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Some Basic Concepts of Chemistry Test - 3

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Some Basic Concepts of Chemistry Test - 3
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Weekly Quiz Competition
  • Question 1
    1 / -0

    The SI unit of time is:

    Solution

    Time has the SI unit second.

     

  • Question 2
    1 / -0

    According to Avogadro's law at the same temperature and pressure:

    Solution

    According to Avogadro's law, equal volumes of gases at same temperature and pressure should contain equal number of molecules.

     

  • Question 3
    1 / -0

    A compound has an empirical formula of C2HBr. If the molar mass of the compound is 314.7 g/mol, what is the molecular formula of the compound? (Atomic mass of Br = 80g/mol)

    Solution

    Empirical formula mass is (2 X 12) + 1 + 80 = 105g and molar mass of the compound is 314 g/mol.

    Hence, n = 3

    Therefore, the molecular formula is C6H3Br3.

     

  • Question 4
    1 / -0

    Vapour density of a gas is 22. Its molecular mass will be:

    Solution

    Molecular mass = 2 x vapour density

    = 2 x 22

    = 44

    Therefore, molecular mass of a gas will be 44.

     

  • Question 5
    1 / -0

    Which formula represents the simplest whole number ratio of various atoms present in a compound?

    Solution

    Empirical formula represents the simplest whole number ratio of various atoms present in a compound.

     

  • Question 6
    1 / -0

    The scientific notation for 0.00016 is:

    Solution

    Here, the decimal has to be moved four places to the right side and hence -4 is the exponent in the scientific notation.

     

  • Question 7
    1 / -0

    The prefix used for 10-18 is:

    Solution

    The prefix atto is used for 10-18.

     

  • Question 8
    1 / -0

    The number of moles of Cr and O in a compound are 4.8 x 1010 and 9.6 x 1010respectively. Its empirical formula is:

    Solution

    Molar ratio of Cr and O = 4.8 x 1010 : 9.6 x 1010 = 1 : 2

    Hence, empirical formula = CrO2

     

  • Question 9
    1 / -0

    If 2 moles of H2 and O2 are available for the reaction, identify the limiting reagent for the reaction, 2H2 + O2 → 2H2O

    Solution

    Only 1 mole of O2 is required for the complete combustion of 2 moles of H2, hydrogen is the limiting reagent.

     

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