Hydrocarbons Test

Result

Hydrocarbons Test - 10

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following is highly inflammable ?

A
Alkenes

B
Alkanes

C
Alkynes

D
None of these
Solution
- On comparing Alkanes, Alkenes, Alkynes, saturated hydrocarbons are highly reactive so they catch fire easily.
- Reason:- Reactivity of alkene and alkynes is lower than alkane as there are multiple bonds are present in the unsaturated compounds(alkene and alkynes) that needs to break before the reaction occurs.
- Hydrogen is highly flammable gas.
Question 2
1 / -0

Benzene was discovered by :

A
Cavendish

B
Faraday

C
Berzelius

D
Wohler

Solution

Michael Faraday first isolated and identified benzene from the oily residue derived from the production of illuminating gas.
Question 3
1 / -0

The total no. of $$\pi$$ electrons present in the benzene are :

A
2

B
6

C
4

D
14

Solution

Benzene has three $$\pi$$ bonds so it has 6 $$\pi$$ electrons.
Question 4
1 / -0

The structure of benzene is :

A
tetrahedral

B
planar

C
trigonal

D
square planar

Solution

All aromatic compounds have planar structure so as benzene.
Question 5
1 / -0

Shape of benzene is:

A
tetrahedral

B
trigonal planar

C
hexagonal planar

D
linear

Solution

All aromatic compounds have planar structure so as benzene.
Also, it is hexagonal so its shape is hexagonal planar.
Question 6
1 / -0

Hybridisation of each carbon in benzene is:

A
$$sp^{3}$$

B
$$sp$$

C
$$sp^{2}$$

D
$$sp$$ and $$sp^{2}$$

Solution

In benzene all carbon atom are $$sp^2$$ hybridized.
Question 7
1 / -0

When chloro-benzene reacts with sodium in presence of ether than the major product formed is.

A

B

C

D

Solution
Question 8
1 / -0

Which of the following is the correct IUPAC name?

A
3-Ethyl-4, 4-dimethylheptane

B
4,4-Dimethyl-3-ethylheptane

C
5-Ethyl-4, 4-dimethylheptane

D
4,4-Bis(methyl)-3-ethylheptane

Solution

In IUPAC naming if different alkyl groups are present, they are written in alphabetical order. Ethyl will be first. followed by methyl, Di, tri, tetra prefixes are not included in alphabetical order.
Question 9
1 / -0

Correct naming of the given compound is:

A
ethane

B
ethene

C
ethyne

D
2-ethene

Solution

The given compound is ethene in which parental chain is of two carbons (wordroot : eath) with a double bond (suffix : ene)

Wordroot = cyclohexane
Substituent = methyl and ethyl (ethane comes first according alphabetical order)
Question 10
1 / -0

$$CH_3CH_2CH_2CH_3 \, \xrightarrow {Br_2 \, / \, hv}$$
Major product in the above reaction is:

A
racemic mixture

B
meso

C
diastereomers

D
constitutional isomers

Solution

$$Br$$
$$CH_3CH_2CH_2CH_3 \xrightarrow []{Br_2/h\nu} CH_3CH_2CH_2Br+CH_3\overset {|}{CH}CH_2CH_3$$
Thus, a racemic mixture is obtained. A racemic mixture is one that has equal amount of left and right handed enantiomers of a chiral molecule.