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Respiration in Plants Test - 63

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Respiration in Plants Test - 63
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  • Question 1
    1 / -0
    Which of the following membrane bound complex in mitochondria is not a proton pump :-
  • Question 2
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    R.Q. would depend upon
    Solution
    Respiratory Quotient (R.Q.) is the ratio of the volume of CO$$_{2}$$ released to the volume of O$$_{2}$$ consumed in a respiration process. It depends on the nature of the substrate and its capacity of using O$$_{2}$$ and releasing CO$$_{2}$$. For example, glucose consumes 6 CO$$_{2}$$ and releases 6 O$$_{2}$$, so its R.Q. is 1.
     Hence, the correct answer is 'Nature of substrate'
  • Question 3
    1 / -0
    When one molecule of glucose undergoes glycolysis aerobically, last stable product will be
    Solution
    The term glycolysis has originated from the Greek words, glucose for sugar and lysis for splitting. In this process, glucose undergoes partial oxidation to form two molecules of pyruvic acid in a multi-step process catalyzed by various enzymes.
    So the correct option is 'Two pyruvic'.
  • Question 4
    1 / -0
    In citric acid cycle, the step not using dehydrogenase enzymes is
    Solution
    1. Malic acid converts into oxaloacetate in the presence of Malic dehydrogenase.
    2. Succinate converts into fumarate in the presence of Succinic dehydrogenase.
    3.  Oxaloacetic acid forms citric acid in the presence of enzyme citrate synthetase.
    4. Citric acid converts into alpha-ketoglutarate in stepwise reactions.
    So the correct option is 'Oxaloacetate to citric acid'.
  • Question 5
    1 / -0
    Substrate level phosphorylation in Krebs cycle occurs during conversion of ________________.
  • Question 6
    1 / -0
    In Krebs cycle, second decarboxylation occurs during
    Solution
    In Krebs' cycle, decarboxylation occurs twice during the completion of one cycle. Second decarboxylation occurs when ketoglutarate (5) is converted to succinyl CoA (4 C) by ketoglutarate dehydrogenase liberating CO2.
    So the answer is 'Ketoglutarate Succinyl CoA'.
  • Question 7
    1 / -0
    Select the wrong statement.
    Solution
    A) RQ is 0.7 with tripalmitin as it consumes more oxygen than carbon dioxide release.
    B) Link compound between glycolysis and Krebs cycle is Acetyl coenzyme A which is formed after the oxidative decarboxylation of pyruvic acid.
    C) 36 ATP molecules are produced per glucose molecule in aerobic respiration obtain by glycolysis. oxidative decarboxylation and TCA.
    D) 2 ATP molecules are produced per glucose molecule in anaerobic respiration.
    So the correct option is 'Link compound between glycolysis and Krebs cycle is malic acid'.
  • Question 8
    1 / -0
    After glycolysis, fate of glucose in mitochondrial matrix is
    Solution
    After glycolysis, the end product pyruvic acid undergoes Krebs cycle but before that, it has to go through link reaction. The link reaction occurs in mitochondrial matrix and converts pyruvic acid to acetyl CoA through the pyruvate dehydrogenase complex. Such a reaction is called oxidative decarboxylation. Hydrogen and carbon dioxide are released.
    So, the correct answer is 'Oxidative decarboxylation'.
  • Question 9
    1 / -0
    Decarboxylation occurs during
    Solution
    In Krebs Cycle six carbon compounds like Citric acid converts into Oxalo succinic acid which is five carbon compound and it forms Malic acid which further reacts and forms Oxaloacetic acid which is both four carbon compound. Therefore in each stem carbon is released in the form of carbon dioxide and the process is known as decarboxylation.
    So the correct option is 'Krebs cycle.'.
  • Question 10
    1 / -0
    The first stable compound of Krebs cycle is
    Solution
    The TCA cycle starts with the condensation of acetyl group with oxaloacetic acid and water to yield citric acid which is the first stage six carbon compound. This reaction is catalyzed by the enzyme citrate synthase. This cycle is the next step in aerobic respiration after glycolysis.
    So, the correct option is 'Citric Acid'.
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