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Respiration in Plants Test - 91

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Respiration in Plants Test - 91
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  • Question 1
    1 / -0
    The intermediate between glycolysis and TCA cycle is
    Solution
    Cellular respiration is the breakdown of glucose to obtain energy. It has three steps : 
    1. Glycolysis
    2. Krebs cycle 
    3. Terminal oxidation
    Glycolysis occurs in the cytoplasm of the cell in which pyruvate molecules are formed, these pyruvate molecules are then transferred to mitochondria through the inner mitochondrial membrane where it undergoes oxidation and forms acetyl CoA with the help of coenzymes and cofactors , this step connects both the process of glycolysis and Krebs cycle thus called as link reaction .
    So, the correct option is ' acetyl CoA'.
  • Question 2
    1 / -0
    Find the incorrect match (with respect to ATP gain) -
    Solution
    The Kreb’s Cycle gives 3 moles of NADH1 mole of FADH and 1 mole of ATP per cycle of substrate i.e per 1 mole of Acetyl CoA. However net ATP i.e after ETS which would make the answer to 12 ATP(9+2+1) respectively.

    36 ATPs are produced in Aerobic Respiration involving the complete breakdown of glucose molecule into carbon-dioxide and water using oxygen as final electron aceptor

    Complete oxidation of glucose molecule takes place in 3 sequential reactions -

    1.Glycolysis occuring in cytoplasm

    2.Kreb cycle occuring in mitochondrial matrix

    3 Electron transport chain (ETC )and oxidative phosphorylation occuring in inner mitochondrial membrane . So,total number of ATPs produced in aerobic respiration are

    Glycolysis - 6/8 ATPs

    Link reaction and kreb cycle - 30ATPs

    Total -36/38 ATPs.


    So, the correct option is 'Option A'.

  • Question 3
    1 / -0
    During respiration,
    Solution
    Correct option: A 
    Explanation: 

    • Respiration occur in these step - glycolysis, Krebs cycle, and oxidative phosphorylation occurs in the electron transport chain.
    • So the first step glycolysis occur in both aerobic and aerobic condition and in final step two molecule of pyruvic acid and two molecule of ATP is produce. connecting link  between glycolysis and Krebs cycle is the pyruvic acid is converted to acetyl CoA. 
    • This acetyl CoA after the two processes form the 2 ATP, 6 NADH, and 2FADH and carbon dioxide . 
    • After that in the electron transport chain, where most of the ATP is produced, the hydrogen that is removed from the products in previous steps are forwarded to mitochondria, where this hydrogen react  with oxygen molecules and water molecule form. 
    So formation of 2PGAL occur in glycolysis not in Krebs cycle . 
  • Question 4
    1 / -0
    Which of the following options does not hold good regarding anaerobic respiration of fermentation?
    Solution
    Fermentation is the incomplete oxidation of glucose under anaerobic conditions by sets of reactions where pyruvic acid is converted to $${CO}_{2}$$ and ethanol (alcoholic fermentation) or lactic acid (lactic acid fermentation). In fermentation, there is a net gain of only 2 ATP molecules for each molecule of glucose degraded o pyruvic acid.
  • Question 5
    1 / -0
    How many oxygen atoms are required for the complete oxidation of pyruvate?
    Solution
    A. Correct option -A
    B. Explanation for correct option -A

    • During the Krebs cycle, 6 oxygen molecules are involved during the oxidation of pyruvate.
    • These 6 oxygen molecules formed from 12 atoms of oxygen.
    • Since in the Krebs cycle 2 molecules of pyruvate are formed, complete oxidation of pyruvate requires 6 atoms of oxygen. 

  • Question 6
    1 / -0
    In kreb cycle, the removal of $$CO_2$$ and $$NAD^+$$ reduction steps are respectively
  • Question 7
    1 / -0
    Study carefully the following statements and select the incorrect ones.
    (i) When fats are used in respiration, the RQ is more than unity because fats contain more $${O}_{2}$$ and require relatively less amount of $${O}_{2}$$ for oxidation.
    (ii) The most important energy carrier is ATP. This energy-rich compound is mobile and can pass from one cell to another.
    (iii) Before pyruvic acid enters Krebs' cycle, one of the two carbon atoms of pyruvic acid is reduced to carbon atoms of pyruvic acid is reduced to carbon dioxide in the reaction called reductive carboxylation.
    (iv) A special electron carrier system located in the mitochondrial membrane is called a shuttle system. It transfers electrons from the hydrogens of cytoplasmic NADH to the mitochondrial electron carriers across the mitochondrial membrane.
    (v) Zymase is a complex mixture of many enzymes which requires several coenzymes for its action. The enzyme complex-zymase catalyses series of reactions taking place during fermentation leading to the production of ethyl alcohol.
  • Question 8
    1 / -0
    During amphibolic pathway, acetyl Co-A can perform the biosynthesis of 
    Solution
    Fatty acid synthesis takes place in the cytoplasm of the cell. It is the creation of fatty acids from acetyl-CoA and NADPH through the action of enzymes called fatty acid synthases. Most of the acetyl-CoA which is converted into fatty acids is derived from carbohydrates via the glycolytic pathway. 
    So, the correct option is option C. 
  • Question 9
    1 / -0
    Respiratory quotient may be represented as
    Solution
    During aerobic respiration, $${O}_{2}$$ is consumed and $${CO}_{2}$$ is released. The ratio of the volume of $${CO}_{2}$$ evolved to the volume of $${O}_{2}$$ consumed in respiration over a period of time is called as respiratory quotient (RQ) or respiratory ratio.
    $$RQ=\frac{Volume\,\, of\,\, {CO}_{2} \,\,evolved}{Volume \,\,of \,\,{O}_{2} \,\,consumed}$$.
    So the correct option is B.
  • Question 10
    1 / -0
    Identify A and B in the given reaction.
    $$Pyruvic \,\,acid+CoA+{NAD}^{+}\xrightarrow[Pyruvate \,\,dehydrogenase]{Mg^{2+}}A+B+NADH+{H}^{+}$$
    Solution
    During aerobic respiration, pyruvic acid which is formed during glycolysis enters mitochondrial matrix. It undergoes oxidative decarboxylation to produce $${CO}_{2}$$ and NADH. The product combines with sulfur-containing co-enzyme A to form acetyl CoA. This reaction is catalyzed by an enzyme complex pyruvate dehydrogenase. This step is called link reaction or gateway step as it links glycolysis with Krebs' cycle.
    $$Pyruvic acid+COA+{NAD}^{+}\xrightarrow[Pyruvate \,\,dehydrogenase]{ Mg^{2+}}Acetyl CoA+{CO}_{2}+NADH+{H}^{+}$$
    So the correct answer is 'A-Acetyl CoA ; B-$$CO_2$$'.
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