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Organic Chemistry Some Basic Principles and Techniques Test - 52

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Organic Chemistry Some Basic Principles and Techniques Test - 52
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following reagents is used for the separation of acetaldehyde from acetophenone? 
    Solution
    $$Acetaldehyde (CH_{3}CHO)$$

    $$Acetophenone(C_{6}H_{5}C(O)CH_{3})$$
     
    $$A)NH_{2}OH$$ is Hydroxylamine which is a derivative of ammonia which gives nuclear fuse addition reaction with the elimination of water. It reacts with both Acetaldehyde and Acetophenone.

    $$B)NaOHI_{2}$$  is a carbon compound test which gives the carbon compound having $$COCH_{3}$$ group. Both Acetaldehyde and Acetophenone has $$COCH_{3}$$ group
     
    $$C)NaHSO_{3}$$  reacts with acetaldehyde to form an addition compound which is precipitated. Acetaldehyde can be recovered with dilute $$HCl$$. Acetophenone does not react.

    $$D)C_{6}H_{5}NHNH_{2}$$ is an ammonium derivative known as phenylhydrazine
    which gives nuclear fuse addition reaction with the elimination of water. It reacts with both Acetaldehyde and Acetophenone.

    $$\mathbf{Hence\ the\ correct\ answer\  is\ option\ (C).}$$
  • Question 2
    1 / -0
    Prussian blue colour is obtained by mixing together an aqueous solution of $$ Fe^{3+} $$ salt with:
    Solution
    Potassium ferricyanide reacts with ferrous iron in an acidic solution to produce the insoluble blue pigment, commonly referred to as Turnbull's blue or Prussian blue. To detect ferric $$(Fe^{+3})$$ iron, potassium ferrocyanide is used instead in the Perls' Prussian blue staining method.

    $$\mathbf{Hence\ the\ correct\ answer\  is\ option\ (B).}$$
  • Question 3
    1 / -0
    The IUPAC name of tertiary butyl iodide is:
    Solution
    Correct IUPAC name is
    2-iodo-2-methyl propane
  • Question 4
    1 / -0
    Which one is not correct for homologous series?
    Solution
    A series of organic compounds that have similar structural features but differ from adjacent members by $$-CH_2$$ group is referred to as homologous series. They have same general formula and because of the same functional group, they have similar chemical properties but due to varying mass, they have different physical properties.

    Hence the correct option is C. 
  • Question 5
    1 / -0
    The grouping >CO is present in: 
    Solution
    Ketones are having $$>C=O$$ group. Ex- $$CH_3-\overset {\overset {\displaystyle  O }{||}}C-CH_3$$
  • Question 6
    1 / -0
    $$ CH_2 COCI $$ is used to detect the number of amino group in the organic compounds. When a compound of molecular mass 180 is acetylated,gives a compound of molecular mass 390. The number group in the compounds is
    Solution
    $$ NH_2 + CH_3 -\overset { \overset { O }{ parallel }  }{ C } -CI\rightarrow \underset { \underset { H }{ | }  }{ N } -\overset { \overset { O }{ parallel }  }{ C } -CH_ 3+HCl $$
     Let the amino compound has n$$ (-NH_2) $$ group Molecular mass of the product will be.
     $$ 180-n \times 1 + n\times 143 = 390 $$
       42n = 210
      n = 5 ]
  • Question 7
    1 / -0
    The functional groups present in 'salol' are
    Solution
    The functional groups present in 'salol' are "- $$OH$$ and -$$ COOR$$".

  • Question 8
    1 / -0
    Which of the following names are correct for the compound?
    $${ \left( { CH }_{ 3 } \right)  }_{ 2 }CHCN$$
    Solution
    The given compound can be named as 2-Methyl propane nitrile or Isobutyro nitrile or Isopropyl cyanide.
    Therefore, option (D) is correct.
  • Question 9
    1 / -0
    The chemical name of DDT is
    Solution

    $$p,p-dichloro$$ diphenyl trichloroethane

  • Question 10
    1 / -0
    Number of bonds in $$SO_2$$:
    Solution
    Answer is Option C.
    The sulphur dioxide molecule contains $$2σ$$, $$2π$$ bonds and one lone pair of electrons. $$S$$ atom contains $$6$$ valence electrons out of which it shares $$2$$ electrons with $$2$$ $$O$$ atoms to form $$2$$ $$sigma$$ bonds.It also shares $$2$$ electrons with $$2$$ $$O$$ atoms to form $$π$$ bonds. The remaining $$2$$ electrons appear as  $$one$$ lone pair of electrons. $$SO_2$$ molecule has bent geometry. The $$S$$ atom undergoes $$sp^2$$ hybridization.

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