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Organic Chemistry Some Basic Principles and Techniques Test - 48

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Organic Chemistry Some Basic Principles and Techniques Test - 48
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  • Question 1
    1 / -0

    Find the major product when the above compound is made to react with the following reagent.

    $$+Br_{ 2 }\quad \overset { hv }{ \underset { 298\quad K }{ \longrightarrow  }  } $$ (major). 

    Solution
    $$3^o$$ free radial more stable.
    So,Major product is option is B

  • Question 2
    1 / -0
    Which of the following pairs is correctly matched?
    Solution
    amino acid alanine is optically active
  • Question 3
    1 / -0
    The correct IUPAC name of the compound $$(CH_3CH_2)_2NCH_3$$ is:
    Solution
    $$(CH_3CH_2)_2NCH_3$$ it is a tertiary amine, and the parent chain is ethanamine.
    IUPAC name is N - Ethyl - N- methyl ethanamine.
  • Question 4
    1 / -0
    The presence of a carboxyl group in a compound can be detected using: 
    Solution
        $$O$$
    $$-\overset {||}{C}-O^{\circleddash}$$ carboxyl group in a compound can be detected by treating it with $$NaHCO_3$$. On reaction with $$NaHCO_3$$, $$CO_2$$ gas is evolved which turns lime water milky.
  • Question 5
    1 / -0
    A canonical structure will be more stable if 
    Solution
    A canonical structure will be more stable of i)negative charge is on more electronegative atom and positive charge on more electropositive atom.
    ii)If it increases cyclic delocalisation of $$(4n+2)\pi$$ electrons than if it involves acyclic delocalisation of $$(4n+2)\pi$$ electrons.
    A is the correct answer.
  • Question 6
    1 / -0
    What is 'A' in the above reaction?

    Solution
    First protonation occur then rearrangement of carbocation  to form more stable carbocation then $$Cl^-$$ get attack.
    C is the correct answer.

  • Question 7
    1 / -0
    No of $$\pi$$ electrons in cyclobutadienyl anion $${({C}_{4}{H}_{4})}^{-2}$$ is 
    Solution
    Number of $$\pi$$ bond in cyclobutadienyl ion is 1 and number of $$\pi$$ electrons is 2 elecrons.

  • Question 8
    1 / -0
    Silver benzoate reacts with bromine to give:
    Solution

    d is the correct option because it correctly shows the product formed

  • Question 9
    1 / -0
    Find the A

    Solution

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