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Respiration in Plants Test - 41

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Respiration in Plants Test - 41
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  • Question 1
    1 / -0
    Enzymes of the electron transport system are present in
    Solution
    The process of aerobic respiration is accomplished in four stages. The site of occurrence of these stages is-
    Glycolysis- cell cytoplasm
    Oxidative decarboxylation of pyruvic acid- mitochondrial matrix.
    Krebs cycle- mitochondrial matrix.
    Oxidative phosphorylation- electron carriers and ATP synthase enzyme complex in the inner mitochondrial membrane.
  • Question 2
    1 / -0
    Which of the following connects glycolysis to Krebs cycle?
    Solution
    Glycolysis breaks one molecule of glucose into two molecules of pyruvic acid in the cytoplasm. The pyruvic acid is decarboxylated to acetyl CoA. The acetyl CoA is metabolised in Krebs cycle. Thus, acetyl CoA forms the connecting link between glycolysis and Krebs cycle.
  • Question 3
    1 / -0
    Which of the following accepts terminal electron during aerobic respiration?
    Solution
    Although the aerobic process of respiration takes place only in the presence of oxygen, the role of oxygen is limited to the terminal stage of the process. Yet, the presence of oxygen is vital, since it drives the whole process by removing hydrogen from the system. Oxygen acts as the final electron acceptor. It accepts electrons from cytochrome $$a$$-$$a_3$$ and forms water molecule.
  • Question 4
    1 / -0
    The enzyme of yeast which converts glucose into ethyl alcohol is called as
    Solution
    Zymase is an enzyme complex that catalyzes the fermentation of sugar into ethanol and carbon dioxide. It occurs naturally in yeasts. Zymase activity varies among yeast strains. Fermentation is a form of anaerobic respiration in which carbohydrates are incompletely oxidised to either ethanol and carbon dioxide as in yeast or lactic acid as in the muscles of higher vertebrates.
    Therefore, the correct answer is option C.
  • Question 5
    1 / -0
    $$FADH_2$$ is produced in Krebs cycle during the conversion of 
    Solution
    The reactions which help in converting pyruvic acid to carbon dioxide and water in mitochondria are called the Krebs cycle. $$FADH_2$$ is produced in Kreb's cycle during the conversion of succinic acid (succinate) to fumaric acid (fumarate) in the presence of enzyme succinate dehydrogenase.
    So, the correct answer is option C. 
  • Question 6
    1 / -0
    Glycolysis is the conversion of
  • Question 7
    1 / -0
    How many ATPs are directly formed during glycolysis cycle of by 6 molecule of glucose?
    Solution
    During glycolysis four ATP molecules are produced by direct substrate level phosphorylation two ATP molecules are formed  when 1,3 bisphosphoglyceric acid is converted to 3 phosphoglyceric acid catalyzed by the enzyme phosphoglycerate kinase and two when phosphoenol pyruvic acid is converted to pyruvic acid by the enzyme pyruvate kinase. 
  • Question 8
    1 / -0
    How many ATP molecules are released when 1 molecule of glucose is oxidised in our liver cells?
    Solution
    The process of aerobic respiration of glucose can be considered in four stages. 
    (1) First stage is glycolysis. Net gain of ATP is 2 molecules. Also there is synthesis of 2 molecules of reduced coenzymes NADH2NADH2. Each  NADH2NADH2 gives 3 ATP during oxidative phosphorylation. Thus the total gain in glycolysis is 8 ATP molecules.
    (2) Second stage is oxidative decarboxylation of pyruvic acid to release acetyl CoA. During this reaction one molecule of reduced coenzyme NADH2NADH2 is produced. As two molecules of pyruvic acid get oxidatively decarboxylated to two molecules of acetyl CoA, there is net synthesis of two molecules of reduced coenzyme NADH2NADH2 or an equivalent of 6 ATP molecules.
    (3) Third stage is Krebs cycle. During each turn of Krebs cycle, there is synthesis of of 3 molecules of reduced coenzyme NADH2NADH2, 1 molecule of reduced coenzyme FADH2FADH2 and 1 molecule of GTP by substrate level phosphorylation. As each FADH2FADH2 gives 2 molecules of ATP in oxidative phosphorylation and each molecule of NADH2NADH2 gives 3 molecules of ATP, the net gain of ATP in one turn of Krebs cycle is 12. During aerobic respiration of one molecule of glucose, the Krebs cycle turns twice, thus there is net synthesis of 24 ATP.
    (4) The last step is mitochondrial electron system, which oxidises the reduced coenzymes NADH2NADH2 and FADH2FADH2and produces ATP by oxidative phosphorylation. 
    Thus, the total gain of ATP in steps 1, 2, and 3 is 8 + 6 +24 i.e., 38 ATP molecules.
  • Question 9
    1 / -0
    A respiratory cycle where $$NADH_{2}$$ is produced is the
    Solution
    Krebs cycle forms the second step in respiration where $$NADH_2$$ and $$FADH_2$$ are produced.  It is a cyclic chain of reactions that starts and ends with oxaloacetate. 

  • Question 10
    1 / -0
    Fermentation is an
    Solution
    The process of respiration can be aerobic or anaerobic. The process of anaerobic respiration is also called as fermentation. Fermentation is a form of anaerobic respiration in which carbohydrates are incompletely oxidised to either ethanol and carbon dioxide as in yeast or lactic acid, as in the muscles of higher vertebrates.
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