Hydrocarbons Test

Result

Hydrocarbons Test - 25

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Weekly Quiz Competition

Question 1
1 / -0

Write the product of the following reaction, $$ CH_3 - CH = CH_2 \xrightarrow [hv]{Cl_2} (A) \xrightarrow [acetone]{Nal} (B) $$
Compound (B) is :

A
$$ ICH_2 - CH = CH_2 $$

B
$$ CH_3 - \underset { \overset { | }{ I } }{ C } = CH_2 $$

C
Both

D
None

Solution
Question 2
1 / -0

In benzene, each carbon atom undergoes:

A
$$sp$$ hybridization

B
$$sp^2$$ hybridization

C
$$sp^3$$ hybridization

D
$$dsp^2$$ hybridization

Solution

Hydrogen atoms $$(1s^1)$$ and carbon atoms $$(1s^22s^22p_x^12p_y^1)$$ are present in benzene molecule. Each carbon atom uses the sp2 hybrids to form sigma bonds with two other carbons and one hydrogen atom
Question 3
1 / -0

When sodium propionate is heated with soda lime, the product formed is :

A
methane

B
ethane

C
propane

D
butane

Solution

When sodium propionate is heated with soda lime ethane is formed. This reaction is known as Decarboxylation reaction.

$$CH_3COONa + NaOH \xrightarrow {CaO} C_2H_6 + Na_2CO_3$$

Option A is correct.
Question 4
1 / -0

Which is not stable at room temperature?

A

B

C

D

Solution

Device referred to above image is anti-aromatic , so it is highly unstable at room temperature.
Stability$$=$$ Aromatic$$>$$Non-Aromatic$$>$$Anti-aromatic$$.$$
Question 5
1 / -0

The reactivity towards the hydrogenation of the following compounds is :

A
$$I > II > III > IV$$

B
$$II > III > IV > I$$

C
$$III > IV > IV > I$$

D
$$IV > III > II >I$$

Solution

Reactivity toward hydrogenation = $$I>II>III>IV$$
More stable alkenes require less heat of hydrogenation.
Question 6
1 / -0

The bond order of individual carbon-carbon bonds in benzene is:

A
one

B
two

C
between one and two

D
one and two, alternately

Solution

Benzene is a resonance hybrid of two resonating structures. Bon dorder can be calculated as:
$$\text {Bond Order} = \dfrac {\text{Number of Resonating bonds}}{\text {Number of resonating structures}} = \dfrac{3}{2} = 1.5$$
The correct answer is between one and two.
Question 7
1 / -0

The product of the above reaction is

A

B

C

D

Solution
Question 8
1 / -0

Which of the following compounds is insoluble even in hot concentrated $$H_{2}SO_{4}$$?

A
Benzene

B
Hexane

C
Aniline

D
Ethylene

Solution

Hexane is an alkane which is also called as paraffin or less reactive. Thus they are not soluble in concentrated $$H_2SO_4$$.
Also, hexane is non-polar and concentrated $$H_2SO_4$$ is polar, thus hexane is not soluble in $$H_2SO_4$$.
Question 9
1 / -0

Which of the following is least soluble in water?

A
$$C_{2}H_{6}$$

B
$$CH_{3}OH$$

C
$$CH_{3}NH_{2}$$

D
$$C_{6}H_{5}OH$$

Solution

$$C_{2}H_{6}$$ being non-polar is least soluble in water (Given the polar nature of $$H_{2}O$$).
Question 10
1 / -0

Among the following reaction(s) which gives tret - butyl benzene as the major product is/are:

A

B

C

D

Solution

The maximum yield of a reaction between alkyl halide and benzene is obtained when it takes place in the presence of $$AlCl_3$$.

In option $$B$$, there will be a hydride shift in the above image, due to which $$tert-butyl$$ cation will attack the benzene ring to give $$tert-butyl$$ $$benzene$$ as the major product.