Photosynthesis in Higher Plants Test

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Photosynthesis in Higher Plants Test - 53

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Weekly Quiz Competition

Question 1
1 / -0

Presence of bundle sheath is characteristic of

A
$$C_4$$ plants

B
Xerophytic plant

C
Grass family

D
$$C_3$$ plants

Solution

A) $${ C }_{ 4 }$$ plants have bundle sheath cells and this is a characteristic feature.
B) Leaves in xerophytes are reduced or modified into spines or are absent.
C) Bulliform cells are a characteristic feature of the leaves of the grass family.
D) $${ C }_{ 3 }$$ plants have only mesophyll cells.
So the correct answer is '$${ C }_{ 4 }$$ plants'.
Question 2
1 / -0

Light reaction in stroma lamellae of chloroplast results in the production of

A
ATP

B
NADPH$$_2$$

C
ATP + NADPH$$_2$$

D
O$$_2$$

Solution

A) Along with ATP, $${ NADPH }_{ 2 }$$ is also produced.
B) Along with $${ NADPH }_{ 2 }$$, ATP is also produced.
C) The light reaction that takes place in the stroma lamellae is the non-cyclic phosphorylation and ATP and $${ NADPH }_{ 2 }$$ are the products.
D) Oxygen is also liberated during the light reaction but is not the main product.
So the correct answer is 'ATP + $${ NADPH }_{ 2 }$$'.
Question 3
1 / -0

In $$C_4$$ pathway, PEP carboxylase gains $$CO_2$$ from

A
Pyruvic acid

B
PEPA

C
OAA

D
Malic acid

Solution

A) Pyruvic acid does not release $${ CO }_{ 2 }$$.
B) Phosphoenol pyruvic acid (PEPA) is converted to OAA in the presence of PEP case.
C) OAA is converted to malate which releases $${ CO }_{ 2 }$$.
D) PEP carboxylase binds to $${ CO }_{ 2 }$$ to make oxaloacetic acid (OAA). OAA then makes malate. Malate enters bundle sheath cells and releases the $${ CO }_{ 2 }$$
Question 4
1 / -0

In $$C_4$$ pathway, RuBP accepts $$CO_2$$ inside

A
Xylem parenchyma

B
Phloem parenchyma

C
Mesophyll cells

D
Bundle sheath cells

Solution

A) Xylem parenchyma is not involved in photosynthesis.
B) Phloem parenchyma is not involved in photosynthesis.
C) Mesophyll cells are rich in PEP which accepts $${ CO }_{ 2 }$$ inside the mesophyll cells.
D) Bundle sheath cells are involved in the decarboxylation of $${ CO }_{ 2 }$$. They do not have PEP. $${ CO }_{ 2 }$$ is accepted in the mesophyll cells.
So the correct answer is 'Mesophyll cells'.
Question 5
1 / -0

Select the incorrect match for $$C_4$$ cycle.

A
Primary $$CO_2$$ fixation product- PGA

B
Site for initial carboxylation- mesophyll cells

C
Primary $$CO_2$$ acceptor- PEP

D
$$C_4$$ plant- maize

E
Location of RuBisCo- bundle sheath cells

Solution

A) The primary $${ CO }_{ 2 }$$ fixation product is a $${ C }_{ 4 }$$ acid.
B) Carboxylation first takes place in the mesophyll cells followed by Calvin's cycle in the bundle sheath cell.
C) The primary $${ CO }_{ 2 }$$ acceptor is PEP- Phosphoenol Pyruvate.
D) Maize, pineapple and sugar cane are $${ C }_{ 4 }$$ plants.
E) RuBisCo is present in the bundle sheath cells and takes part in Calvin's cycle.
So the correct option is 'Primary $${ CO }_{ 2 }$$ fixation product- PGA'.
Question 6
1 / -0

Which of the following is water soluble?

A
Phycobilin

B
Carotene

C
Xanthophyll

D
Chlorophyll

Solution

A) Phycobilin is red or blue photosynthetic pigment present red algae and cyanobacteria. They are proteins that are soluble in water.
B) Carotenoids are insoluble in water but are soluble in organic solvents.
C) Xanthophylls are insoluble in water.
D) Chlorophyll is insoluble in water.
So the correct answer is 'Phycobilin'.
Question 7
1 / -0

Identify the correct labeling of the given diagram.

A
a - PS II, b - PS I, c - $$e^-$$ acceptor, d - LHC

B
a - $$e^-$$ acceptor, b - LHC, c - PS II, d - PS I

C
a - LHC, b - $$e^-$$ acceptor, c - PS I, d - PS II

D
a - PS I, b - PS II, c - $$e^-$$ acceptor, d - LHC.

Solution

A) 'a' corresponds to PS II, 'b' corresponds to PS I, 'c' is an $${ e }^{ - }$$ acceptor and 'd' is the LHC of PS II.
B) 'a' is PS II and 'b' is PS I.
C) 'c' is an $${ e }^{ - }$$ acceptor and 'd' is the LHC of PS II.
D) 'a' corresponds to PS II and 'b' corresponds to PS I.
So the correct answer is 'a - PS II, b - PS I, c - $${ e }^{ - }$$ acceptor, d - LHC'.
Question 8
1 / -0

The first product of $$C_4$$ pathway is

A
OAA

B
PGA

C
PGAL

D
DHAP.

Solution

A) OAA - Oxalo Acetic Acid is the first product of the $${ C }_{ 4 }$$ pathway.
B) PGA is the first product of the $${ C }_{ 3 }$$ pathway.
C) PGA molecules are converted into PGAL by using ATP and NADPH from the light dependent reaction.
D) Dihydroxyacetone phosphate (DHAP) is the anion that is involved in many metabolic pathways, including the Calvin cycle in plants and glycolysis. It is the phosphate ester of dihydroxyacetone.
So the correct answer is 'OAA'.
Question 9
1 / -0

Choose the correct combination of labelling 1-5

A
1. Mesophyll cell. 2. Bundle sheath cell. 3. Regeneration. 4 Fixation. 5. Decarboxylation

B
1. Bundle sheath cell 2. Mesophyll cell. 3. Fixation 4. Regeneration 5. Decarboxylation

C
1. Mesophyll cell 2. Bundle sheath cell 3. Decarboxylation 4. Fixation 5. Regeneration

D
1. Mesophyll cell 2. Bundle sheath cell 3. Fixation 4. Regeneration 5. Decarboxylation

Solution

A) 1 corresponds to the mesophyll cell and 2 corresponds to the bundle sheath cell. But 3 corresponds to fixation of carbon dioxide to form a $${ C }_{ 4 }$$ acid.
B) 4 corresponds to the regeneration of PEP.
C) 5 corresponds to the decarboxylation of the $${ C }_{ 4 }$$ acid in Calvin's cycle.
D) 1 corresponds to the mesophyll cell, 2 corresponds to the bundle sheath cell, 3 corresponds to fixation of carbon dioxide, 4 corresponds to the regeneration of PEP and 5 corresponds to decarboxylation.
So the correct answer is '1. Mesophyll cell 2. Bundle sheath cell 3. Fixation 4. Regeneration 5. Decarboxylation'.
Question 10
1 / -0

Photooxidation of water results in the formation of

A
H$$^+$$, O$$_2$$, ATP

B
H$$^+$$, O$$_2$$, e$$^-$$, ATP

C
H$$^+$$, O$$_2$$, e$$^-$$

D
None of the above

Solution

A) One electron is released per molecule of water that is split. ATP is not released.
B) ATP is not released as a byproduct of the splitting of water.
C) Photooxidation or photolysis of water occurs in the LHC of PS II where water is split by light to liberate $${ H }^{ + },{ O }_{ 2 },{ e }^{ - }$$.
D) Water splits to liberate $${ H }^{ + },{ O }_{ 2 }, { e }^{ - }$$
So the correct answer is '$${ H }^{ + },{ O }_{ 2 },{ e }^{ - }$$'.

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Photosynthesis in Higher Plants Test - 53

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Photosynthesis in Higher Plants Test - 53

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SHARING IS CARING

Question 1

$$C_4$$ plants

Xerophytic plant

Grass family

$$C_3$$ plants

Solution

Question 2

ATP

NADPH$$_2$$

ATP + NADPH$$_2$$

O$$_2$$

Solution

Question 3

Pyruvic acid

PEPA

OAA

Malic acid

Solution

Question 4

Xylem parenchyma

Phloem parenchyma

Mesophyll cells

Bundle sheath cells

Solution

Question 5

Primary $$CO_2$$ fixation product- PGA

Site for initial carboxylation- mesophyll cells

Primary $$CO_2$$ acceptor- PEP

$$C_4$$ plant- maize

Location of RuBisCo- bundle sheath cells

Solution

Question 6

Phycobilin

Carotene

Xanthophyll

Chlorophyll

Solution

Question 7

a - PS II, b - PS I, c - $$e^-$$ acceptor, d - LHC

a - $$e^-$$ acceptor, b - LHC, c - PS II, d - PS I

a - LHC, b - $$e^-$$ acceptor, c - PS I, d - PS II

a - PS I, b - PS II, c - $$e^-$$ acceptor, d - LHC.

Solution

Question 8

OAA

PGA

PGAL

DHAP.

Solution

Question 9

1. Mesophyll cell. 2. Bundle sheath cell. 3. Regeneration. 4 Fixation. 5. Decarboxylation

1. Bundle sheath cell 2. Mesophyll cell. 3. Fixation 4. Regeneration 5. Decarboxylation

1. Mesophyll cell 2. Bundle sheath cell 3. Decarboxylation 4. Fixation 5. Regeneration

1. Mesophyll cell 2. Bundle sheath cell 3. Fixation 4. Regeneration 5. Decarboxylation

Solution

Question 10

H$$^+$$, O$$_2$$, ATP

H$$^+$$, O$$_2$$, e$$^-$$, ATP

H$$^+$$, O$$_2$$, e$$^-$$

None of the above

Solution

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