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Organic Chemistry Some Basic Principles and Techniques Test - 56

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Organic Chemistry Some Basic Principles and Techniques Test - 56
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  • Question 1
    1 / -0
    $${N}_{2}$$ is estimated in organic compound by
    Solution
    Duma's method can be used to estimate nitrogen in all type of organic compounds. Detection of nitrogen is done by Lassigne's test. Estimation of phosphorus is done by Carius method.
  • Question 2
    1 / -0
    Which is matched incorrectly?
  • Question 3
    1 / -0
    The number of sigma $$\left( \sigma  \right) $$ and $$\left( \pi  \right) $$ bonds present in $$1, 3, 5, 7$$-octatetraene are __________ respectively.
    Solution

    ($$\because$$ Each single bond is a $$\sigma$$ bond and a double bond contains one $$\sigma$$ and one $$\pi$$ bond).

    $$\therefore$$ The number of $$\sigma$$ and $$\pi$$ bonds are respectively $$17$$ and $$4$$.

  • Question 4
    1 / -0
    Which of the following do not contain carbon - oxygen double bonds?
    Solution
    Ethers do not contain carbon - oxygen double bonds. They contain $$C-O-C$$ linkages.

  • Question 5
    1 / -0
    Which of following can have vacant $$p-$$orbital?
    Solution
    Alkyl free radicals are either planar or pyramidal in structure, they have $$sp^{2}$$ hybridisation with impaired $$e^{-}$$ located primarily in $$p-$$orbital.
    In $$CH_{3}$$, it has $$sp^{2}$$ hybridisation with two $$e^{-}$$ on each and one empty $$p-$$orbital.
    In $$CH_{4}$$, every $$p-$$orbital is involved in hybridisation making it $$sp_{3}$$.
  • Question 6
    1 / -0
    Two compounds X and Y have the same molecular formula $$C_3H_6O$$. Identify the functional groups and structural formula of X and Y. 
  • Question 7
    1 / -0
    Number of $$\pi$$-bods in the following compound  $$\dfrac{CH_3C \equiv CN}{3}$$
    Solution

  • Question 8
    1 / -0
    What is NOT true for aceto-phenone?
    Solution
    1. Acetophenone reacts with 2-4-DiNitroPhenylHydrazine test to form 2-4-DiNitroPhenylHydrazone.
    2. On drastic oxidation with $$KMnO_4$$, $$H^+$$ acetophenone forms benzoic acid.
    3. As acetophenone does not contain any hydrogen atom directly attached to the carbonyl carbon like aldehydes it does not give Tollen's or Fehling test.
    4. Acetophenone reacts with $$NaOH$$, $$Cl_2$$ to form Chloroform which is colourless. 
    5. Therefore, option D is correct.
  • Question 9
    1 / -0
    Consider the following sequence of reactions, the end product B is:

    Solution
    On addition of $$Br_2$$ addition of Bromine at alkene takes place.
    The product A thus formed is reacted with 1,2-dihydroxybenzene in presence of acetone to give product B.

  • Question 10
    1 / -0
    The derived name of the above compound is:

    Solution

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