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Organic Chemistry Some Basic Principles and Techniques Test - 45

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Organic Chemistry Some Basic Principles and Techniques Test - 45
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  • Question 1
    1 / -0
    Consider the reactions
    (i) $$(CH_3)_2CH - CH_2Br$$
        $$\xrightarrow{C_2H_3OH}(CH_3)_2CH - CH_2OC_2H_5 +HBr$$
    (ii) $$(CH_3)_2CH - CH_2Br$$
        $$\xrightarrow{C_2H_3O^-}(CH_3)_2CH - CH_2OC_2H_5 +HBr$$
    The mechanisms of reactions(i) and (ii) are respectively.
    Solution

    (i) $$(CH_3)_2CH-CH_2Br \xrightarrow []{C_2H_3OH}(CH_3)_2CH-CH_2OC_2H_5+HBr$$
    (Refer to Image 1)

    (ii) $$(CH_3)_2CH-CH_2Br \xrightarrow []{C_2H_5O^{\circleddash}} (CH_3)_2CH-CH_2O-C_2H_5$$
    (Refer to Image 2)

  • Question 2
    1 / -0
    Give $$ IUPAC $$ names of following alkyl group.

    Solution

  • Question 3
    1 / -0
    $$IUPAC$$ name of the hydrocarbon $$(A)$$ is:

    Solution
    The IUPAC name is  :- $$2,5-dimethyl$$ $$heptane$$.

  • Question 4
    1 / -0
    Based on "$$1993$$ Recommendations" $$H_2C=CHCH_2CH_2CH_3$$ is named as:
    Solution
    $$\underset { 1 }{ { H }_{ 2 }C } =\underset { 2 }{ CH } \underset { 3 }{ { CH }_{ 2 } } \underset { 4 }{ { CH }_{ 2 } } \underset { 5 }{ { CH }_{ 3 } } $$
    $$1-$$pentene position of the functional group
    should be mention before the main carbon chain name.
  • Question 5
    1 / -0
    Which of the following substrate is most reactive towards methoxide ion ($$Me=\overset{\ominus}{O}$$)?
    Solution
    Solution:- (C)
    The substrate which has the best leaving group, i.e., the weakest base will be most reactive. 
    $$C{H}_{3}-O-S{O}_{2}-C{F}_{3}$$ is most reactive substrate because it has weakest base $$\left( -O-S{O}_{2}-C{F}_{3} \right)$$ group.
  • Question 6
    1 / -0
    IUPAC name of the formula $$CH_2(COOH)_2$$ is ?
    Solution

  • Question 7
    1 / -0
    Question

  • Question 8
    1 / -0
    A number of functional group and degree of unsaturation (respectively) in the above compounds is:

    Solution
    Function Groups are:
        $$O$$                      $$O$$
    $$-\overset {||}{C}-NH-$$ , $$-\overset {||}{C}-NH_2$$, $$-COOH$$, $$-O-$$, $$-NH-$$, $$-C\equiv CH$$ .
    Hence, only $$6$$ functional groups.
    Degree of unsaturation is $$8$$  ($$3$$ Rings+ $$3$$ Double bonds+ $$1$$ Triple bond) 
  • Question 9
    1 / -0
    Compound $$(A)$$ is:

  • Question 10
    1 / -0
    Which of the following molecules contains only $$\pi$$ bond?
    Solution
    There can be exclusive pi bonds without existing sigma bonds. Some such molecules are $$B_2$$ and $$C_2$$.
    $$MO$$ Theory shows that there are two sets of paired electrons in a degenerate pi bonding set of orbitals.
    The paired electrons belong to the pi orbitals ($$\pi$$ $$2px$$ and $$\pi 2py$$ to be precise). It is these paired electrons that are involved in bonding while the rest of the inner shell electrons aren’t.
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