Straight Lines Test 41

Result

Straight Lines Test 41

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

$$16,40,100,250 , ?$$

A
$$575$$

B
$$625$$

C
$$425$$

D
$$525$$

Solution

$$16,40,100,250,?$$
$${ \underline { 4 } }^{ 2 },\underline { 4 } \times \underline { \left( 10 \right) } ,{ \left( 10 \right) }^{ 2 },\underline { 10 } \times \left( 25 \right) ,{ \left( 25 \right) }^{ 2 }$$
$$16,40,100,250,625$$.
Question 2
1 / -0

In the given figure (not drawn to scale), the coordinates of P, Q and R are (3, 0) (0, 5) and (0, -5) respectively. Find the area of $$\Delta PQR$$.

A
20 sq. units

B
40 sq. units

C
15 sq. units

D
25/2 sq. units

Solution
Question 3
1 / -0

Find the missing number

A
$$11$$

B
$$13$$

C
$$15$$

D
$$17$$

Solution

$$\textbf{Step 1: Observe the numbers opposite to each other}$$
$$ \text{We can see that the number opposite to 196 is 14. Also, } \dfrac{196}{14}=14$$
$$\text{Hence, we can say the missing number has at least one factor of 14}$$
$$\text{We see the missing number is opposite to 154}$$
$$\text{Also, } 14\times11=154$$
$$\text{Hence, let's assume the missing number is 11}$$
$$\textbf{Step 2: Verification}$$
$$\text{Let the missing number be x.}$$
$$\text{According to the question, }$$
$$\Rightarrow 14+196+x=221$$
$$\Rightarrow x=221-14-196$$
$$x=11$$
$$\text{Hence, it is verified that x=11}$$
$$\textbf{Thus, the missing number is (A) 11.}$$
Question 4
1 / -0

Find : $$13,23,43,83,163 , ?$$

A
$$326$$

B
$$323$$

C
$$321$$

D
$$318$$
Question 5
1 / -0

The number of seven letter words that can be formed by using the letters of the word $$SUCCESS$$ that the two $$C$$ are together but no two $$S$$ are together is

A
$$24$$

B
$$18$$

C
$$54$$

D
none of these

Solution

using the letters of the word $$SUCCESS$$ that the two $$C$$ are together but no two $$S$$ are together
let two C's be 1 unit
$$\therefore $$ no. of ways $$=\frac{6!}{4!}=30$$
We have to put 1 letter between one S
So, No of ways$$=2\times 3!=12$$
No. of ways=30-12=18
Question 6
1 / -0

Find the missing number :

A
$$125$$

B
$$90$$

C
$$105$$

D
$$225$$

Solution

$$\textbf{Step 1: Observe the numbers opposite to each other}$$
$$ \text{We can see that the number opposite to 315 is 21. Also, } \dfrac{315}{21}=15$$
$$\text{Hence, we can say the missing number has at least one factor of 15 }$$
$$\text{We see the missing number is opposite to 15}$$
$$\text{Also, } 15\times15=225$$
$$\textbf{Step 2: Verification}$$
$$\text{Let the missing number be x.}$$
$$\text{ATQ, }$$
$$\Rightarrow 21+15+x=261$$
$$\Rightarrow x=261-21-15$$
$$x=225$$
$$\text{Hence, it is verified that x=225}$$
$$\textbf{Thus, the missing number is D 225.}$$
Question 7
1 / -0

The value of $$^{47}C_{4}+\displaystyle \sum _{ j=1 }^{ 5 }\ ^{ \left( 52-j \right) } { C }_{ 3 }$$ is

A
$$^{47}C_{5}$$

B
$$^{52}C_{5}$$

C
$$^{52}C_{4}$$

D
$$^{52}C_{3}$$

Solution

We have,
$$\begin{array}{l} ^{ 47 }{ C_{ 4 } }{ +^{ 51 } }{ C_{ 3 } }{ +^{ 50 } }{ C_{ 3 } }{ +^{ 49 } }{ C_{ 3 } }{ +^{ 48 } }{ C_{ 3 } }{ +^{ 47 } }{ C_{ 3 } } \\ { =^{ n } }{ C_{ r } }{ +^{ n } }{ C_{ r-1 } }{ =^{ n+1 } }{ C_{ r } } \\ { =^{ 48 } }{ C_{ 4 } }{ +^{ 48 } }{ C_{ 3 } }{ +^{ 49 } }{ C_{ 3 } }{ +^{ 50 } }{ C_{ 3 } }{ +^{ 51 } }{ C_{ 3 } } \\ { =^{ 49 } }{ C_{ 4 } }{ +^{ 49 } }{ C_{ 3 } }{ +^{ 50 } }{ C_{ 3 } }{ +^{ 51 } }{ C_{ 3 } } \end{array}$$
Similarly,
$$=^{52}{C_4}$$.
Question 8
1 / -0

$$496 : 204 : : 329 : ?$$

A
$$90$$

B
$$110$$

C
$$115$$

D
$$135$$
Question 9
1 / -0

Find the missing number.

A
$$74$$

B
$$62$$

C
$$91$$

D
$$97$$

Solution

$$ \textbf{ Step 1: Observing the difference between the adjacent numbers}$$

$$ \text{If we notice the adjacent numbers, we see } 4\times 2 -1 =7$$

$$ \text{Similarly, } 7 \times 2-1=13$$

$$ \text{Similarly, } 13\times2 -1=25$$

$$ \text{Similarly, } 25\times2-1=49$$

$$ \textbf{Step 2: Calculating the missing number}$$

$$ \text{Thus, looking at the above observations, we can conclude the missing number will be:}$$

$$ \Rightarrow 49\times 2-1=97$$

$$\textbf{Thus, the missing number is D 97}$$
Question 10
1 / -0

A committee of $$4$$ persons is to be formed from $$2$$ ladies, $$2$$ old men and $$4$$ young men such that it includes at least $$1$$ lady. at least $$1$$ old man and at most $$2$$ young men. Then the total number of ways in which this committee can be formed is :

A
$$40$$

B
$$41$$

C
$$16$$

D
$$32$$

Solution