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Hydrocarbons Test - 12

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Hydrocarbons Test - 12
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  • Question 1
    1 / -0
    2-Methyl butane on reacting with bromine in presence of sunlight gives mainly :
    Solution
    $$CH_3CH(CH_3)CH_2CH_3+Br_2 \overset{sunlight} {\longrightarrow}H_3CC(Br)(CH_3)CH_2CH_3$$
                                                   
    The reaction proceeds via the free radical mechanism. 

    Since the radical formed in this case is tertiary, as it is more stable than primary and secondary, 2-Bromo-2-methyl butane is formed.

    Option B is correct.
  • Question 2
    1 / -0
    Difference in the molecular formulae of $$D$$ and $$C$$ is:

    Solution
    $$RMgX \xrightarrow {Methanol} \underset {A } {CH_3CH_3} \xrightarrow [h \nu] {1  \ mole \ of \ chlorine} \underset {B} {CH_3CH_2-Cl} $$

    $$\underset {B} {CH_3CH_2-Cl}\xrightarrow [Ethanol] {Zn-Cu}  \underset {C} {CH_3CH_3} $$

    $$\underset {B} {CH_3CH_2-Cl}\xrightarrow {Na/ dry ether}  \underset {D}{CH_3CH_2CH_2CH_3} $$
    Difference in the molecular formulae of $$D$$ and $$C$$ is $${ C }_{ 2 }{ H }_{ 4 }$$.
  • Question 3
    1 / -0
    $$\left( { CH }_{ 3 } \right) _{ 3 }C-MgCl$$ on reaction with $${ D }_{ 2 }O$$ produces :
    Solution
    $$\left( { CH }_{ 3 } \right) _{ 3 }C-MgCl$$ is a strong base.

    $$\left( { CH }_{ 3 } \right) _{ 3 }C-MgCl$$ + $$D_2O$$ $$\longrightarrow $$ $$\left( { CH }_{ 3 } \right) _{ 3 }C-D$$ + $$MgBrOD$$.
  • Question 4
    1 / -0
     Which of the following type of reaction ethylene undergoes readily?
    Solution
    $$CH_2=CH_2+Cl_2\rightarrow CH_2Cl-CH_2Cl$$
                                                                       (1,2-dichloroethane)

    Ethylene undergoes addition reactions, as they contain double bond..

    Option B is correct.
  • Question 5
    1 / -0
    Statement-1: Alkenes participate in addition reactions
    Statement-2: Alkenes are unsaturated hydrocarbons
    Solution
    As alkenes are unsaturated hydrocarbons so they have atleast one double bond which can participate in addition reaction, so they can perform addition reaction (like with halogens, hydrogen, halogen acids etc.).
  • Question 6
    1 / -0
    Common name of alkenes is :
    Solution
    Olefin also called alkene,  with the general formula $$C_nH_{2n}$$
  • Question 7
    1 / -0
    The reaction $${ C }_{ 12 }{ H }_{ 26 }\rightarrow { C }_{ 6 }{ H }_{ 12 }+{ C }_{ 6 }{ H }_{ 14 }$$ represents :
    Solution
    Hydrocarbon cracking is the process of breaking a long-chain of hydrocarbons into short ones.
  • Question 8
    1 / -0
    Which isomerism relates 2-methyl-1-butene and 2-methyl-2-butene?
    Solution
    2-methyl-1-butene is $$CH_2=C(CH_3)-CH_2-CH_3$$ and 2-methyl-2-butene is $$CH_3-C(CH_3)=CH-CH_3$$. 

    These are position isomers as the functional groups (double bond (alkene) in this case) are in different positions in the same carbon chain.

    Option C is correct.
  • Question 9
    1 / -0
    The IUPAC name of the compound $${ H }_{ 2 }C=CH-CH\left( { CH }_{ 3 } \right) _{ 2 }$$:
    Solution
    IUPAC name of the compound $${ H }_{ 2 }C=CH-CH\left( { CH }_{ 3 } \right) _{ 2 }$$ is 3-Methyl-1-butene as methyl is substituted at carbon no.3 and also double bond is present there at carbon no. 1.
  • Question 10
    1 / -0
    IUPAC name of $$CH_{3}-CH(CH_{3})-C\equiv C-CH(CH_{3})-CH_{3}$$  is:
    Solution
        1          2                      3       4      5                     6
    $$CH_{3}-CH(CH_{3})-C\equiv C-CH(CH_{3})-CH_{3}$$

    The given compound is alkyne as it contains a triple bond. Its parent chain contains 6 carbon atom. 

    As methyl is present as substituent group at carbon no. 2 and 5 and a triple bond is present at carbon number 3.

    So, IUPAC name of the compound is 2,5-dimethyl-3-hexyne.
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