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Some Basic Concepts of Chemistry Test - 48

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Some Basic Concepts of Chemistry Test - 48
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  • Question 1
    1 / -0
    An organic compound made of $$C, H$$ and $$N$$ contains $$20$$% nitrogen. Its  minimum molecular weight is:
    Solution
    Let the molecular weight be $$X$$. Then $$20$$% of $$X$$  is equal to molecular weight of Nitrogen ($$N$$).

    $$20$$%  of $$X$$ = $$14$$

    $$X$$/$$5$$  = $$14$$

    Therefore the minimun molecular weight is $$14×5$$ = $$70$$.
  • Question 2
    1 / -0
    At $$\displaystyle\, 80^{\circ}C$$ the vapour pressure of pure liquid A is 250 mm of Hg and that of pure liquid B is 1000 mm of Hg. If a solution of A and B boils at $$\displaystyle\, 80^{\circ}C$$ and 1 atm pressure, the amount of A in the mixture is (1 atm = 760 mm Hg) 
    Solution
    $$P$$= $$P°_{a}$$*$$X_{a}$$+ $$P°_{b}$$*($$1$$ - $$X_{a}$$)
    $$760$$ = $$250$$*$$X_{a}$$ + $$1000$$*($$1$$ - $$X_{a}$$)
    $$X_{a}$$ = $$34$$ mole percent
  • Question 3
    1 / -0
    Which symbol is used to represent the unit of atomic mass, amu?
    Solution
    The symbol 'u' represents the unit of atomic mass, amu. For example, the atomic mass of carbon-12 is written as 12 u. 
    Hence, option A is correct.
  • Question 4
    1 / -0
    $$CH_3CH_2CH_2CH_{3(g)}\rightleftharpoons CH_3-\underset{iso-butane}{\underset{CH_3}{\underset{|}{C}H}}-CH_{3(g)}$$
    Solution
    $$K_c$$ for the above reaction is represented as
    $$ K_c = \dfrac{isobutane}{butane}$$
    $$ (isobutane) = 3(butane)$$
    So the concentration of sobutane is thrice of butane in 100% solution of the isobutane and butane.
    So isobutane $$= 75\%$$
  • Question 5
    1 / -0
    4.88 g of $$KClO_3$$ when heated produced 1.92 g of $$O_2$$ and 2.96 g of KCl. Which of the following statements regarding the experiment is correct?
    Solution
    $$2KClO_3 \rightarrow 2KCl+3O_2$$ 
    Mass of the reactant = total mass of the products ($$2.96 + 1.92=4.88\ g$$)
    According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. Therefore, this demonstrates the law of conservation of mass.
    Option A is correct
  • Question 6
    1 / -0
    Which of the following statements best explains the law of conservation of mass, concerning a chemical change?
    Solution
    According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.
    Among the given option only option C involves a chemical change/reaction as:
    $$C+O_2 \rightarrow CO_2$$
    $$m_{reactants}=m_{products}$$
    $$36+32=68\ g$$
    option C is the best demonstration of the law of conservation of mass.
  • Question 7
    1 / -0
    The density of a gas is $$1.78 \ g \ L^{-1}$$ at STP. The weight of one mole of gas is:
    Solution
    Density $$=1.78 \ g L^{−1}$$  at STP

    mass of $$1\ L$$ gas$$=1.78\ g$$

    1 mol of gas at STP $$=22.4\ L$$

    $$\therefore\ $$mass of $$22.4\ L$$ gas$$=22.4 \times 1.78=39.872\ g$$

    Option $$A$$ is correct.
  • Question 8
    1 / -0
    At $$-50^0C$$, liquid $$NH_3$$ has ionic product is $$10^{-30}$$. How many amide $$(NH_2{^-})$$ ions are present per $$mm^3$$ in pure liquid $$NH_3$$ ? Take $$N_a \, = \, 6 \times \, 10^{23}$$
    Solution
    $$\displaystyle 2NH_3 \to NH_4^++NH_2^- $$
    The ionic product $$\displaystyle [NH_2^-][NH_4^+]=10^{-30} $$
    $$\displaystyle [NH_2^-]=[NH_4^+]$$
    $$\displaystyle [NH_2^-]^2=10^{-30} $$
    $$\displaystyle [NH_2^-]=10^{-15} \ mol/dm^3 $$
    $$\displaystyle 1 \ dm^3 =10^6 \ mm^3$$
    $$\displaystyle [NH_2^-]=10^{-15} \ mol/dm^3  \times  \dfrac {1 \ dm^3}{10^6 \ mm^3}$$
    $$\displaystyle [NH_2^-]=10^{-21} \ mol/mm^3 $$
    $$\displaystyle N_a=6 \times 10^{23} \ ions/mol$$
    $$\displaystyle [NH_2^-]=10^{-21} \ mol/mm^3  \times \dfrac { 6 \times 10^{23} \ ions} { 1 \ mol }$$
    $$\displaystyle [NH_2^-]= 600 \ ions/mm^3 $$
    Hence, $$\displaystyle [NH_2^-]= 602 \ ions/mm^3 $$ is correct answer.
  • Question 9
    1 / -0
    Which of the following gases will have least volume if 10 g of each gas is taken at same temperature and pressure?
    Solution
    Avogadro’s Law states that under same conditions of temperature and pressure, volume of gases (V) is proportional to the amount of gases in moles(n).

    $$V \propto n$$

    $$n=\dfrac{mass}{molar\ mass}$$

    Mass of gases are same = 10 g

    $$V \propto \dfrac{1}{Molar\ mass}$$

    Molar mass of $$CO_2=12+2\times 16=44\ g$$
    Molar mass of $$N_2=2\times 14=28\ g$$
    Molar mass of $$CH_4=12+4\times 1=16\ g$$
    Molar mass of $$HCl=1+35.5=36.5\ g$$

    Order of volume of 10 g of given gases is:
    $$CH_4>N_2>HCl>CO_2$$
  • Question 10
    1 / -0
    What will be the mass of 100 atoms of hydrogen?
    Solution
    Mass of 1 mol or ($$6.022 \times 10^{23}$$ atoms) of $$H=1\ g$$
    Mass of 100 atoms = $$\dfrac{1}{6.022 \times 10^{23}} \times 100$$ g
    $$=0.166 \times 10^{-23}=1.66 \times 10^{-22}$$ g
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