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Hydrocarbons Test - 16

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Hydrocarbons Test - 16
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  • Question 1
    1 / -0
    The ratio of $$\sigma$$ and $$\pi$$ bonds in benzene is:
    Solution
    Benzene has 12 $$\sigma$$ bonds and 3 $$\pi$$ bonds , So their ratio = 4:1

    $$\dfrac{\sigma}{\pi} = \dfrac{12}{3} = 4:1$$
  • Question 2
    1 / -0
    Preceding and succeeding homologues of $$C_{10}H_{22}$$ respectively are:
    Solution

    $$C_{10}H_{12}$$

    $$\downarrow$$

    $$C_nH_{2n + 2}$$

    $$n = 10$$

    $$ n – 1 = 9 \rightarrow C_9H_{20}$$

    $$ n + 1 = 11 \rightarrow C_{11}H_{24}$$

  • Question 3
    1 / -0
    Methanides are:
    Solution
    Ionic carbides have discrete carbon anions of the forms $$C^{4-}$$, called methanides since they can be viewed as being derived from methane ($$CH_4$$). So $$Be_2C$$ and $$Al_4C_3$$ are methanides as they have $$C^{4-}$$ ions.
  • Question 4
    1 / -0
    Metal carbides on reaction with $$H_2O$$ forms $$CH_4$$. 

    Carbide can be:
    Solution
    Different metal carbides react with $$H_2O$$, give the following compounds.

    $$Be_2C(s) + 4 H_2O(l)\rightarrow  2 Be(OH)_2(s) + CH_4(g)$$

    $$CaC_2 + 2H_2O \rightarrow C_2H_2 + Ca(OH)_2$$

    $$Mg_3C_2 + 4H_2O\rightarrow  2Mg (OH)_2+ C_3H_4$$

    Here, beryllium carbide is a metal carbide that forms methane.

    The correct option is ( C )
  • Question 5
    1 / -0
    Which of the following have only 2 types of H-atom?

    Solution
    Only compound (a) naphthalene has two different types of hydrogen atoms. One is alpha hydrogen and the other is beta hydrogen.
    In compound (b) three types of hydrogen atoms are present $$\alpha,  \beta$$ and $$\gamma$$.
    In compound (c) four types of hydrogen atoms are present $$\alpha,  \beta,  \gamma$$ and methyl group.
    In compound (d) four types of hydrogen atoms are present $$\alpha,  \beta,  \gamma$$ and methylene group.

  • Question 6
    1 / -0
    How many different products (excluding stereoisomer) can be obtained by monochlorination of isopentane ?
  • Question 7
    1 / -0

    Name the compound shown in the figure:

    Solution
    The name of the given alkene $$(C_2H_4)$$ is ethene or ethylene which is the first member of the alkene hydrocarbons.

    However, acetylene $$(C_2H_2)$$ is the first member of alkyne hydrocarbons.

    Hence, the correct option is A.
  • Question 8
    1 / -0
    Which of the following carbides produces propyne on reaction with water?
    Solution
    $$CaC_2 + H_2O\rightarrow Ca(OH)_2 +HC \equiv  CH  \uparrow $$
    $$ Be_2C + 2H_2O\rightarrow  2BeO + CH_4 \uparrow$$ 
    $$ Al_4C_3+ 12H_2)\rightarrow  4Al(OH)_3 + 3CH_4\uparrow $$
    $$ Mg_2C_3+ 4H_2O 2+Mg(OH)_2 + H_3C-C \equiv CH \uparrow $$
    Hence option D is correct.
  • Question 9
    1 / -0
    $$CH_3I + xNa + CH_3I \longrightarrow CH_yCH_y + xNaI$$

    Find the value of  x and y :
    Solution

  • Question 10
    1 / -0
    Name the organic compound prepared by the following reaction :

    $$C_2H_5COONa+ NaOH\longrightarrow $$
    Solution

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