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Organic Chemistry Some Basic Principles and Techniques Test - 9

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Organic Chemistry Some Basic Principles and Techniques Test - 9
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which of the following is the correct IUPAC name?

    Solution

    In IUPAC naming is different alkyl groups are present, they are written in alphabetical order. Ethyl will be first, followed by methyl. Di, tri, tetra prefixes are not included in alphabetical order.

  • Question 2
    1 / -0

    The IUPAC name for is \(CH_3-\overset{\overset{O}{||}}{C}-CH_2-CH_2-\overset{\overset{O}{||}}{C}-OH\)

    Solution

    If more than one functional groups are present in the chain, one will be the main functional group on priority basis and mentioned as a sec. suffix, while the others are written as prefix mentioned as oxo along with locant.

  • Question 3
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    Electronegativity of carbon atoms depends upon their state of hybridization. In which of the following compounds, the carbon marked with asterisk is most electronegative?

    Solution

    Electronegativity of carbon atom depends on its hybridized state and percentage of ‘s’ character. Electronegativity is directly proportional to percentage of ’s’character, \(sp^3\) (25% ‘s’ character) < \(sp^2\)(33% ‘s’ character) < sp(50% ‘s’ character). Carbon linked through two \(\pi\) bonds is sp hybridized.

  • Question 4
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    Which of the following compounds contain all the carbon atoms in the same hybridization state?

    (i) \(H-C\equiv C-C\equiv C-H\)

    (ii) \(CH_3-C \equiv C-CH_3\)

    (iii) \(CH_2 = C = CH_2\)

    (iv) \(CH_2 = CH-CH = CH_2\)

    Solution

    Only in these two compounds all carbon atoms are in same hybridization state i.e., sp and \(sp ^2\) hybridized, respectively

  • Question 5
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    In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.

    Assertion (A): Simple distillation can help in separating a mixture of propan-1-ol (boiling point 97°C) and propanone (boiling point 56°C).

    Reason (R): Liquids with a difference of more than 20°C in their boiling points can be separated by simple distillation.

    Solution

    The liquids are having sufficient difference in their boiling points. Liquids having different boiling points vaporize at different temperatures. The vapours are cooled and the liquids so formed are collected separately.

  • Question 6
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    Match the type of mixture of compounds in Column I with the technique of separation/purification given in Column II.

    Column I Column II
    (i) Two solids which have different solubility’s in a solvent and which do not undergo reaction when dissolved in it (a) Steam distillation
    (ii) Liquid that decomposes at its boiling point (b) Fractional distillation
    (iii) Steam volatile liquid (c) Simple distillation
    (iv) Two liquids which have boiling points close to each other (d)Distillation under reduced pressure
    (v) Two liquids with large difference in boiling points (e) Crystallization
  • Question 7
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    Match the terms mentioned in Column I with the terms in Column II.

    Column I Column II
    (i) Carbocation (a) Cyclohexane and 1- hexane
    (ii) Nucleophile (b) Conjugation of electrons of C-H bond with empty p-orbital present at adjacent positively charged carbon
    (iii) Hyperconjugation (c) \(sp ^2\) hybridized carbon with empty p-orbital
    (iv) Isomers (d) Ethyne
    (v) sp hybridization (e) Species that can receive a pair of electrons
    (vi) Electrophile (f) Species that can supply a pair of electrons
  • Question 8
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    In which of the following, functional group isomerism is not possible?

    Solution

    Functional isomers have same molecular formula but different functional group. Alcohols are functional isomers of ethers. Aldehydes are functional isomers of ketones. Cyanides are functional isomers of isocyanides. Only alkyl halides do not show functional isomerism.

  • Question 9
    1 / -0

    The fragrance of flowers is due to the presence of some steam volatile organic compounds called essential oils. These are generally insoluble in water at room temperature but are miscible with water vapour in vapour phase. A suitable method for the extraction of these oils from the flowers is:

    Solution

    This technique is applied to separate substances which are steam volatile and are immiscible with water. In steam distillation, steam, from a steam generator is passed through a heated flask containing the liquid to be distilled. The mixture of steam and the volatile organic compound is condensed and collected. The compound is later separated from water using a separating funnel.

  • Question 10
    1 / -0

    During hearing of a court case, the judge suspected that some changes in the documents had been carried out. He asked the forensic department to check the ink used at two different places. According to you which technique can give the best results?

    Solution

    Thin layer chromatography (TLC): It is a method for analyzing mixtures by separating the components of the mixture. TLC can be used to determine the number of components in the mixture, the identity of compounds and the purity of compounds by observing the appearance of a product or the disappearance of a reactant. It can also be used to monitor the progress of a reaction. TLC is a sensitive technique- microgram (0.000001)g quantities can be analyzed by TLC.

  • Question 11
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    The principle involved in paper chromatography is

    Solution

    Partition chromatography is based on continuous differential partitioning of components of a mixture between stationary and mobile phases. Paper hromatography is a type of partition chromatography.

  • Question 12
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    Electrophiles are electron seeking species. Which of the following groups contain only electrophiles?

    (i) \(BF_3 , NH_3 , H_2O\)

    (ii) \(AlCl_3, SO_3 , NO_2^+\)

    (iii) \(NO_2^ + , CH_3^ + , CH_3 -\overset{+}{C} = O\)

    (iv) \(C_2H^-_5,\overset{\bullet}{C}_2H_5,C_2H_5^+\)

    Solution

    Electrophiles are +vely charged or electron deficient species. They are Lewis acids. \(AlCl_3\),\(SO_3\) are Lewis acids, \(NO^+_2\)\(CH^+_3\),\(CH_3\)-\(C^+\) = 0 are +vely charged species

  • Question 13
    1 / -0

    What is the correct order of decreasing stability of the following cations?

    I. \(CH_3-\overset{\oplus}{C}H-CH_3\)

    II. \(CH_3-\overset{\oplus}{C}H-OCH_3\)

    III. \(CH_3-\overset{\oplus}{C}H-CH_2-OCH_3\)

    Solution

    In (I) case, +vely charged C is attached to two alkyl groups and +I effect stabilize carbocation.

    In (II) case, +R effect of \(OCH_3\) group stabilize carbocation.

    In (III) case, -I effect of -\(OCH_3\) gp. destabilizes carbocation.

  • Question 14
    1 / -0

    Correct IUPAC name for \(H_3C-\underset{\underset{C_2H_5}{|}}{CH}-\underset{\underset{C_2H_5}{|}}{CH}-CH_3\) is

    Solution

    In longest continuous chain both ethyl groups are included and \(3 ^{rd}\) and \(4 ^{th}\) carbon have methyl groups present as a substituent.

  • Question 15
    1 / -0

    Consider the following four compounds for answering questions

    I. \(CH_3-CH_2-CH_2-CH_2-\overset{\overset{O}{||}}{C}-H\)

    II. \(CH_3-CH_2-CH_2-\overset{\overset{O}{||}}{C}-CH_3\)

    III. \(CH_3-CH_2-\underset{\underset{O}{||}}{C}-CH_2-CH_3\)

    IV. \(CH_3-\underset{\underset{CH_3}{|}}{CH}-CH_2-\underset{\underset{O}{||}}{C}-H\)

    Which of the following pairs are position isomers?

    Solution

    In position isomerism, two or more compounds differ in the position of substituent, functional group or multiple bonds but molecular formula is same. In pentanone-2 and pentanone-3, position of ketonic group is different.

    \(CH_3-CH_2-CH_2-CO-CH_3\) and \(CH_3-CH_2-CO-CH_2-CH_3\)

  • Question 16
    1 / -0

    In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.

    Assertion (A): Pent- 1- ene and pent- 2- ene are position isomers.

    Reason (R): Position isomers differ in the position of functional group or substituent.

    Solution

    When two or more compounds differ in the position of substituent atom or functional group on the carbon skeleton, they are called position isomers and this phenomenon is termed as position isomerism. Pent-2-ene and pent-l-ene are position isomers because differ in the position of double bond.

  • Question 17
    1 / -0

    Match Column I with Column II.

    Column I Column II
    (i) Dumas method (a) \(AgNO_3\)
    (ii) Kjeldahl’s method (b) Silica gel
    (iii) Carius method (c) Nitrogen gas
    (iv) Chromatography (d) Free radicals
    (v) Hemolysis (e) Ammonium sulphate
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