Respiration in Plants Test

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Respiration in Plants Test - 50

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Weekly Quiz Competition

Question 1
1 / -0

The number of ATP produced when a molecule of glucose undergoes fermentation is?

A
$$4$$

B
$$36$$

C
$$2$$

D
$$38$$
Solution
- The chemical breakdown of glucose in the absence of oxygen is called as fermentation. This process is also called anaerobic respiration.
- In this reaction, 2 moles of $$ATP$$ along with 2 molecules of $$NADH$$ are generated during the conversion of glucose to pyruvate.
- This pyruvate is then converted into lactic acid at the expenditure of 2 molecules of $$NADH$$. So the net gain is $$2$$ $$ATP$$ molecules.
Thus the correct answer is option C.
Question 2
1 / -0

Which one of the following reactions is an example of oxidative decarboxylation?

A
Conversion of succinate to fumarate.

B
Conversion of fumarate to malate.

C
Conversion of pyruvate to acetyl Co-A.

D
Conversion of citrate to isocitrate.

Solution

The conversion of pyruvate to acetyl-CoA is a linker step between glycolysis and Krebs cycle. After the entry of pyruvate in the mitochondria the acetylation takes place in the perimitochondrial space which is the space between the inner and outer mitochondrial membrane. Each molecule of pyruvic acid is oxidatively decarboxylated to acetyl coA by the action of an enzyme complex pyruvate dehydrogenase. The acetyl coA then enters the Krebs cycle. Thus the correct answer is option C.
Question 3
1 / -0

In members of family Crassulaceae, .......... is regenerated from starch during night.

A
Phosphoenol pyruvic acid

B
Pyruvic acid

C
Malic acid

D
Oxaloacetic acid

Solution

Crassulaceae is a CAM (Crassulacean Acid Metabolism) plant. CAM plants are the succulent plants which grow in deserts and are exposed to high temperatures. In these plants, stomata open during the night and close during the day time. At night, CAM plants open their stomata, allowing carbon dioxide to diffuse into the leaves. This carbon dioxide is fixed into oxaloacetate by the enzyme PEP carboxylase that is converted to malate or other organic acids During day time the organic acids are broken down to release carbon dioxide which enters Calvin cycle. Thus the correct answer is option A.
Question 4
1 / -0

When 100% carbon is oxidized to CO$$_2$$, the efficiency of such respiration is

A
40%

B
60%

C
90%

D
100%

Solution

Oxidation of carbon to CO$$_2$$ takes place in aerobic respiration.
The amount of energy released by complete oxidation of 1 mol of glucose = 686 kcal
No. of ATPs produced during respiration = 36
Energy required to produce 1 mol ATP = 7.6 kcal
Total energy used to produce ATPs = 7.6 x 36 = 273.6 kcal
Percentage of total energy conserved = (273.6 / 686) x 100 = 39.88 %
Hence, Efficiency of aerobic respiration is 39.88% i.e. 40%
So, the answer is A.
Question 5
1 / -0

Enzyme taking part in converting dihydroxyacetone phosphate to glyceraldehyde phosphate belongs to the class of

A
Isomerases

B
Hydrolases

C
Ligases

D
Transferases

Solution

Enzyme catalyzing optical or geometrical rearrangement of atomic groups without altering molecular weight or number of atoms is isomerase. It converts one isomer to the other isomer by changing the intramolecular arrangement by forming or breaking the bond. For example, dihydroxyacetone phosphate and glyceraldehyde phosphate both are three carbon compound and DHAP gets isomerized to glyceraldehyde phosphate by enzyme triose phosphate isomerase.
So, the correct answer is option A.
Question 6
1 / -0

Which is false regarding EMP pathways?

A
End product is $$CO_2$$ and $$H_2O$$

B
Substrate level phosphorylation

C
Production of ATP

D
Expenditure of ATP

Solution

Glycolysis process is also known as EMP pathway. The process does not require $$O_2$$ and takes place in the cytoplasm. During the whole process of glycolysis, one molecule of glucose (6C) is converted into two pyruvic acid molecule (3C), two ATP are used and 4ATP are evolved. In this process, substrate level phosphorylation is also taken place.
Question 7
1 / -0

For undergoing glycolysis, glucose requires priming with the help of how many ATP?

A
1

B
2

C
3

D
4

Solution

The mechanism of respiration is initiated by breaking down glucose to pyruvic acid without the help of oxygen. The initial process occurs in the cytosol of cells which requires glucose as well as ATP molecules which provide energy for the process to start. This initial process is known as glycolysis and it takes place in 10 steps in which total 4 ATP molecules are produced and 2 ATP molecules are consumed. These 2 ATP molecules are required for the initiation of the process. 4 ATP molecules are produced in the sixth and ninth step of glycolysis while 2 ATP molecules are consumed in the first and third step of glycolysis. Thus, there is the net production of 2 ATP molecules.
Thus, the correct answer is option B.
Question 8
1 / -0

Which one yields the highest energy per gram

A
Carbohydrate

B
Protein

C
Fat

D
Amino acids

Solution

Our food contains three main constituents: carbohydrates, fats and proteins. The amount of energy released when one gram of any of these food elements is burned is known as calorific value. Thus calorific value of food indicates as to how much is the energy value of food which the human body can gain through metabolism. It is usually given in kcal/gm. Fats form the most concentrated source of energy in our diet. 1 gram of fat yields 9.5 kcal of energy which is the highest among the food components. 1 gram of carbohydrates and proteins yield almost similar amount of energy which is equal to 4 kcal.
Thus, the correct answer is option C.
Question 9
1 / -0

FAD acts as an $$e^-$$ acceptor in between

A
Fumaric and malic acid

B
Succinic and fumaric acid

C
Malic and oxaloacetic acid

D
Citric and isocitric acid

Solution

Succinate changes to fumarate in the citric acid cycle. The succinate is a four carbon molecule which is oxidized, to fumarate. In this reaction, two hydrogen atoms with their electrons are transferred to FAD and converts into FADH$$_2$$ in presence of enzyme succinate dehydrogenase.
So, the correct answer is option B.
Question 10
1 / -0

Series of reactions which can convert fatty acids to sugars in plants but not in animals is

A
Krebs cycle

B
Glyoxylate cycle

C
Ornithine cycle

D
Glycolysis.

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Respiration in Plants Test - 50

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Respiration in Plants Test - 50

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Question 1

$$4$$

$$36$$

$$2$$

$$38$$

Solution

Question 2

Conversion of succinate to fumarate.

Conversion of fumarate to malate.

Conversion of pyruvate to acetyl Co-A.

Conversion of citrate to isocitrate.

Solution

Question 3

Phosphoenol pyruvic acid

Pyruvic acid

Malic acid

Oxaloacetic acid

Solution

Question 4

40%

60%

90%

100%

Solution

Question 5

Isomerases

Hydrolases

Ligases

Transferases

Solution

Question 6

End product is $$CO_2$$ and $$H_2O$$

Substrate level phosphorylation

Production of ATP

Expenditure of ATP

Solution

Question 7

1

2

3

4

Solution

Question 8

Carbohydrate

Protein

Fat

Amino acids

Solution

Question 9

Fumaric and malic acid

Succinic and fumaric acid

Malic and oxaloacetic acid

Citric and isocitric acid

Solution

Question 10

Krebs cycle

Glyoxylate cycle

Ornithine cycle

Glycolysis.

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