Organic Chemistry Some Basic Principles and Techniques Test

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Organic Chemistry Some Basic Principles and Techniques Test - 62

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Question 1
1 / -0

Product $$(C)$$ is:

A

B

C

D

Solution

The more hyperconjugate product will be more stable , so the answer is A.
Question 2
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The deamination of $$Ph_2C(OH)CH_2NH_2$$ with $$NaNO_2-HCl$$ gives a product $$(P)$$, which on oxidation gives benzoic acid only. Identify the product $$(P)$$.

A
$$Ph-CH_2-CH_2-Ph$$

B
$$Ph-\overset{O}{\overset{||}{C}}-CH_2-Ph$$

C
$$Ph-\overset{O}{\overset{||}{C}}-\overset{O}{\overset{||}{C}}-Ph$$

D
$$Ph-CH_2-NH-Ph$$

Solution

In this reaction $$NaNO_2 $$ along with $$HCl$$ is used which is mainly used for diazotization reaction. It converts aromatic amine into a diazonium ion. This is followed by its oxidation which leads to the formation of benzoic acid. $$(Ph- COOH)$$
Question 3
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The product (P) will be:

A

B

C

D

Solution

In the reaction of $$-OCR$$ group from $$CH_3OH$$ gets attached to the meta position with respect to the nitro group as $$-OCH_3$$ group is a meta directing group. It leads to the formation of the product as shown above by the substitution $$-OCH_3$$ at meta position from from $$Cl$$.
Question 4
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Given the following thermos chemical reactions:

$$XO_2(s)+CO(g)\rightarrow XO(s)+CO_2(g)$$;$$\Delta H=-20.0$$ kJ

$$X_3O_4(s)+CO(g)\rightarrow 3XO(s)+CO_2(g)$$;$$\Delta H=+6.0$$ kJ

$$3X_2O_3(s)+CO(g)\rightarrow 2X_3O_4(s)+CO_2(g)$$;$$\Delta H=-12.0$$ kJ

Find $$\Delta H$$ in kJ for the reaction.

$$2XO_2(s)+CO(g)\rightarrow X_2O_3(s)+CO_2(g)$$.

A
$$-40.0$$

B
$$-28.0$$

C
$$-26.0$$

D
$$-37.3$$

Solution

$$ \text { i) } XO_{2}(s)+C O(g) \longrightarrow XO(s)+CO_{2} ( g) \quad \Delta H=-20 K J $$

$$ \text { (ii) }-X_{3} 0_{4}(s)+CO (g) \rightarrow 3 XO(g)+C O_{2}(g) \Delta H=+6 K J $$

$$ \text { iii) } 3 X_{2} \mathrm{O}_{3}(s)+\mathrm{CO}(\mathrm{g}) \longrightarrow 2 \mathrm{X}_{3} \mathrm{O}_{4}+\mathrm{CO}_{2}(\mathrm{~g}) \quad \Delta \mathrm{H}=-12 \mathrm{KJ} $$

$$ i v)-2 XO_{2}(s)+{CO}( g) \rightarrow X_{2} O_{3}(s)+CO_{2}(g) \Delta H=? $$
$$ \begin{aligned} \Delta H_{i v} &={2(i)+(2(-i i))+-i i i)}{ } \\ &=2 \times -20+2(-6)+-(-12) \\ &=-40-12+12 \\ &=-40 K J \end{aligned} $$
Question 5
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Curved arrows are used in Organic Chemistry to show the movement of electrons in the mechanism of a reaction. The correct product of the following reaction is:

A

B

C

D

Solution

(Refer to Image 1)
The aliphatic claisen rearrangement is a $$[3,3]$$- sigma tropic rearrangement in which an allyl vinyl ether is converted thermally to an unsaturated carbonyl compound.
Question 6
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The product is:

A

B

C

D

Solution
Question 7
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Products of the following reaction will be:

A

B

C

D

Solution

This reaction is addition of $$HCl$$. The double bond in the alkene first attacks the $$H$$ in the $$HCl$$ bond. The $$H-Cl$$ bond then breaks and moves an electron pair on to chlorine forming $${ Cl }^{ - }$$, a nucleophile. Note that the hydrogen also is attached to the other side of the double bond because the resulting secondary carbocation is equally as stable. The nucleophile attack at the positive charged carbon atom.
Question 8
1 / -0

Phenyl acetate $$\overset{(i) CH_3MgBr(excess)}{\underset{(ii) H^{\ominus}}{\rightarrow}}$$ $$'P'$$.

A

B

C

D

Solution
Question 9
1 / -0

The major product of the following reaction sequence is:

A

B

C

D

Solution
Question 10
1 / -0

The given product can be formed by which set of reaction in the presence of $$AlCl_3$$ catalyst?

A

B

C

D
All of these

Solution

Since electrophilic substitution is favored only when substrate(mestiylene) is electron rich so that it can accept electrophile at no cost(easily).