Organic Chemistry Some Basic Principles and Techniques Test

Result

Organic Chemistry Some Basic Principles and Techniques Test - 5

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

In which of the following, functional group isomerism is not possible?

A
Cyanides

B
Aldehydes

C
Alkyl halides

D
Alcohols

Solution

Two or more compounds having the same molecular formula but different functional groups are called functional isomers and this phenomenon is termed as functional group isomerism. Alkyl halides do not show functional isomerism.
Question 2
1 / -0

The fragrance of flowers is due to the presence of some steam volatile organic compounds called essential oils. These are generally insoluble in water at room temperature but are miscible with water vapour in vapour phase. A suitable method for the extraction of these oils from the flowers is:

A
Crystallisation

B
Distillation under reduced pressure

C
Steam distillation

D
Distillation

Solution

Steam distillation is a technique applied to separate substances which are steam volatile and are immiscible with water. Essential oils are insoluble in water and soluble in steam and have high vapour pressure. Therefore, they can be separated by steam distillation.
Question 3
1 / -0

During hearing of a court case, the judge suspected that some changes in the documents had been carried out. He asked the forensic department to check the ink used at two different places. According to you which technique can give the best results?

A
Column chromatography

B
Distillation

C
Thin layer chromatography

D
Solvent extraction

Solution

Thin layer chromatography (TLC) is an adsorption chromatography, which involves separation of substances of a mixture over a thin layer of an adsorbent coated on glass plate. It is used to separate the pigments of the ink and will give the best results.
Question 4
1 / -0

The principle involved in paper chromatography is

A
Volatility

B
Partition

C
Adsorption

D
Solubility

Solution

Paper chromatography is a type of partition chromatography. In paper chromatography, a special quality paper known as chromatography paper is used. Chromatography paper contains water trapped in it, which acts as the stationary phase. Separation of components of a mixture depends upon their partitioning between water held in stationary phase (adsorbant paper) and the liquid present in the mobile phase.
Question 5
1 / -0

In which of the following compounds the carbon marked with asterisk is expected to have greatest partial positive charge?

A
∗CH₃− CH₂−Br

B
∗CH₃− CH₂− CH₃

C
∗CH₃−CH₂−I

D
∗ CH₃− CH₂−Cl

Solution

Cl is most electronegative amongst Cl, Br and I and has more -I (inductive electron withdrawing) effect. So it causes the asterisk marked to have the maximum partial positive charge.
Question 6
1 / -0

C₄H₁₀O represents methoxypropane (CH₃OC₃H₇) and ethoxyethane (C₂H₅O C₂H₅)

A
Metamerism

B
Functional group isomerism

C
Position isomerism

D
Stereoisomerism

Solution

Metamerism arises due to different alkyl chains on either side of the functional group in the molecule. For example, C₄H₁₀O represents methoxypropane (CH₃OC₃H₇) and ethoxyethane (C₂H₅OC₂H₅)
Question 7
1 / -0

The order of decreasing priority for some functional groups in the naming of an organic compound is:

A
− CN,− HC = O, > C = O, − OH, − NH₂, − COOR (R = alkyl group), −COCl, −CONH₂

B
− COOR (R = alkyl group), − COCl, −CONH₂, − CN,− HC = O, > C = O, −OH, −NH₂

C
− CONH₂, − CN,− HC = O, > C = O, −OH, −NH₂, − COOR (R = alkyl group), −COCl

D
− COCl, − CONH₂, − CN,− HC = O , > C = O, −OH, −NH₂ , −COOR (R = alkyl group)

Solution

COOR (R=alkyl group) > -COCl,> -CONH₂> -CN > -HC=O> >C=O> -OH, -NH₂ is the decreasing order of priority
ester > acylhalide > acylamide > nitrile > aldehyde > ketones > alcohol > amine
Question 8
1 / -0

Select the nucleophile(s) among the following molecules/ions
HS^-, BF_{3 ,}C₂H₅O^- , (CH₃)₃N: , Cl⁺ ,CH₃C⁺ =O ,H₂N^-: ,NO₂⁺

A
BF₃, Cl⁺

B
CH₃C⁺ =O, NO₂⁺

C
HS^-, H₂N^-: (CH₃)₃N:, C₂H₅O^-

D
Cl⁺, CH₃C⁺ =O

Solution

Nucleophiles are nucleus loving species. These can be negatively charged or netural having lone pair of electrons. So among the given options nucleophiles are HS^-, H₂N^-:, (CH₃)₃N:, C₂H₅O^-

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Organic Chemistry Some Basic Principles and Techniques Test - 5

Result

Organic Chemistry Some Basic Principles and Techniques Test - 5

Score

-

Rank

-

SHARING IS CARING

Question 1

Cyanides

Aldehydes

Alkyl halides

Alcohols

Solution

Question 2

Crystallisation

Distillation under reduced pressure

Steam distillation

Distillation

Solution

Question 3

Column chromatography

Distillation

Thin layer chromatography

Solvent extraction

Solution

Question 4

Volatility

Partition

Adsorption

Solubility

Solution

Question 5

∗CH3− CH2−Br

∗CH3− CH2− CH3

∗CH3−CH2−I

∗ CH3− CH2−Cl

Solution

Question 6

Metamerism

Functional group isomerism

Position isomerism

Stereoisomerism

Solution

Question 7

− CN,− HC = O, > C = O, − OH, − NH2, − COOR (R = alkyl group), −COCl, −CONH2

− COOR (R = alkyl group), − COCl, −CONH2, − CN,− HC = O, > C = O, −OH, −NH2

− CONH2, − CN,− HC = O, > C = O, −OH, −NH2, − COOR (R = alkyl group), −COCl

− COCl, − CONH2, − CN,− HC = O , > C = O, −OH, −NH2 , −COOR (R = alkyl group)

Solution

Question 8

BF​​​​​3​​​​, Cl+

CH3C+ =O, NO​​​​​2​+

HS- , H2N-: (CH3)3N:, C2H5O-

Cl+, CH3C+ =O

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.

∗CH₃− CH₂−Br

∗CH₃− CH₂− CH₃

∗CH₃−CH₂−I

∗ CH₃− CH₂−Cl

− CN,− HC = O, > C = O, − OH, − NH₂, − COOR (R = alkyl group), −COCl, −CONH₂

− COOR (R = alkyl group), − COCl, −CONH₂, − CN,− HC = O, > C = O, −OH, −NH₂

− CONH₂, − CN,− HC = O, > C = O, −OH, −NH₂, − COOR (R = alkyl group), −COCl

− COCl, − CONH₂, − CN,− HC = O , > C = O, −OH, −NH₂ , −COOR (R = alkyl group)

BF₃, Cl⁺

CH₃C⁺ =O, NO₂⁺

HS^-, H₂N^-: (CH₃)₃N:, C₂H₅O^-

Cl⁺, CH₃C⁺ =O