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Respiration in Plants Test - 55

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Respiration in Plants Test - 55
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  • Question 1
    1 / -0
    Citric acid cycle is the alternate name of
    Solution
    Citric acid cycle or tricarboxylic acid cycle or Krebs cycle is a process which is named after a German biochemist Hans Kreb. It is named citric acid cycle after one of its participating compounds. It takes place in the mitochondria of cells and results in the formation of ATP.
    So, the correct option is 'TCA cycle'
  • Question 2
    1 / -0
    Which of the following process is used in the conversion of pyruvate to acetyl CoA?
    Solution
    If sufficient oxygen is available pyruvic acid will enter the mitochondrial matrix and undergo Krebs cycle by aerobic means. This reaction is known as the link reaction, where pyruvic acid is converted to acetyl CoA and NADH₂.
    This is the oxidative decarboxylation of pyruvic acid because here the three carbon molecule of pyruvic acid is converted into a two-carbon molecule of acetyl CoA.
    So, the correct option is 'Oxidative decarboxylation'
  • Question 3
    1 / -0
    Succinate is oxidised to fumarate in Krebs cycle by
    Solution
    In the Krebs cycle, succinate is oxidized to form fumarate by removal of 1 hydrogen.
    Here the enzyme used is succinate dehydrogenase and also a coenzyme FAD is used which gets converted to FADH. In this process, 1 molecule of water is also released.
    So, the correct option is 'Removal of hydrogen'
  • Question 4
    1 / -0
    Fumerase changes fumaric acid into
    Solution
    Krebs' cycle is a stepwise catabolic process that converts organic acids to CO$$_2$$ and H$$_2$$O and yields energy. Fumaric acid is a four carbon organic compound which when acted upon by fumarase enzyme, forms malic acid by releasing H$$_2$$O. Malic acid is also a four carbon compound.
    So the answer is 'Malic acid'.
  • Question 5
    1 / -0
    Biological oxidation in Krebs cycle involves
    Solution
    A carboxyl group is removed from pyruvate and released as carbon dioxide. The two-carbon molecule from the first step is oxidized, The oxidized two-carbon molecule, an acetyl group, is attached to Coenzyme A to form acetyl CoA.
    The Krebs cycle does not require oxygen directly but it can only take place when oxygen is present because it relies on by-products from the electron transport chain, which requires oxygen.
    So the correct option is 'O$$_2$$'.
  • Question 6
    1 / -0
    R.Q. can vary due to
    Solution
    The respiratory quotient depends on the type of respiratory substrate which is to release energy for the synthesis of ATP. If the respiratory substrate is a lipid, it consists carbon-hydrogen bonds mean more ATP is produced from them in respiration. This also means more oxygen is required to break them down, so has an RQ of less than one and if the substrate is glucose the RQ is 1.
    So the correct option is 'Respiratory substrate'.
  • Question 7
    1 / -0
    Which of the following is an end product of citric acid cycle?
    Solution
    Glycolysis produces 2 pyruvate molecules. The pyruvate molecules then forms acetyl CoA and one molecule of carbon dioxide is released. The acetyl-CoA molecules then enters the citric acid cycle. The end product of citric acid cycle is 2 carbon dioxide molecules, 1 GTP, 3 NADH and 1 FADH$$_2$$.
    Thus, the correct answer is 'Carbon dioxide.'

  • Question 8
    1 / -0
    NADH of glycolysis reacts with an inorganic element during liberation of energy. The respiration is
    Solution
    The end product of pyruvate and NADH which is formed by the dehydrogenation of glyceraldehydes 3 phosphates is then reoxidized to NAD+ by oxygen. During the oxidation of glyceraldehyde 3 phosphate, much of free energy is liberated.  Such type of events occurs in plant and animal tissues during aerobic conditions.
    So, the correct answer is 'Aerobic respiration'.
  • Question 9
    1 / -0
    Sequence in Krebs cycle is
    Solution
    During the Krab cycle, the isocitric acid is converted to oxalosuccinic acid where a molecule of energy is converted to NADH and the enzyme used here is isocitrate dehydrogenase.
    This oxalosuccinic acid is converted into Alpha-ketoglutaric acid by the enzyme isocitrate dehydrogenase and during this process, a carbon dioxide molecule is released.
    So, the correct option is 'Isocitric acid --> Oxalosuccinic acid -->α -Ketoglutaric acid'
  • Question 10
    1 / -0
    Connecting link between glycolysis and Krebs cycle is/before entering Krebs cycle pyruvate is changed to
    Solution
    The end product of glycolysis is a three-carbon molecule pyruvic acid. Pyruvic acid is first converted to acetyl coenzyme A by a link reaction. This acetyl coenzyme A is a two-carbon molecule. This reaction results in the decarboxylation of the pyruvic acid. The acetyl coenzyme A thus formed enters the Krebs cycle and along with oxaloacetic acid forms a 6 C molecule citric acid.
    So, the correct option is acetyl 'Acetyl CoA.'
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