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Organic Chemistry Some Basic Principles and Techniques Test - 44

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Organic Chemistry Some Basic Principles and Techniques Test - 44
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Weekly Quiz Competition
  • Question 1
    1 / -0
    $$ \xrightarrow [ { H }^{ + } ]{  } A$$, $$A$$ is:

    Solution

  • Question 2
    1 / -0
    Compound A is:

    Solution

  • Question 3
    1 / -0
    Predict the product of reaction below:

    Solution

  • Question 4
    1 / -0
    In the given equation X is?

    Solution

    $$Br_2 | FeBr_3 $$ is a nucleophilic substitution reagent where $$FeBr_3$$ is a lewis acid. It attacks the more electron deficient site so it attaches by the carbon.

  • Question 5
    1 / -0
      

  • Question 6
    1 / -0
    An organic compound 'X' is a constituent of wine. On heating with acidified potassium dichromate it gives a compound 'Y' which gives brisk effervescence with sodium bicarbonate. Identify 'X' and 'Y'
    Solution
    $$(A)\ C_{2}H_{6}, CH_{3}COOH$$
    Because wine contains $$C_{2}H_{2}$$ and on heating it gives $$y$$
    $$C_{2}H_{6}\xrightarrow [ potassium ]{ \Delta  }  CH_{3}COOH\rightarrow Na_{2}HCO_{3}$$
    dichromats (acidified)                                   $$\downarrow$$
                                                                     gives brisk effervesce




  • Question 7
    1 / -0
    $$R-\overset{O}{\overset{||}{C}}-Cl+N\overset{-}{u}\rightarrow R-\overset{O}{\overset{||}{C}}-Na+Cl^-$$
    The correct expansion for the below reactions is?
    Solution
    Nucleophile being negative attack the deficit C of carbonyl group and after that the electron withdrawing group Cl separated with two electrons with it and cabonyl group again forms. Tihs reaction is nucleophilic addition reaction to a compound containing carbonyl group.
  • Question 8
    1 / -0
    What is the major product of the reaction ?

    Solution
    The (i) reaction is nucleophilic addition reaction in presence of Grignard's reagent and the (ii) reaction is an electrophilic substitution reaction. 
    Product in option $$A$$ is formed.

  • Question 9
    1 / -0
    Compound $$(B)$$ is:
    $$C_6H_5(CH_2)_5\overset{\overset{O}{||}}{C}-Cl\overset{AlCl_3}{\underset{CS_2}{\longrightarrow}}\underset{C_{12}H_{14}O}{(A)}$$$$\overset{KMnO_4,D}{\underset{H_3O^{\oplus}}{\longrightarrow}}(B);$$
  • Question 10
    1 / -0
    Which of the following represents an intermediate formed in reaction of toluene and chlorine at elevated temperature in sunlight?
    Solution
    Refer to Image 1)
    This reaction occurs via radical mechanism and intermediate is (Refer to Image 2).

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