Cell Cycle and Cell Division Test

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Cell Cycle and Cell Division Test - 78

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Weekly Quiz Competition

Question 1
1 / -0

How many mitotic divisions are required to produce 128 cells from a single cell?

A
16

B
8

C
14

D
7
Solution
- In mitosis, each cell divides into two. So starting from a single cell, the increase in a number of cells will occur as per the following progression- 1->2->4->8->16->32->64->128.
- Thus a total of 7 divisions is required to produce 128 cells starting from a single cell or 2$$^n$$ times the division.
So, the correct answer is option D.
Question 2
1 / -0

In how many cells, the meiosis division has taken place if the total number of spermatids produced are 32?

A
16

B
8

C
4

D
5

E
32

Solution

In meiosis, each mother cell divides to produce 4 daughter cells. Thus 32 spermatids will be produced from 32/4, i.e., 8 spermatocytes. This calculation is based on the assumption that all the cell produced after meiosis are functional. This may not be the case always. For example, in the case of angiosperms, ovule develops from a single megaspore called functional megaspore and three megaspores of the four megaspores produced after meiosis in megaspore mother cell degenerate. In this case, each meiosis event gives rise to only one functional haploid egg cell.
So, the correct answer is option B.
Question 3
1 / -0

A series of changes or sequential events which occur regularly in a dividing cell is called ___________.

A
Cell division

B
Cell cycle

C
Karyokinesis

D
Kinesis
Solution
- Cell cycle is the series of events that occurs to a cell, at the end of which it converts into two daughter cells. It composed of Interphase, division phase (mitosis/meiosis), and cytokinesis.
- Cell division is the splitting of one cell into two daughter cells.
- Karyokinesis is the process of division of the nucleus.
- Kinesis is the movement or activity of a cell in response to some stimuli.
Thus, the correct answer is (B).
Question 4
1 / -0

Position of the same arm of chromosomes during metaphase of mitosis are

A
Towards the equator

B
Poleward

C
At any place in the spindle

D
Variable from plant to plant

Solution

At the metaphase stage, the chromosomes are arranged at the equator. The centromere is bound to the spindle fibers. The arms of chromosomes are oriented variably. However, after splitting of the centromere, when chromosomes move towards opposite poles, the arms of chromosomes are pointed away from the centriole and oriented towards the equator because the chromosomes are pulled by spindle fibers attached to the centromere.
So, the correct answer is option C.
Question 5
1 / -0

How many types of fibers are there in the nuclear spindle?

A
One

B
Two

C
Three

D
Four

Solution

There are four types of fibers in the nuclear spindle. The nuclear spindle is the fusiform figure which is a characteristic of a dividing cell, it consists of microtubules called spindle fibers, some of which become attached to each chromosome at its centromere and appear to be involved in chromosomal movement; other microtubules - continuous fibers pass from pole to pole. There are four types of fibers in the nuclear spindle-
(a) chromosomal fibres which runs from kinetochore to the pole of spindle,
(b) continuous fibres exists from pole to pole without attachment to chromosomes,
(c) interzonal fibres are formed in between centromeres of chromosomes of two poles and,
(d) Astral rays.
So, the correct answer is option D.
Question 6
1 / -0

An ovum of an animal has 2.5 pg of DNA in its nucleus. The amount of DNA at the end of G$$_2$$ phase will be

A
2.5 pg

B
5 pg

C
250 pg

D
10 pg
Solution
- An ovum is a haploid cell. It is having half the DNA content. It will fuse with sperm. The sperm is also a haploid cell having half the DNA content. When sperm fuses with the egg to form a zygote, the DNA content is restored to that in a normal diploid cell.
- Thus, if the ovum contained 2.5 picograms the zygote will contain 5.0 picograms of DNA. Now, this zygote shall pass through the first growth phase or G$$_1$$ phase and then synthesis or S phase.
- In the S phase, DNA will undergo replication and consequently DNA content will become double or 10.0 picograms.
So, the correct answer is option D.
Question 7
1 / -0

If during the initiation of meiosis there is 16 pg of DNA in a gametocyte. Then the amount of DNA present in the gamete will be

A
8 pg

B
16 pg

C
4 pg

D
32 pg

Solution

The typical cell cycle comprises of interphase and mitotic phase (M phase). The interphase is divided into first growth phase (G$$_1$$ phase), synthesis phase (S phase) and second growth phase (G$$_2$$ phase). The DNA replication occurs during synthesis or S phase. Thus, DNA amount doubles during S phase. Further, meiosis is the reductional division in which the chromosome number is reduced to one half. Thus, if a meiocyte (gametocyte) contains 16 picogram of DNA the haploid gametes produced after meiosis will contain 8 picogram of DNA and half the number of chromosomes as compared to the meiocyte (gametocyte).
Question 8
1 / -0

Brachymeiosis is characteristic of

A
Protista

B
Fungi

C
Higher plants

D
Only animals

Solution

Brachymeiosis is a different type of meiosis observed in some fungi. The method involves three type of divisions. The first and second division are reductional forms and the third division is of equational type. The second type of division is the characteristic of this method. The ascomycetes perform this type of meiotic division in the ascus to form the ascospores.
Thus, the correct answer is option B.
Question 9
1 / -0

Arrange these figures in ascending order of cell divisions.

A
C, D, A, B

B
B, A, D, C

C
A, B, C, D

D
B, D, A, C

Solution

The figures show various stages of meiotic first prophase. Prophase of first meiotic division comprises of following sub-stages- Leptotene, zygotene, pachytene, diplotene and diakinesis. Leptotene is the first substage which is characterised by the coiling of chromosomes. Zygotene is the second substage which is characterised by the pairing of homologous chromosome. Pachytene is the third substage, characterised by crossing-over event between non-sister chromatids of a homologous pair of chromosome. In diplotene stage, points at which crossing over had occurred are visible as X-shaped structures called as chiasma.
So, the correct answer is option D.
Question 10
1 / -0

During mitosis, nuclear membrane disappears at

A
Early prophase

B
Late prophase

C
Metaphase

D
Anaphase

Solution

During karyokinesis the nuclear membrane disappears. Nuclear membrane starts disappearing at the start of mitosis and by the late prophase it disappears completely along with the major cell organelles. The nuclear membrane disappears presumably to allow more space for karyokinesis and proper separation of chromatids.

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Cell Cycle and Cell Division Test - 78

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Cell Cycle and Cell Division Test - 78

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Question 1

16

8

14

7

Solution

Question 2

16

8

4

5

32

Solution

Question 3

Cell division

Cell cycle

Karyokinesis

Kinesis

Solution

Question 4

Towards the equator

Poleward

At any place in the spindle

Variable from plant to plant

Solution

Question 5

One

Two

Three

Four

Solution

Question 6

2.5 pg

5 pg

250 pg

10 pg

Solution

Question 7

8 pg

16 pg

4 pg

32 pg

Solution

Question 8

Protista

Fungi

Higher plants

Only animals

Solution

Question 9

C, D, A, B

B, A, D, C

A, B, C, D

B, D, A, C

Solution

Question 10

Early prophase

Late prophase

Metaphase

Anaphase

Solution

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