Respiration in Plants Test

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Respiration in Plants Test - 20

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Weekly Quiz Competition

Question 1
1 / -0

First step in respiration is

A
Aerobic oxidation of pyruvic acid

B
Liberation of $$CO_{2}$$

C
Glycolysis

D
Electron transport system

Solution

Glycolysis is the first stage in respiration. Glycolysis is the metabolic pathway that converts glucose into pyruvate. The free energy released in this process is used to form the high-energy compounds ATP and NADH.
So, the correct answer is 'Glycolysis'
Question 2
1 / -0

In glycolysis, during oxidation electrons are removed by

A
NAD$$^{+}$$

B
Molecular oxygen

C
ATP

D
Glyceraldehyde-3-phosphate

Solution

Correct Option: A

Explanation:

During glycolysis, electrons are extracted by NAD+ during the oxidation of glyceraldehyde 3-phosphate to 1, 3-bisphosphoglycerate, which generates NADH + H+.

Hence, NAD+ removes electrons in glycolysis.
Question 3
1 / -0

Which of the following is formed in presence of pyruvate kinase?

A
Phosphoenol pyruvic acid

B
Pyruvic acid

C
Both (A) and (B)

D
Acetyl CoA

Solution

Pyruvate kinase is an enzyme involved in glycolysis. It catalyzes the transfer of a phosphate group from phosphoenolpyruvate to ADP, yielding one molecule of pyruvate and one molecule of ATP.
Question 4
1 / -0

What is the other name of glycolysis?

A
EMP pathway

B
TCA pathway

C
HMS pathway

D
None of the above

Solution

Glycolysis is also called as EMP pathway. It is after the name of the discoverers - Embden, Meyerhof and Parnas.
Question 5
1 / -0

Besides the net gain of 2 ATP molecules in glycolysis which other molecules are simultaneously formed?

A
$$FADH_{2}$$

B
$$NADPH_{2}$$

C
$$NADH_{2}$$

D
$$FAMH_{2}$$

Solution

In glycolysis, there is a net gain of 2 ATP molecules. Glycolysis is the metabolic pathway that converts glucose into pyruvate. The free energy released in this process is used to form the high-energy compounds ATP and NADH$$_2$$. NADH$$_2$$ is formed during the synthesis of 1,3-bisphosphoglycerate from the glyceraldehyde-3-phosphate.
So, the correct answer is option C.
Question 6
1 / -0

Which of the following involves the loss of two protons and two electrons?

A
Deamination

B
Dehydrogenation

C
Carboxylation

D
None of the above
Solution
Correct option B

Explanation for the correct option:
- Dehydrogenation is a chemical reaction in which hydrogen from a molecule is removed.
- It is the reversal of the hydrogenation process.
- Two protons and two electrons are lost in the process.
Question 7
1 / -0

In last step of glycolysis the

A
Protein is converted to glucose

B
Glucose is converted into glucose

C
Starch is converted into glucose

D
Glucose is converted into pyruvic acid

Solution

Glycolysis is the metabolic pathway, that converts glucose into pyruvate. The free energy released in this process is used to form the high-energy compounds ATP and $$NADH_2$$. From one hexose sugar two molecules of pyruvic acid is produced through the glycolysis.
Question 8
1 / -0

Which of the following is the product of phosphorylation?

A
PGA

B
Fructose 1,6-diphosphate

C
DPGA

D
Pyruvic acid

Solution

Fructose 1,6-bisphosphate (fructose 1,6-diphosphate) is formed as a result of phosphorylation of fructose-6-phosphate. It is a product of glycolysis. This step occurs in presence of phosphofructokinase.
So, the correct answer is option B.
Question 9
1 / -0

Pyruvate (pyruvic acid) dehydrogenase is used in converting

A
Pyruvate to glucose

B
Glucose to pyruvate

C
Pyruvic acid to lactic acid

D
Pyruvate to acetyl CoA

Solution

The pyruvic acid generated in the glycolysis enters into the mitochondrial matrix, undergoes oxidative decarboxylation and forms active acetate in a coordinated series of reactions catalysed by the multienzyme complex. The reaction takes place in the presence of enzyme pyruvate dehydrogenase and several coenzymes including $$NAD^+$$, coenzyme A, thiamine pyrophosphate and lipoic acid. The reaction occurs in 4 steps involving the conversion of pyruvic acid to acetyl coenzyme A. One molecule of carbon dioxide is released. The coenzyme $$NAD^+$$ is reduced to $$NADH + H^+$$ in the reaction.
Thus, the correct answer is option D.
Question 10
1 / -0

During respiration, pyruvic acid is formed by

A
Glycolysis

B
Krebs cycle

C
HMP pathway

D
None of the above

Solution

Glycolysis is the metabolic pathway that converts glucose into pyruvate. The free enrgy released in this process is used to form the high-energy compounds ATP and $$NADH_2$$.

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Respiration in Plants Test - 20

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Respiration in Plants Test - 20

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SHARING IS CARING

Question 1

Aerobic oxidation of pyruvic acid

Liberation of $$CO_{2}$$

Glycolysis

Electron transport system

Solution

Question 2

NAD$$^{+}$$

Molecular oxygen

ATP

Glyceraldehyde-3-phosphate

Solution

Question 3

Phosphoenol pyruvic acid

Pyruvic acid

Both (A) and (B)

Acetyl CoA

Solution

Question 4

EMP pathway

TCA pathway

HMS pathway

None of the above

Solution

Question 5

$$FADH_{2}$$

$$NADPH_{2}$$

$$NADH_{2}$$

$$FAMH_{2}$$

Solution

Question 6

Deamination

Dehydrogenation

Carboxylation

None of the above

Solution

Question 7

Protein is converted to glucose

Glucose is converted into glucose

Starch is converted into glucose

Glucose is converted into pyruvic acid

Solution

Question 8

PGA

Fructose 1,6-diphosphate

DPGA

Pyruvic acid

Solution

Question 9

Pyruvate to glucose

Glucose to pyruvate

Pyruvic acid to lactic acid

Pyruvate to acetyl CoA

Solution

Question 10

Glycolysis

Krebs cycle

HMP pathway

None of the above

Solution

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