Respiration in Plants Test

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Respiration in Plants Test - 19

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Weekly Quiz Competition

Question 1
1 / -0

Which molecule listed below is a product of fermentation of glucose by yeast?

A
$$C_{6}H_{10}O_{5}$$

B
$$C_{2}H_{5}OH$$

C
$$C_{6}H_{12}O_{6}$$

D
$$CH_{3}OH$$

Solution

Beer and wine are produced by fermenting glucose with yeast. Yeast contains enzymes, that catalyze the breakdown of glucose to ethanol and carbon dioxide.
Question 2
1 / -0

During fermentation alcohol is formed from

A
Sugar

B
Protein

C
Carbon dioxide and water

D
None of the above

Solution

Fermentation is an energy releasing process in which substrate like sugar is oxidized into alcohol. It is an anaerobic process. It occurs in yeasts, some bacteria and muscle cells. Under anaerobic conditions, pyruvic acid is either converted ethanol in alcohol fermentation. During alcohol fermentation, pyruvic acid is first converted to acetaldehyde in presence of enzyme pyruvate decarboxylase. The acetaldehyde is then converted into ethyl alcohol by enzyme alcohol dehydrogenase.
Thus, the correct answer is option A.
Question 3
1 / -0

Fermentation refers to

A
Anaerobic respiration

B
Incomplete oxidation of carbohydrate

C
Complete oxidation of carbohydrate

D
Both A and B

Solution

The process of respiration can be aerobic or anaerobic. The process of anaerobic respiration is also called fermentation. Fermentation is a form of anaerobic respiration in which carbohydrates are incompletely oxidised to either ethanol and carbon dioxide as in yeast or lactic acid as in the muscles of higher vertebrates.
Question 4
1 / -0

Organism which can respire in absence of $$O_{2}$$ is

A
Chlorella

B
Solanum

C
Saccharum

D
Saccharomyces

Solution

Saccharomyces are facultative anaerobes. They make ATP by aerobic respiration if oxygen is present, but is capable of switching to fermentation or anaerobic respiration if oxygen is absent.
Question 5
1 / -0

For complete phosphorylation of a glucose molecule, how many ATP molecules are required?

A
4

B
2

C
6

D
8

Solution

For complete phosphorylation of a glucose molecule, 2 ATP molecules are required. Two molecules of ATP are consumed in glycolysis during phosphorylation of glucose to fructose 1,6-diphosphate.
Question 6
1 / -0

Decarboxylation is not involved in

A
Pyruvic acid to acetyl-CoA

B
Glycolysis

C
Krebs cycle

D
Alcoholic fermentation

Solution

The end product of glycolysis, pyruvic acid is converted to acetyl-CoA by the process of oxidative decarboxylation in presence of pyruvate dehydrogenase enzyme. During alcoholic fermentation, pyruvic acid is first converted to acetaldehyde in presence of enzyme pyruvate decarboxylase. The acetaldehyde is then converted into ethyl alcohol by enzyme dehydrogenase. During Krebs cycle, oxalosuccinate undergoes decarboxylation in the presence of oxalosuccinate decarboxylase to form alpha-ketoglutarate.Thus decarboxylation occurs after glycolysis and is not a part of glycolysis.
Thus, the correct answer is option B.
Question 7
1 / -0

Continuous addition of sugars in fed batch fermentation is done to

A
Degrade sewage

B
Produce methane

C
Obtain antibiotics

D
Purify enzymes
Solution
Correct Option: D

Explanation:
- Fed-batch fermentation is a microbiological operation in which one or more substrates (such as sugar/nutrients) are fed or supplied to the bioreactor during the growth phase, and the product remains in the bioreactor until the end of the reaction.
- The fed-batch method is used to purify enzymes by adding nutrients/sugar to the mechanism on a regular basis.
Hence Continuous addition of sugars in fed-batch fermentation is done to purify enzymes.
Question 8
1 / -0

Which one is correct sequence in glycolysis?

A
G 6-P$$\rightarrow $$ PEP$$\rightarrow $$3-PGAL$$\rightarrow $$3-PGA

B
G 6-P$$\rightarrow $$ 3-PGAL$$\rightarrow $$3-PGA$$\rightarrow $$3-PEP

C
G 6-P$$\rightarrow $$ PEP$$\rightarrow $$3-PGA$$\rightarrow $$3-PGAL

D
G 6-P$$\rightarrow $$ 3-PGA$$\rightarrow $$3-PGAL$$\rightarrow $$3-PEP
Solution
Glycolysis is the partial oxidation process of glucose into two molecules of pyruvic acid.
Glucose will break down into two molecules of pyruvic acid while 3-PGAL ( Glyceraldehyde 3- Phosphate ), 3- PGA ( 3- Phosphoglycerate ) and phosphoenolpyruvate are the intermediates.
The correct answer is ' G 6-P→ 3-PGAL→3-PGA→3-PEP'.
Question 9
1 / -0

In which of the following reaction of glycolysis, a molecule of water is removed from the substrate?

A
Fructose-6-phosphate$$\rightarrow $$fructose 1,6-bisphosphate

B
3-Phosphate glyceraldehyde$$\rightarrow $$1,3-bisphosphoglyceric acid

C
PEP$$\rightarrow $$ pyruvic acid

D
2-Phosphoglycerate$$\rightarrow $$ PEP

E
Glucose$$\rightarrow $$glucose6-phosphate

Solution

During the formation of phosphoenol pyruvate (PEP) from 2-phosphoglycerate, a water molecule is eliminated. This reaction is catalysed by the enzyme enolase. This is a step of glycolysis. This reaction takes place in the cytoplasm.
Thus, the correct answer is option D.
Question 10
1 / -0

Conversion of fructose-6-phosphate to fructose 1,6-diphosphate is catalysed by

A
Phosphofructose kinase

B
Aldolase

C
Hexokinase

D
None of the above

Solution

Fructose 6-phosphate is converted to fructose 1,6-diphosphate catalyzed by phosphofructose kinase, along with the consumption of an ATP molecule.

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Respiration in Plants Test - 19

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Respiration in Plants Test - 19

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Question 1

$$C_{6}H_{10}O_{5}$$

$$C_{2}H_{5}OH$$

$$C_{6}H_{12}O_{6}$$

$$CH_{3}OH$$

Solution

Question 2

Sugar

Protein

Carbon dioxide and water

None of the above

Solution

Question 3

Anaerobic respiration

Incomplete oxidation of carbohydrate

Complete oxidation of carbohydrate

Both A and B

Solution

Question 4

Chlorella

Solanum

Saccharum

Saccharomyces

Solution

Question 5

4

2

6

8

Solution

Question 6

Pyruvic acid to acetyl-CoA

Glycolysis

Krebs cycle

Alcoholic fermentation

Solution

Question 7

Degrade sewage

Produce methane

Obtain antibiotics

Purify enzymes

Solution

Question 8

G 6-P$$\rightarrow $$ PEP$$\rightarrow $$3-PGAL$$\rightarrow $$3-PGA

G 6-P$$\rightarrow $$ 3-PGAL$$\rightarrow $$3-PGA$$\rightarrow $$3-PEP

G 6-P$$\rightarrow $$ PEP$$\rightarrow $$3-PGA$$\rightarrow $$3-PGAL

G 6-P$$\rightarrow $$ 3-PGA$$\rightarrow $$3-PGAL$$\rightarrow $$3-PEP

Solution

Question 9

Fructose-6-phosphate$$\rightarrow $$fructose 1,6-bisphosphate

3-Phosphate glyceraldehyde$$\rightarrow $$1,3-bisphosphoglyceric acid

PEP$$\rightarrow $$ pyruvic acid

2-Phosphoglycerate$$\rightarrow $$ PEP

Glucose$$\rightarrow $$glucose6-phosphate

Solution

Question 10

Phosphofructose kinase

Aldolase

Hexokinase

None of the above

Solution

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