Hydrocarbons Test

Result

Hydrocarbons Test - 23

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Weekly Quiz Competition

Question 1
1 / -0

How many isomers are possible in $$C_4H_8$$?

A
$$3$$

B
$$2$$

C
$$4$$

D
$$5$$
Solution
There are five constitutional isomers with the formula $${ C }_{ 4 }{ H }_{ 8 }$$. They are
1. But-1-ene
2. But-2-ene
3. 2-Methylpropane
4. Cyclobutane
5. methylcyclopropane
Hence, this is the answer.
Question 2
1 / -0

The IUPAC name of given compound is:

$$CH_3-C\equiv C-C(CH_3)_2-CH_3$$

A
4,4-dimethyl-2-heptene-5-yne

B
4,4-dimethyl-2-heptene-6-yne

C
4,4-dimethyl-5-heptene-2-yne

D
None of these

Solution

$$ CH_3-C\equiv C-C(CH_3)_2-CH_3$$

IUPAC name: 4,4-dimethyl-pent-2-yne
Question 3
1 / -0

How many isomers are possible for $$C_6H_{12}$$?

A
25

B
24

C
22

D
none of these

Solution

If we limited it to straight-chained alkenes and any conventional cycloalkanes (i.e. the reasonable ones that we would be expected to think of), then there are six. But let's just get as many of the down as we can think of.
Question 4
1 / -0

Give IUPAC name of the following compound :
$$CH\equiv C-C(CH_3)_3$$

A
3,3- dimethylpropyne

B
3,3-dimethylbutyne

C
2,2-dimethylbut-3-yne

D
None of these

Solution

$$\underset {1}{C}H\equiv \underset{2}{C}- \underset{3}{C}(CH_3)_2-\underset{4}{C}H_3$$

The numbering of the compound starts from the triple bond carbon, as alkynes are given higher priority in the order of priority of functional groups when compared to alkanes or single bonds, and methyl substituents.

IUPAC name: 3,3 - dimethylbutyne.

Hence, the correct option is B.
Question 5
1 / -0

The degree of unsaturation of the compound formed by the partial hydrogenation of phenol is:

A
$$3$$

B
$$4$$

C
$$2$$

D
$$1$$

Solution

The degree of unsaturation of the compound formed by the partial hydrogenation of phenol is 2.
Phenol has 3 $$\displaystyle C=C$$ double bonds. During the partial hydrogenation of phenol, one
$$\displaystyle C=C$$ double is hydrogenated and two $$\displaystyle C=C$$ double bonds remain.
Question 6
1 / -0

The IUPAC name of the compound $$CH\equiv C-CH_2-CH_2-CH=CH_2$$ is:

A
Hex-1-en-5-yne

B
Hexyn-5-ene

C
Hex-5-en-2-yne

D
Hex-5-en-1-yne

Solution

$$CH\equiv C-CH_2-CH_2-CH=CH_2$$

IUPAC name: Hex-1-en-5-yne.

Numbering starts from the double bond bearing carbon, as alkenes are higher priority functional groups than alkynes (triple bond).
Question 7
1 / -0

The correct structural formula of benzene is :

A

B

C

D

Solution

The correct structural formula of benzene is represented by the option (B). Here one H atom is attached to each C atom. In the 6 member ring, alternate single and double bonds are present. Each C atom is sp$$\displaystyle _2$$ hybridised as in ethylene molecule. 3 C$$\displaystyle =$$C double bonds are completely delocalised over entire ring.
Question 8
1 / -0

IUPAC name of the first member of alkyne is ___________.

A
ethene

B
ethyne

C
ethane

D
methane

Solution

Alkynes are carbon compounds with general formula $$C_nH_{2n-2}$$
The first member of alkyne series is $$C_2H_2$$ (ethyne)
$$H-C\equiv C-H$$
Alkyne series: $$C_2H_2, C_3H_4, C_4H_6, C_5H_8$$.
Question 9
1 / -0

The compound which is not formed when a mixture of n-butyl bromide and ethyl bromide treated with sodium metal in presence of dry ether is :

A
butane

B
octane

C
hexane

D
ethane

Solution

The compound which is not formed when a mixture of n-butyl bromide and ethyl bromide treated with sodium metal in the presence of dry ether is ethane, $$\displaystyle CH_3-CH_3$$.

The following products are obtained during the reaction.

$$\displaystyle 2\underset {\displaystyle ethyl \: bromide}{ CH_3-CH_2- Br}\xrightarrow [dry \: ether]{Na} \underset {\displaystyle butane}{CH_3-CH_2-CH_2-CH_3}$$

$$\displaystyle 2\underset {\displaystyle n-butyl \: bromide}{ CH_3-CH_2-CH_2-CH_2-Br}\xrightarrow [dry \: ether]{Na} \underset {\displaystyle octane}{CH_3-CH_2-CH_2-CH_2-CH_2-CH_2-CH_2-CH_3}$$

$$\displaystyle \underset {\displaystyle n-butyl \: bromide}{ CH_3-CH_2-CH_2-CH_2-Br}+ \underset {\displaystyle ethyl \: bromide}{ CH_3-CH_2- Br}\xrightarrow [dry \: ether]{Na} \underset {\displaystyle hexane}{CH_3-CH_3}$$

So, the corret option is $$D$$
Question 10
1 / -0

Which of the compound does not dissolve in concentrated $$H_2SO_4$$?

A
Hexane

B
Benzene

C
Ethylene

D
Aniline

Solution

$$\displaystyle Hexane$$ does not dissolve in concentrated $$\displaystyle H_2SO_4$$. $$\displaystyle Hexane$$ is nonpolar hydrocarbon. Polar compound such as $$\displaystyle benzene$$, $$\displaystyle ethylene$$ and $$\displaystyle aniline$$ dissolve in concentrated $$\displaystyle H_2SO_4$$ as they donate their $$\displaystyle \pi$$ electrons to $$\displaystyle H^+$$ ions of concentrated $$\displaystyle H_2SO_4$$.

Option A is correct.