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Respiration in Plants Test - 56

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Respiration in Plants Test - 56
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Fermentation products of yeast are
    Solution
    Unicellular organisms like yeast undergo an alternate pathway of respiration in which an organic substrate is broken down in absence of oxygen. The end products are alcohol and CO$$_2$$. Such a process is called alcoholic fermentation. In Yeast, the fermentation products are ethyl alcohol and carbon dioxide.
    So the answer is 'Ethyl alcohol + CO$$_2$$'.
  • Question 2
    1 / -0
    Krebs cycle is
    Solution
    The hydroxyethyl group of pyruvate is oxidized to an acetyl group and the enzyme-bound acetyl group is transferred to CoA forming acetyl CoA. During the Krebs cycle, electrons are removed from acetyl CoA and these electrons reduce more NAD+, along with another electron carrier, FAD.
    So the correct option is 'Complete oxidation of acetyl CoA without electron transport'.
  • Question 3
    1 / -0
    Pyruvic acid is formed at the end of
    Solution
    Pyruvic acid is the end product of Glycolysis. The process of Glycolysis starts with one molecule of glucose and ends with the two molecules of pyruvate (pyruvic acid).
    So, the correct answer is 'Glycolysis'.
  • Question 4
    1 / -0
    Oxidation of pyruvate to CO$$_2$$ and H$$_2$$O occurs through
    Solution
    Pyruvate formed during glycolysis is oxidized CO$$_2$$ and H$$_2$$O in Krebs cycle or Citric acid cycle or Tricarboxylic acid cycle. Krebs cycle involves in the oxidation of acetyl CoA into CO$$_2$$ and H$$_2$$O.
    So the correct option is 'Citric acid cycle, Tricarboxylic acid and Krebs cycle'.
  • Question 5
    1 / -0
    Krebs cycle is component of
    Solution
    Krebs cycle is also called as citric acid cycle or tricarboxylic acid cycle. It is component of aerobic respiration. Through Krebs cycle, all aerobic organisms obtain their energy. It does not directly require oxygen. However, it relies on the by-products from the electron transport chain, which requires oxygen. Hence, it is an aerobic process.
    Thus, the correct answer is 'Aerobic respiration.'
  • Question 6
    1 / -0
    Most of the biological energy is supplied by mitochondria through
    Solution
    Mitochondrial matrix houses the entire process of Krebs' cycle except succinyl dehydrogenase enzyme which is located in the inner membrane of mitochondria. Krebs' cycle or TCA cycle is a catabolic oxidation of organic substrates which results in release of CO2 and H2O. As it entirely occurs in mitochondria, primary supply of energy by mitochondria is through the TCA cycle.
    So the answer is 'Oxidising TCA substrates'.
  • Question 7
    1 / -0
    For two molecules of glucose, glycolysis uses and produces ATP molecules
    Solution

    A. Correct option A 
    B. Explanation for correct option:

    • The first step of glucose breakdown is glycolysis in which there is a net gain of 8 ATP ( 6 ATP from NADH$$_2$$ and 2 ATP by direct conversion from ADP) from 1 molecule of glucose.
    • However, 2 ATP are consumed and 4 ATP are produced by direct conversion per molecule of glucose during glycolysis. 
    • Hence, for 2 molecules of glucose, 4 ATP and 8 ATP are used and produced respectively in total.

  • Question 8
    1 / -0
    Glycolysis and TCA cycle operate respectively in
    Solution
    The first step of cellular respiration is glycolysis that operates in the cytoplasm of the cell. Glycolysis is followed by Krebs cycle which takes place in the mitochondrial matrix.
    So the answer is 'Cytosol and matrix of mitochondrion'. 
  • Question 9
    1 / -0
    The site of Krebs cycle in bacteria is
    Solution
    Krebs cycle is performed in the mitochondrial matrix, in the cytosol with the proton gradient for ATP production being across the cell's surface i.e. plasma membrane.
    So the correct option is 'Plasma membrane'.
  • Question 10
    1 / -0
    In case NADH is oxidised in a single step to form water
    Solution
    All the NADH$$_2$$ produced during Glycolysis and Krebs' cycle may enter ETS at a higher energy level that defines the proton gradient. Stepwise oxidation of NADH$$_2$$ ensures release of 3 ATP per molecule of it. If it happens in a single step, usable energy in the form of ATP would be released very less and most energy will be liberated as heat.
    So the answer is 'Most of energy is liberated as heat'.
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