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Respiration in Plants Test - 29

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Respiration in Plants Test - 29
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Weekly Quiz Competition
  • Question 1
    1 / -0
    The end product of fermentation of sugars by Lactobacillus bacteria is
    Solution
    The chemical breakdown of glucose in the absence of oxygen is called as fermentation. This process is also called anaerobic respiration. In this conversion, the intermediate produced is pyruvate followed by oxidation of NADH and formation of lactic acid. The bacterium Lactobacillus is used for the commercial production of lactic acid. Thus the correct answer is option A.

  • Question 2
    1 / -0
    How many electrons are involved for the formation of 1 mole of glucose and  6$$O_{2}$$ molecules?
    Solution
    • During light reactions, 4e- will be released.
    2H$$_{2}$$O 4H+ + 4e- + O$$_{2}$$
    • During dark reactions, 8e- will be released.
    • All together 12 electrons are involved for the formation of 1 mole of glucose and 6 O$$_{2}$$ molecules.

    Thus, option B is correct.
  • Question 3
    1 / -0
    Kreb's cycle starts with the formation of a six carbon compound by the reaction between
    Solution
    The Krebs cycle (or citric acid cycle) is part of cellular respiration. it is a series of chemical reactions used by all aerobic organisms to generate energy. Krebs cycle starts with the formation of a six carbon compound by the reaction between oxaloacetic acid and acetyl CoA. The 6 carbon compound formed is citric acid and this reaction is catalyzed by citrate synthase. 

  • Question 4
    1 / -0
    Fermentation is carried out by
    Solution
    Fermentation is incomplete oxidation of food substances into alcohol and lactic acid with the small amount of energy being released. Both lactic acid and ethanol fermentation do not produce oxygen. It is carried out by anaerobic bacteria and fungi. Aerobic bacteria and fungi carry out aerobic respiration. Thus, the correct answer is option C.  
  • Question 5
    1 / -0
    Which of the following sequence is correct in Krebs cycle?
    Solution
    Fumarate, malate or oxaloacetate are the intermediates of Krebs cycle, where succinate gets converted to fumarate, fumarate gets converted to malate and malate gets converted to oxaloacetate. So, the correct sequence in Krebs cycle is fumarate - malate - oxaloacetic acid.
    Thus, the correct answer is option C. 

  • Question 6
    1 / -0
    In CAM the R.Q  will be 
    Solution
    CAM plants open their stomata only at night and absorbs $$CO_2$$, which then converted into malate by acidification. During night time oxygen is absorbed continuously but no $$CO_2$$ is evolved. There fore R.Q in night is zero. During day time, malate gets converted to $$CO_2$$ and $$C_3$$ photosynthesis occurs. During day time amount of $$CO_2$$ evolved is equal to the amount of $$O_2$$ absorbed. So, R.Q at day time is 1. So, in CAM plants, R.Q will be zero at night. Thus, option A is correct and other options are incorrect.
  • Question 7
    1 / -0
    Which of the metabolites is common to respiration mediated breakdown of fats and carbohydrates?
    Solution
    Acetyl-CoA is an important molecule in metabolism, used in many biochemical reactions. It is produced by pyruvate by under the influence of enzyme pyruvate dehydrogenase. It also plays a major role in beta-oxidation of fatty acid.
    So, the correct answer is option C.
  • Question 8
    1 / -0
    Before combining with the oxaloacetic acid of citric acid cycle the  pyruvic acid changes into
    Solution
    Pyruvic acid is the end product of glycolysis, which occurs in the cytoplasm of the cell. Pyruvic acid before combining with the oxaloacetic acid of citric acid cycle changes into acetyl CoA, which is a 2 carbon compound. This reaction is catalysed by pyruvate dehydrogenase. 

  • Question 9
    1 / -0
    Mineral activator needed for the enzyme aconitase of Kreb's cycle is 
    Solution
    Mineral activator needed for the enzyme aconitase of Krebs cycle is iron (Fe). Fe catalyses the interconversion of citrate and isocitrate, via a cis-aconitate intermediate, functioning in both the tricarboxylic acid (TCA) and glyoxylate cycles
  • Question 10
    1 / -0
    If man consumes only carbohydrate, the R.Q. will be
    Solution
    The respiratory quotient (R.Q) is the ratio of $$CO_2$$ produced to $$O_2$$ consumed, while food is being metabolized.
    RQ = $$CO_2$$ eliminated / $$O_2$$ consumed.
    The respiratory quotient for carbohydrate metabolism can be demonstrated by the chemical equation for oxidation of glucose.
    $$C_6H_{12}O_6$$ + 6 $$O_2$$-----> 6 $$CO_2$$+ 6 $$H_2O$$
    Because the gas exchange in this reaction is equal, the respiratory quotient for carbohydrates is: RQ = 6 $$CO_2$$ / 6 $$O_2$$ = 1. So, if man consumes only carbohydrate the R.Q. for such substance will be 1. 
    So, the correct answer is option A.
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