Organic Chemistry Some Basic Principles and Techniques Test

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Organic Chemistry Some Basic Principles and Techniques Test - 36

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Weekly Quiz Competition

Question 1
1 / -0

Indicate the wrongly named compound.

A
$$\underset{(4-methyl-1-pentanal)}{CH_3 - \underset{CH_3}{\underset{|}{CH}} - CH_2 - CH_2 - CHO}$$

B
$$\underset{(4-Methylpent-2-yn-1-oic \ acid)}{CH_3 - \underset{CH_3}{\underset{|}{CH}} - C \equiv C - COOH}$$

C
$$\underset{(2-Methyl -1-pentanoic acid)}{CH_3CH_2CH_2 - \underset{CH_3}{\underset{|}{CH}} - COOH}$$

D
$$\underset{(Hex -3-en-5-one)}{CH_3CH_2 - CH = CH - \overset{O}{\overset{||}{C}} - CH_3}$$

Solution

According to IUPAC convention, minimum numbering should be given for groups or substituents on parent skeleton.

Ketone functional group has a higher priority than alkene.

So, correct name should be: $$Hex-3-en-2-one$$

$$\underset{6}{CH_3} - \underset{5}{CH_2} - \underset{4}{CH} = \underset{3}{CH} - \overset{O}{\overset{||}{\underset{2}{C}}} - \underset{1}{CH_3}$$

Option D is correct.
Question 2
1 / -0

Two members of a homologous series have different:

A
general formula

B
molecular weights

C
methods of preparation

D
chemical properties

Solution

In an organic chemistry, a homologous series of compounds with the same functional group and similar chemical properties in which the number of series differs by a number of repeating units they contain, so differ by weight.
In homologous series, the consecutive members differ by the molecular weight of 14.
Question 3
1 / -0

The synthetic steroid ethynylestardiol (1) is a compuond used in the birth control pill.
How many asymmetric (stereogenic) centres are present in compound (1) ?

A
2

B
3

C
4

D
5

Solution

Stereogenic centres are those centre which are attached to the different group with single bond.
There are $$5$$ stereogenic centre.
Question 4
1 / -0

The functional groups present in Cortisone are:

A
Ether, alkene, alchohol

B
Alcohol, ketone, alkene, ether

C
Alcohol, ketone, ammine

D
Ether, amine, ketone

Solution

$$a$$ is alcoholic group, $$b$$ is ether, $$c$$ is ketone group and $$d$$ is the alkene group.
Question 5
1 / -0

IUPAC name of 4-iso-propyl-m-xylene is:

A
1-iso-propyl-2,4-dimethylbenzene

B
4-iso-propyl-m-xylene

C
4-iso-propyl-2,3-dimethylbenzene

D
4-iso-propyl-3,5-dimethylbenzene

Solution

According to IUPAC convention, least number should be given to the substituent on parent molecule.
Name is: $$1-iso-propyl-2,4-dimethylbenzene$$
Question 6
1 / -0

Identify which functional group are not present in the given compound?

A
ketone

B
Ester

C
Amide

D
Ether

Solution

Box $$a$$ encloses ester group, $$b$$ encloses ketone group while $$c$$ encloses amide group.
Here ether group is not present.
Question 7
1 / -0

The product $$X$$ is :

A

B

C

D

Solution

(Refer to Image)
$$DMSO$$ is dimethyl sulfoxide. It is an organosulphur compound with the formula of $$(CH_3)_2SO$$. Sulphur is nucleophilic towards soft electrophiles and the oxygen is nucleophilic towards hard electrophiles.
Question 8
1 / -0

Which combination is best for preparation of the compound $$(A)$$ shown below ?

A

B

C

D

Solution

To prepare A, the reagent should be a non-inverting one and also the other group must retain the same configuration.$$NaC\equiv CH$$ is a non inverting reagent, Hence,

Refer to image
Question 9
1 / -0

What is the major product of the given reaction?
$${CH}_{3}-C\equiv N\xrightarrow [ { Et }_{ 2 }O ]{ { CH }_{ 3 }MgI }\quad \xrightarrow [ ]{ { H }_{ 3 }{ O }^{ \oplus } } $$

A
$${CH}_{3}-{CH}_{2}-NH-{CH}_{3}$$

B

C

D

Solution

A structural reaction for the reaction written .
Thus when acetonitrate reacts with methyl magnessium iodide it leads to the formation of acetone.This is also an example of grignards reaction.
Question 10
1 / -0

To convert $$1-$$butyne to $$1-D-$$butanal, one would carry out the following steps :
(I) Sodium amide, then $$D_{2}O$$
(II) Disiamy Iborane, then hydrogen peroxide/sodium hydroxide
(III) The transformation can not be carried out with the indicated reagents.

A
$$I$$, followed by $$II$$

B
$$II$$, followed by $$I$$

C
$$III$$

D
$$II$$

Solution

For conversion of 1-butyne to 1-D-butanal

$$CH\equiv C-CH_2-CH_3\longrightarrow CH_3-CH_2-CH_2-CHO$$

so addition reaction of water with -OH groups on same carbon occurs. Here, where water is lost. Since neither of options indicate this, the indicated reagents can not be used.