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Hydrocarbons Test - 41

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Hydrocarbons Test - 41
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  • Question 1
    1 / -0
    The IUPAC name of 

    Solution
    IUPAC name of this compound is
    5-bromo-6-chloro-1-cyclohexen-3-yne
  • Question 2
    1 / -0
    The IUPAC name of the compound shown is:

    Solution
    The correct IUPAC name is 
    3-bromo-1-chlorocyclohexene
  • Question 3
    1 / -0
    The IUPAC name of the given compound is

    Solution
    The correct IUPAC name is
    bicyclo [2,2,0] hexane
  • Question 4
    1 / -0
    The highest boiling point is expected for:
    Solution
    We know higher branching in a compound results low boiling point.n-octane has highest boiling point as it is a straight chain of eight carbon atoms without branching. 
       
    The other compounds iso-octane and 2,2,3,3-tetramethyloctane have eight carbon atoms  but have branching in the compound. So, they have less boiling point. n-pentane has five carbon atoms, which results lowering of boiling point than all the other compounds.
  • Question 5
    1 / -0
    The IUPAC name of the compound

    Solution

    The IUPAC name of the given compound is 3-bromomethyl-1-chloro-5-methyl hexane. The parent chain has 6 Carbon atoms so it is a hexane and the 3 Carbon has the bromomethyl group.

    Hence, group (A) is the correct option.

  • Question 6
    1 / -0
    The IUPAC name of the given, is

    Solution

  • Question 7
    1 / -0
    Select the correct IUPAC name of the following compound:

    Solution

  • Question 8
    1 / -0
    The relative rates of addition of 

    Solution
    The relative rates of addition of given compounds is the order of stability of carbocation formed in the addition reaction.

    Order of stability of carbocation:
    $$\mathrm{I> II> III > IV > V}$$.

    Hence, Option "A" is the correct answer.
  • Question 9
    1 / -0
    The IUPAC name of the compound is:

    Solution

  • Question 10
    1 / -0
    Among the following the aromtic compounds is:
    Solution
    $$\text{According to Huckel rule for aromaticity, the molecule must be planar, cyclic system having delocalised }$$$$\text{(4nπ+2) electron where n is an integer i. e, 0, 1, 2, 3. Thus, aromatic compounds have 2, 6, 10 or 14π }$$$$\text{electrons. Among yhe following Cyclopropenyl cation (Δ) has 2π electron (n = 0) so, it is aromatic.}$$
    $$\text{ Hence, option B is correct.}$$
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