
$$110$$

B
$$1$$

C
$$55$$

D
$$441$$

Solution

$$\dfrac {11\times 10}{2} = 55$$
Question 5
1 / -0

Find the missing number in above figure :

A
$$38$$

B
$$66$$

C
$$68$$

D
$$70$$

Solution

Sum of all digits is $$7$$.
example $$142$$ $$i.e$$ $$1+4+2 = 7$$
$$\therefore$$ The solution is $$70$$.
Question 6
1 / -0

$$4C$$ $$2B$$ $$3A$$
$$28A$$ ? $$45B$$
$$7C$$ $$8A$$ $$15B$$

A
$$16C$$

B
$$12C$$

C
$$13C$$

D
$$7C$$

Solution
Question 7
1 / -0

Find the missing number in above figure :

A
$$100$$

B
$$10$$

C
$$200$$

D
$$9$$

Solution

$$5 \times 3 = 15, 8 \times 3 = 24$$
$$14 \times 2 = 28, 16 \times 2= 32$$
$$25 \times 2 = 50, 10 \times 2 = 20$$.

$$\therefore$$ The solution is $$10$$.
Question 8
1 / -0

In the given question, in four out of the five figures of element $$I$$ is related to element $$II$$ in some particular way. Find out the figure in which the element is not related to element $$II$$.The figures are given.

A

B

C

D

E

Solution

The relation between I and II is:

(1)There is a 'shift' of the whole pattern by one spot.

(2)The first $$3$$ shapes shift by one place.

(3)The $$4^{th}$$ shape does not shift but instead changes into some other shape

(4)The $$5^{th}$$ shape shifts by $$2$$ places.

Option D doesn't follow (3) and (4).
Question 9
1 / -0

Find the area (in square units) of the triangle whose vertices are $$(a, b+c), (a, b-c) $$ and $$(-a, c). $$

A
$$2ac$$

B
$$2bc$$

C
$$b(a+c)$$

D
$$c(a-h)$$

Solution

Area of triangle having vertices $$(x_1,y_1), (x_2,y_2)$$ and $$(x_3,y_3)$$ is given by
Area $$ = \dfrac{1}{2} \times |[ x_1 (y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) ] |$$
Given the vertices of triangle,
$$A (a,b+c) ,B(a,b-c) ,C(-a,c)$$
Therefore, area is given by
$$=\dfrac { 1 }{ 2 } |\left[ a\left[ b-c-c \right] +a\left[ c-b-c \right] +(-a)\left[ b+c-b+c \right] \right]| \\ =\dfrac { 1 }{ 2 } |\left[ a(b-2c)+a(-b)-a(2c) \right]| \\ =\dfrac { 1 }{ 2 } |\left[ ab-2ac-ab-2ac \right]| =\left| \dfrac { -4ac }{ 2 } \right| =2ac$$
Question 10
1 / -0

Directions For Questions

In the questions, numbers are placed in figures on the basis of some rules. One place in the figure is indicated by the interrogation sign (?). Find out the correct alternative to replace the question mark and indicate your answer by filling the circle of the corresponding letter of alternatives in the OMR Answer sheet.

...view full instructions

The figure is given

A
$$P$$

B
$$H$$

C
$$M$$

D
$$L$$

Solution

We can observe the figure as :
Position of $$N$$ is $$14$$
Position of $$T$$ is $$20$$
Position of $$B$$ is $$2$$
Position of $$P$$ is $$16$$